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Erdős 699: cofactor bounds from quadratic constant-gap identities

P699 research · Erdős problem 699 · Small-index effectivity


Three selected factors whose positions form an arithmetic progression obey an effective cofactor restriction that does not follow from applying the same Padé estimates to pairs of factors separately. The source identity is

(n−r−)(n−r+)=(n−r0)2−h2,r±=r0±h.(1)(n-r_-)(n-r_+)=(n-r_0)^2-h^2, \qquad r_\pm=r_0\pm h. \tag{1}

The two sides have size comparable to n2n^2. Matching powers of a composite base at the endpoints therefore gives a three-way alternative, with a factor of two in the endpoint exponents.

The input is the BFT author preprint, On the factorization of consecutive integers, Theorem 2.4 and especially equation (7.6). Theorem 2.4 permits distinct positive integer bases, including the composite bases used here. The explicit coefficient-gcd estimate is proved in the numerical-threshold note.

1. A three-way cofactor inequality

Fix a position bound RR and distinct primes p−,p0,p+p_-,p_0,p_+. Let 0≤r−<r0<r+≤R0\le r_-<r_0<r_+\le R be in arithmetic progression, and write

n−rt=ptktut(t∈{−,0,+}),(2)n-r_t=p_t^{k_t}u_t\qquad(t\in\{-,0,+\}), \tag{2}

where kt≥0k_t\ge0 and utu_t are positive integers. Maximal prime-power extraction is allowed, but is not needed for this assertion.

Choose positive integers A,B,CA,B,C and set

M=p0B,E=p−Ap+C.M=p_0^B,\qquad E=p_-^A p_+^C.

Choose either (P,Q)=(M,E)(P,Q)=(M,E) or (P,Q)=(E,M)(P,Q)=(E,M) as the oriented seed bases. Suppose a BFT seed aP−bQ=D0>0aP-bQ=D_0>0 and a rational parameter s=c/d>1s=c/d>1 satisfy Theorem 2.4 with Ω3,Ω4>1\Omega_3,\Omega_4>1. Put

K=log⁡max⁡(P,Q)+log⁡Ω4s,α0=1−log⁡MK,α−=1−2Alog⁡p−K,α+=1−2Clog⁡p+K.(3)K=\log\max(P,Q)+\frac{\log\Omega_4}{s}, \quad \alpha_0=1-\frac{\log M}{K}, \quad \alpha_-=1-\frac{2A\log p_-}{K}, \quad \alpha_+=1-\frac{2C\log p_+}{K}. \tag{3}

Proposition. For every choice of γt<αt\gamma_t<\alpha_t, there is an effectively computable NN such that every n≥Nn\ge N satisfying (2) obeys

u−≥nγ−oru0≥nγ0oru+≥nγ+.(4)u_-\ge n^{\gamma_-} \quad\text{or}\quad u_0\ge n^{\gamma_0} \quad\text{or}\quad u_+\ge n^{\gamma_+}. \tag{4}

The threshold can be chosen uniformly for all AP positions in [0,R][0,R].

Proof. Match all three prime-power exponents by taking

m=min⁡{⌊2k0Bc⌋,⌊k−Ac⌋,⌊k+Cc⌋}.(5)m=\min\left\{ \left\lfloor\frac{2k_0}{Bc}\right\rfloor, \left\lfloor\frac{k_-}{Ac}\right\rfloor, \left\lfloor\frac{k_+}{Cc}\right\rfloor \right\}. \tag{5}

Equation (1) becomes

∣PcmU−QcmV∣=h2,|P^{cm}U-Q^{cm}V|=h^2,

with positive integers U,VU,V. The sign is positive when P=MP=M and negative when P=EP=E. BFT's determinant argument leading to (7.6) applies to these integers without any restriction on their size. Once m>m0m>m_0 and κ1<Ω3dm\kappa_1<\Omega_3^{dm}, it gives

V>κ2Ω4dm(Pmin⁡(P,Q))cm.V>\kappa_2\Omega_4^{dm} \left(\frac{P}{\min(P,Q)}\right)^{cm}.

Here κ1,κ2\kappa_1,\kappa_2 are the explicit constants before Theorem 2.4. Use the gap bound D=R2D=R^2 in κ1\kappa_1 to make them uniform in the positions. The determinant inequality uses the absolute gap, so it holds for either orientation. Multiplying by QcmQ^{cm} yields

n2≥QcmV>κ2exp⁡(cmK),cm<2log⁡n−log⁡κ2K.(6)n^2\ge Q^{cm}V>\kappa_2\exp(cmK), \qquad cm<\frac{2\log n-\log\kappa_2}{K}. \tag{6}

If the middle floor attains the minimum in (5), then 2k0<Bc(m+1)2k_0<Bc(m+1), and therefore, for n≥2Rn\ge2R,

u0>12M−c/2κ2log⁡M/(2K)nα0.(7)u_0>\frac12M^{-c/2}\kappa_2^{\log M/(2K)}n^{\alpha_0}. \tag{7}

If an endpoint floor attains the minimum, the corresponding bound is

u−>12p−−Acκ2Alog⁡p−/Knα−,oru+>12p+−Ccκ2Clog⁡p+/Knα+.(8)u_->\frac12p_-^{-Ac}\kappa_2^{A\log p_-/K}n^{\alpha_-}, \quad\text{or}\quad u_+>\frac12p_+^{-Cc}\kappa_2^{C\log p_+/K}n^{\alpha_+}. \tag{8}

This also explains the factor two in (3): (6) bounds the matched block by the logarithm of a product of two row factors, whereas an endpoint cofactor belongs to just one row factor.

Choose an integer

M>max⁡(m0,0,log⁡κ1dlog⁡Ω3).M>\max\left(m_0,0,\frac{\log\kappa_1}{d\log\Omega_3}\right).

For m≥Mm\ge M, equations (7)--(8) apply. If m<Mm<M, a floor attaining the minimum bounds its corresponding prime-power exponent by a fixed constant; that cofactor is at least a computable positive constant times nn. Since every αt<1\alpha_t<1, this also bounds one cofactor below by a computable positive constant times nαtn^{\alpha_t}. Finally, the strict inequalities γt<αt\gamma_t<\alpha_t absorb these fixed constants once nn exceeds an effective threshold. This proves (4). □\square

2. Certified choices for the primes 2, 3 and 5

Set up=(n−rp)/pvp(n−rp)u_p=(n-r_p)/p^{v_p(n-r_p)}. Each row in the table means that, for all sufficiently large nn, at least one of the three inequalities up≥nγpu_p\ge n^{\gamma_p} holds. The stated middle prime must occupy the middle position of the AP; the other two primes occupy its endpoints.

Middle primeSeed aP−bQ=1aP-bQ=1ssγ2\gamma_2γ3\gamma_3γ5\gamma_5
2216−15=116-15=111/811/8.348.348.483.483.243.243
3381−80=181-80=15/45/4.262.262.415.415.571.571
3381−2⋅40=181-2\cdot40=129/2029/20.3299.3299.292.292.4813.4813
5525−24=125-24=14/34/3.194.194.574.574.376.376

For example, 81−80=181-80=1 uses P=M=34P=M=3^4 and Q=E=24⋅5Q=E=2^4\cdot5; thus the factor of two at the 22-endpoint multiplies 4log⁡24\log2.

All four choices use m0=108m_0=10^8 and 40004000 prime intervals in the explicit gcd estimate. The certified lower bounds for log⁡L1\log L_1 are, in table order,

589904174315625000000,3116761442011012,4239541594631012,3764731797291012.\frac{5899041743}{15625000000},\qquad \frac{311676144201}{10^{12}},\qquad \frac{423954159463}{10^{12}},\qquad \frac{376473179729}{10^{12}}.

Directed interval arithmetic verifies Ω3,Ω4>1\Omega_3,\Omega_4>1 and αp−10−4>γp\alpha_p-10^{-4}>\gamma_p in every case. The resulting threshold in nn is effective; it has not been evaluated here.

These are additional arithmetic restrictions. For example, the cofactor exponent vector (e2,e3,e5)=(0,.30,.28)(e_2,e_3,e_5)=(0,.30,.28) satisfies the previously retained pair bounds for these three primes, but violates the 81−8081-80 row when r3r_3 is the middle AP position. This observation concerns the strength of the inequalities, not the existence of row factors with that exponent vector.

Two further choices include the prime 77:

Middle primeEndpoint primesOriented seedssCertified alternative
332,72,728−27=128-27=1, E=22⋅7E=2^2\cdot7, M=33M=3^34/34/3u2≥n.483u_2\ge n^{.483} or u3≥n.385u_3\ge n^{.385} or u7≥n.274u_7\ge n^{.274}
335,75,7245−243=2245-243=2, E=5⋅72E=5\cdot7^2, M=35M=3^55/45/4u3≥n.346u_3\ge n^{.346} or u5≥n.617u_5\ge n^{.617} or u7≥n.074u_7\ge n^{.074}

Both use the composite as PP and the middle prime power as QQ. The gcd inputs are those above for s=4/3s=4/3 and s=5/4s=5/4, respectively. The checker verifies a margin of 10−410^{-4} in each exponent. For the second choice, K>8.40729345K>8.40729345 and the three unrounded exponents exceed .3466314,.6171329,.0741799.3466314,.6171329,.0741799.

For an AP with middle prime 22 and endpoint primes 3,73,7, the additional seed 64−63=164-63=1, with s=4/3s=4/3, gives the certified alternative

u2≥n.390oru3≥n.356oru7≥n.429.u_2\ge n^{.390}\quad\text{or}\quad u_3\ge n^{.356}\quad\text{or}\quad u_7\ge n^{.429}.

Its exact coefficient-gcd input and exponent intervals are included in the same checker and output. The numerical-threshold note also supplies this alternative using the published Proposition 5.1 entry at s=9/7s=9/7.

For an AP with middle prime 77 and endpoint primes 2,32,3, the seed 7−6=17-6=1 gives the additional alternative

u2≥n.428oru3≥n.13oru7≥n.198.u_2\ge n^{.428}\quad\text{or}\quad u_3\ge n^{.13}\quad\text{or}\quad u_7\ge n^{.198}.

It is included in the same certificate. The numerical product-threshold calculation uses s=3/2s=3/2 and the Dusart coefficient-gcd bound at m0=200000m_0=200000, giving a numerical height threshold 1032905110^{329051} for positions in [0,9][0,9].

3. Four factors with equal position sums

Suppose four selected positions satisfy

r1+r2=r3+r4,r1r2≠r3r4,0≤rt≤R.r_1+r_2=r_3+r_4,\qquad r_1r_2\ne r_3r_4, \qquad 0\le r_t\le R.

Equivalently, the two unordered position pairs are different. In the applications here all four positions are distinct.

Then

(n−r1)(n−r2)−(n−r3)(n−r4)=r1r2−r3r4,(9)(n-r_1)(n-r_2)-(n-r_3)(n-r_4)=r_1r_2-r_3r_4, \tag{9}

and the absolute gap is nonzero and at most R2R^2. Write n−rt=ptktutn-r_t=p_t^{k_t}u_t for four distinct primes. Given positive integers a1,a2,a3,a4a_1,a_2,a_3,a_4, choose the oriented BFT bases from

P=p1a1p2a2,Q=p3a3p4a4,P=p_1^{a_1}p_2^{a_2},\qquad Q=p_3^{a_3}p_4^{a_4},

interchanging the two bases if needed. With KK defined as in (3), matching

m=min⁡1≤t≤4⌊ktatc⌋m=\min_{1\le t\le4}\left\lfloor\frac{k_t}{a_tc}\right\rfloor

gives the same bound (6). Consequently, for every

γt<1−2atlog⁡ptK,\gamma_t<1-\frac{2a_t\log p_t}{K},

at least one of ut≥nγtu_t\ge n^{\gamma_t} holds for all sufficiently large nn, with an effective threshold uniform in the positions. The proof of (7)--(8), including the treatment of small mm, applies to the four possible minimum floors. No primeness of the BFT bases themselves is used.

For the partition r2+r3=r5+r7r_2+r_3=r_5+r_7, take

P=36=22⋅32,Q=35=5⋅7,a=b=1,s=13/10.P=36=2^2\cdot3^2,\qquad Q=35=5\cdot7,\qquad a=b=1,\quad s=13/10.

The exact gcd lower bound is

log⁡L1=3341199341591012,m0=108.\log L_1=\frac{334119934159}{10^{12}},\qquad m_0=10^8.

The checker verifies log⁡Ω3>.01868984524\log\Omega_3>.01868984524, K>5.88707253765K>5.88707253765, and the four unrounded exponents exceed

.5290377,.2535425,.4532298,.3389209..5290377,\quad .2535425,\quad .4532298,\quad .3389209.

Thus the effective alternative

u2≥n.528oru3≥n.253oru5≥n.453oru7≥n.338(10)u_2\ge n^{.528}\quad\text{or}\quad u_3\ge n^{.253}\quad\text{or}\quad u_5\ge n^{.453}\quad\text{or}\quad u_7\ge n^{.338} \tag{10}

holds whenever r2+r3=r5+r7r_2+r_3=r_5+r_7. The retained certificate again includes a margin of 10−410^{-4}.

These restrictions apply to the indicated position patterns. They require a separate argument covering all other patterns before yielding an effective bound for a whole index ii.

The checker and retained certificate evaluate these seven analytic parameter choices. They enumerate no binomial rows.