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Reductions


All claims below are necessary conditions on a hypothetical counterexample; they do not prove that one exists. Put N=r2+1N=r^2+1, and let GiG_i be the graph of color ii. The exact counterexample condition is

α(Gi)≤r(i=1,…,r),\alpha(G_i)\le r\qquad(i=1,\ldots,r),

and the graphs GiG_i partition E(KN)E(K_N).

Inherited density

For n=rq+bn=rq+b, 0≤b<r0\le b<r, define

pr(n)=r(q2)+qb,Dr(n)=(n2)−(r−1)pr(n).p_r(n)=r\binom q2+qb, \qquad D_r(n)=\binom n2-(r-1)p_r(n).

Complementary Turán gives, for every vertex set WW and every color ii,

pr(∣W∣)≤e(Gi[W])≤Dr(∣W∣).p_r(|W|)\le e(G_i[W])\le D_r(|W|).

The upper bound follows by applying the lower bound to the other r−1r-1 colors and summing their disjoint edge sets. In particular,

e(Gi[S])≤(r2)+1(∣S∣=r+1).e(G_i[S])\le\binom r2+1\quad(|S|=r+1).

The general inequality is strictly stronger than this last cap. Its use in the supplied nine-color proof was checked in source, Lemma 2.

Least color and neighborhood accounting

A least color GG satisfies

e(G)≤r(r2+1)2.e(G)\le \frac{r(r^2+1)}2.

It has a vertex of degree at most r−1r-1. Otherwise it is rr-regular. Brooks's theorem then makes it rr-colorable, because a component Kr+1K_{r+1} is forbidden and the odd-cycle exception has degree two, whereas r≥3r\ge3. An rr-coloring of N>r2N>r^2 vertices gives an independent r+1r+1-set, a contradiction.

For a minimum-degree vertex vv, put d=dG(v)d=d_G(v), A=NG(v)A=N_G(v), U=V(G)∖(A∪{v})U=V(G)\setminus(A\cup\{v\}), X=eG(A,U)X=e_G(A,U), and Y=e(G[A])Y=e(G[A]). Summing the degree lower bound over AA gives

X+2Y≥d(d−1).X+2Y\ge d(d-1).

Since Y≤(d2)Y\le\binom d2,

e(G[U])≤e(G)−d−(d2),∣U∣=r2−d,α(G[U])≤r−1.e(G[U])\le e(G)-d-\binom d2, \qquad |U|=r^2-d, \qquad\alpha(G[U])\le r-1.

Monochromatic KrK_r's

If QQ is a color-ii KrK_r and x∉Qx\notin Q, at most one of the rr edges from xx to QQ has color ii. Indeed, all the other r−1r-1 colors must occur on those edges. In particular, distinct such cliques intersect in at most one vertex.

Given disjoint color-ii KrK_r's Q1,…,QkQ_1,\ldots,Q_k and a disjoint color-ii independent set II, one can extend II by one representative from each QjQ_j, while preserving independence, provided ∣I∣+k≤r|I|+k\le r. At each step fewer than rr previously selected vertices exclude at most one vertex each from the next block.

Consequently, after removing jj disjoint target KrK_r's from the nonneighborhood UU above, the residual RjR_j has

∣Rj∣=r2−d−jr,α(G[Rj])≤r−1−j,|R_j|=r^2-d-jr,\qquad \alpha(G[R_j])\le r-1-j,

and

e(G[Rj])≤r(r2+1)2−(d+12)−j(r2).e(G[R_j])\le \frac{r(r^2+1)}2-\binom{d+1}{2}-j\binom r2.

To check the independence bound, an independent set of size r−jr-j in RjR_j could be extended to size rr within UU, and then by vv. The edge estimate discards the internal edges of the removed cliques, and does not count any cross edges twice.

This is the uniform content of the nine-color proof, Lemmas 6--7 and Section 3. What is missing is a uniform theorem forcing another KrK_r in the residual, or otherwise excluding it. Parameter-specific tables and finite Ramsey catalogs cannot be substituted for such a theorem.