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Problem 595

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claims/: The 1 claim page of Problem 595, one per claimant's result; the problem's standing derives from them.


Statement. Is there an infinite graph GG which contains no K4K_4 and is not the union of countably many triangle-free graphs?

Status. Open. The site labels Problem 595 OPEN. The one claim recorded here is imported from the site's ruling on the identical first question of Problem 1174, which it labels NOT DISPROVABLE, crediting Shelah; the claim page Shelah 1989 records that result, which is one side of an independence result, so the problem is open on it.

Source. erdosproblems.com/595, accessed 2026-09-04. Cite as: T. F. Bloom, Erdős Problem #595, https://www.erdosproblems.com/595.

References.

  • [Fo70] Folkman, Jon, Graphs with monochromatic complete subgraphs in every edge coloring. SIAM J. Appl. Math. (1970), 19-24.
  • [NeRo75] Nešetřil, Jaroslav and Rödl, Vojtěch, Type theory of partition properties of graphs. (1975), 405-412.

Formalization. Statement in formal-conjectures.

Current assessment

The site labels the problem OPEN and its remarks record only the finite analog: Folkman [Fo70] for two colors and Nešetřil and Rödl [NeRo75] for every nn proved that there is a K4K_4-free graph that is not the union of nn triangle-free graphs, which is Folkman's Theorem 1 with k1=k2=3k_1=k_2=3 (result page theorem_1) and its extension to every number of colors. The question itself, whether one K4K_4-free graph defeats countably many colors, has a consistent positive answer: Shelah (Lecture Notes in Math. 1401, 1989, Lemma 5.1 with k(∗)=3k(*)=3 and μ=ℵ0\mu=\aleph_0) proved by forcing, from a measurable cardinal or one of the lemma's weaker hypotheses, that such a graph can exist, so relative to that hypothesis ZFC cannot refute a positive answer; this is the accepted partial claim on Shelah 1989, with the value not_disprovable that the site gives the identical first question of Problem 1174. It is one side of an independence result, so the problem stays open. Komjáth's survey (Bull. Symbolic Logic 31 (2025), Problem 53) records Shelah's consistency proof and records that existence in ZFC is open, which is the open part of the problem: a ZFC construction would answer the question outright, and a proof that no such graph exists would contradict Shelah's result and so would need the lemma's hypothesis to be inconsistent. Any such graph has more than 2ℵ02^{\aleph_0} vertices, as the Known Results explain. No formal proof is recorded: the formal-conjectures statement file, as of 2026-10-07, marks only the finite analog research solved, and the community database lists the problem as open.

Known Results

The question is the first question of Problem 1174 in other words, and Komjáth's survey notes the same cardinality obstruction: the required graph has more than 2ℵ02^{\aleph_0} vertices, since the complete graph on 2ℵ02^{\aleph_0} vertices is a countable union of bipartite graphs.

Linked library material

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