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Problem 1150

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claims/: The 4 claim pages of Problem 1150, one per claimant's result; the problem's standing derives from them.


Statement. Does there exist a constant c>0c>0 such that, for all large nn and all polynomials PP of degree nn with coefficients ±1\pm 1,

max⁡∣z∣=1∣P(z)∣>(1+c)n?\max_{\lvert z\rvert=1}\lvert P(z)\rvert > (1+c)\sqrt{n}?

Status. OPEN: the site's label (page last edited 23 January 2026; problem page accessed 2026-10-06, its proof-claims tab empty). The derived standing departs from the label, which predates the release: it is solved and disproved, because Theorem 1.1 of the OpenAI release's manuscript of 23 September 2026 gives, for every η>0\eta>0 and every large NN, signs ±1\pm1 whose polynomial of length NN has maximum modulus at most (1+η)N(1+\eta)\sqrt N on the circle, so no c>0c>0 works; this corpus's verification built its Lean declaration OAI.AsymptoticallyMinimalLittlewood.main with only the three standard axioms and audited its statement, and the corpus accepts it on the claim page. No acknowledgment outside this repository is known. The site's commentary, written before the release, restates the question as whether ultraflat polynomials with coefficients ±1\pm1 exist, notes that ultraflat polynomials do exist when the coefficients may be any points of the unit circle (Problem 230), so that the unimodular analogue of the Statement has the answer no, notes that max⁡∣P∣≥n\max\lvert P\rvert\ge\sqrt n is Parseval's identity, and points to the weaker flatness question Problem 228. The problem's discussion thread carries one earlier affirmative claim, el Abdalaoui's preprint of 2025 that ±1\pm1 polynomials are never LαL^\alpha-flat for even α>2\alpha>2, to which the curator and Tao objected and which the accepted theorem contradicts; it has the rejected claim page el Abdalaoui 2025. The same author claimed the affirmative answer earlier, in a 2016 preprint, and again in September 2025; both claims have rejected claim pages (2016, September 2025). Of the two release manuscripts of 5 October 2026, both without Lean, one claims the two-sided ultraflat form (1−ε)N≤∣P(z)∣≤(1+ε)N(1-\varepsilon)\sqrt N\le\lvert P(z)\rvert\le(1+\varepsilon)\sqrt N and the other the lower bound N/16≤∣P(z)∣\sqrt N/16\le\lvert P(z)\rvert with the same upper bound; both are pending on Problem 228's claim page.

Source. erdosproblems.com/1150, accessed 2026-09-04. Cite as: T. F. Bloom, Erdős Problem #1150, https://www.erdosproblems.com/1150.

Formalization. Statement in formal-conjectures; the file states the problem without a proof and proves only the Parseval lower bound max⁡∣P∣≥n+1\max\lvert P\rvert\ge\sqrt{n+1} for degree nn. The release's declaration OAI.AsymptoticallyMinimalLittlewood.main, built and audited by this corpus's verification against the Statement above, is recorded on the claim page; the statement audit recorded there also compared the declaration with the formal-conjectures statement erdos_1150: its eventual range in nn, its coefficient class fixed by the natural degree, and its supremum over the circle against the declaration's pointwise bound.

Current assessment

Disproved by the OpenAI release's construction of 2026-09-23, whose Lean declaration this corpus built and audited (2026-10-07); no acknowledgment outside this repository is known. The question, as the site states it (page last edited 2026-01-23), asks for one c>0c>0 such that every ±1\pm1 polynomial of every large degree nn has maximum modulus above (1+c)n(1+c)\sqrt n on the unit circle; the lower bound n\sqrt n is Parseval's identity, and the complex-coefficient relative, where Kahane's ultraflat polynomials give the answer no, is Problem 230. The release's Theorem 1.1 answers no for real signs: the minimal normalized maximum mNm_N tends to 11 through all lengths. The accepted claim page records the bridge from length NN to degree N−1N-1, the declaration, the build with axioms propext, Classical.choice and Quot.sound only, the comparator pin and the fidelity audit; the evidence is formalized alone, since nobody outside the repository has reviewed or refereed the result and the site lists the problem OPEN with an empty proof-claims tab. What the result trusts is Lean's kernel and the consistency of Mathlib; what it does not give is a lower bound on the circle, as the manuscript's remark after Theorem 1.1 says, nor a convergence rate or a signing algorithm, as the release's family document says.

What remains is quantitative. The release's manuscript notes that Erdélyi's 2026 bound max⁡∣z∣=1∣P(z)∣2≥N+(N−1)1/3/38\max_{\lvert z\rvert=1}\lvert P(z)\rvert^2\ge N+(N-1)^{1/3}/38 for every ±1\pm1 polynomial of length NN (card erdelyi_2026_erdos_problem_about_maximum_modulus_littlewood_polynomials_unit_circl) is compatible with the theorem: the excess max⁡∣P∣2−N\max\lvert P\rvert^2-N is unbounded, but o(N)o(N), and its true order between N1/3N^{1/3} and o(N)o(N) is not determined. The two-sided ultraflat form, (1−ε)N≤∣P(z)∣≤(1+ε)N(1-\varepsilon)\sqrt N\le\lvert P(z)\rvert\le(1+\varepsilon)\sqrt N on the whole circle for every large NN, is claimed by one release manuscript of 2026-10-05, and a second manuscript of the same date claims the lower bound N/16≤∣P(z)∣\sqrt N/16\le\lvert P(z)\rvert with the same upper bound; both are without Lean and are claimed on Problem 228's pending claim page; neither is part of this problem's question.

Three claims of an answer by el Abdalaoui are rejected on their claim pages. A 2016 preprint (its page) asserts that no ±1\pm1 sequence is L4L^4-flat, and a September 2025 preprint (its page) asserts the same for every LαL^\alpha; Appendix A of the release disputes both. His April 2025 preprint, that ±1\pm1 polynomials are never LαL^\alpha-flat for even α>2\alpha>2, which would give a universal gap, is rejected on its claim page: in the site's thread the curator found that the final step of its proof, on p. 9, does not contradict its Lemma 5, which gives only one function with concentration, and Tao asked that its claims be treated as unconfirmed, and the accepted theorem gives LαL^\alpha flatness for every finite α\alpha along its polynomials, contradicting the conclusion.

A separate release manuscript of 2026-09-23, The circulant Hadamard conjecture, claims that real circulant Hadamard matrices exist only in orders 1 and 4, so that Barker sequences would exist only at lengths 2, 3, 4, 5, 7, 11 and 13, which would make vacuous the Borwein–Mossinghoff consequences of arbitrarily long Barker sequences (card borwein_mossinghoff_2008_barker_sequences_flat_polynomials); its Theorem 1.1, the statement on orders, is formally verified here, as its card records, while of the Barker consequence only the even-length direction is, and the manuscript claims nothing about this problem and gets no claim page.

Search scope: the site's problem page and proof-claims tab (accessed 2026-10-06) and its discussion thread (accessed 2026-10-07), the release's manuscripts, family document and lean/ folder at the pinned revision, the acceptance recorded on the claim page, and the retained cards linked below. The proof-claims tab is empty; the thread's one proof posting, el Abdalaoui's preprint, has the rejected claim page above. No wider literature search was made.

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