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Problem 1015

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claims/: The 2 claim pages of Problem 1015, one per claimant's result; the problem's standing derives from them.


Statement. Let f(t)f(t) be minimal such that, in any two-colouring of the edges of KnK_n, the edges can be partitioned into vertex disjoint monochromatic copies of KtK_t (not necessarily the same colour) with at most f(t)f(t) vertices remaining.

Estimate f(t)f(t). In particular, is it true that f(t)1/t→1f(t)^{1/t}\to 1? Is it true that f(t)≪tf(t)\ll t?

Formulation. The site's wording as accessed (the page shows no last-edited date). The quantity depends on nn as well as tt: the source, Burr, Erdős and Spencer (1975), writes f(n,k)f(n,k) for the least number such that in any two-coloring of KnK_n one can find vertex-disjoint monochromatic KkK_k, of either color, "with ≤f(n,k)\le f(n,k) points left over", and studies kk fixed and nn large; the site's commentary supposes that Erdős meant the question for nn large in terms of tt, and its f(t)f(t) is read here as the eventual value of f(n,t)f(n,t), which for fixed tt is periodic in nn once nn is large, with maximum R(t,t−1)+t−2R(t,t-1)+t-2. The site's "the edges can be partitioned into" is loose: the copies of KtK_t cover vertices, not edges, and the source's phrase is that vertex-disjoint monochromatic KkK_k are deleted until at most f(n,k)f(n,k) vertices remain. Erdős's own 1971 wording (item 9 of [Er71], printed p. 100) counts cliques rather than leftover vertices: "Let f(l)f(l) be the smallest integer with the property that, if we colour the edges of a KnK_n with two colours, then there are always [n/l]−f(l)[n/l]-f(l) vertex disjoint KlK_l's all of whose edges have the same colour." He adds that Ramsey's theorem implies f(l)<4lf(l)<4^l (printed 4b4^b, a misprint for 4l4^l) and that "it seems certain that f(l)1/l→1f(l)^{1/l}\to1 and perhaps f(l)<clf(l)<cl, or f(l)f(l) is bounded." A shortfall of ff cliques leaves lf+(n mod l)lf+(n\bmod l) vertices, so the site's vertex count and Erdős's clique count differ by a factor of about ll, which changes neither closing question (an observation made here). The site's remark that Erdős derived f(t)≪4tf(t)\ll4^t from the Ramsey number is his remark that Ramsey's theorem implies f(l)<4lf(l)<4^l.

Status. Solved, in the site's label (SOLVED, the site's label for a resolution that is neither a proof nor a disproof), which attaches to the estimate: for fixed kk and all sufficiently large nn, Theorem 6 of Burr, Erdős and Spencer (Trans. Amer. Math. Soc. 209 (1975), refereed) gives the exact value

f(n,k)=r(k,k−1)−1+rem(n−r(k,k−1)+1, k),f(n,k)=r(k,k-1)-1+\mathrm{rem}(n-r(k,k-1)+1,\,k),

where r(k,k−1)r(k,k-1) is the off-diagonal Ramsey number and rem(a,b)\mathrm{rem}(a,b) the remainder of aa on division by bb; so the eventual maximum over nn is r(k,k−1)+k−2r(k,k-1)+k-2 and the eventual minimum r(k,k−1)−1r(k,k-1)-1. The claim page Burr, Erdős and Spencer 1975 records Theorem 6 as the accepted resolution, on the curator's credit and the refereed publication, and the frontmatter standing derives from it. Moon's theorem, the case t=3t=3 with the site's value f(3)=4f(3)=4, is an accepted partial claim, Moon 1966. The two closing questions are not stated in [BES75]; an elementary deduction from Theorem 6 and Erdős's 1947 bound, written out under Current assessment and named as this page's own, is not acceptance evidence and does not enter the standing. The site's formula differs from the paper's by the term −1-1 (recorded below, not repaired).

Source. erdosproblems.com/1015, accessed 2026-09-18: the problem page (SOLVED; no last-edited date shown; source key [Er71]; commentary citing [Mo66b] and [BES75]; OEIS "Possible"), its empty discussion thread and its empty proof-claim tab. Cite as: T. F. Bloom, Erdős Problem #1015, https://www.erdosproblems.com/1015, accessed 2026-09-18.

References.

  • [BES75] Burr, S. A., Erdős, P. and Spencer, J. H., Ramsey theorems for multiple copies of graphs. Trans. Amer. Math. Soc. 209 (1975), 87--99, doi:10.1090/S0002-9947-1975-0409255-0 (received 14 January 1974). Section 5 and Theorem 6, printed pp. 94--95. Library home: burr_1975_ramsey_theorems_multiple_copies_graphs.
  • [Er71] Erdős, P., Some unsolved problems in graph theory and combinatorial analysis. Combinatorial Mathematics and its Applications (Oxford, 1969), Academic Press (1971), 97--109; item 9, printed p. 100. Library home: erdos_1971_unsolved_problems_graph_theory_combinatorial_analysis.
  • [Mo66b] Moon, J. W., Disjoint triangles in chromatic graphs. Math. Mag. 39 (1966), no. 5, 259--261, doi:10.1080/0025570X.1966.11975734; the Theorem with its facts A and B, printed p. 259, its proof, pp. 259--261, and the remark on sharpness, p. 261. Library home: moon_1966_disjoint_triangles_chromatic_graphs, result page Theorem.
  • [Sp75] Spencer, J., Ramsey's theorem---a new lower bound. J. Combinatorial Theory Ser. A 18 (1975), 108--115; Corollary 1, printed p. 109, Erdős's 1947 bound R(k)≥k2k/2[1/(e2)+o(1)]R(k)\ge k2^{k/2}[1/(e\sqrt2)+o(1)] as restated there. Library home: spencer_1975_ramsey_theorem_new_lower_bound / corollary_1.

Formalization. None. No file for this problem exists in google-deepmind/formal-conjectures at the main revision of 2026-09-18 (the directory FormalConjectures/ErdosProblems/ listed in full, 673 entries), the site's indicator records no formalized statement, and the community database lists the problem as solved as of its last update, 10 September 2025, and not formalized, with no formal proof.

Current assessment

The question (site formulation). The statement above; SOLVED; no last-edited date shown. The commentary attributes the question to Moon [Mo66b], crediting him with f(3)=4f(3)=4 for n≥8n\ge8; supposes that Erdős meant to ask only for nn large in terms of tt; records Erdős's bound f(t)≪4tf(t)\ll4^t from the Ramsey number R(t)R(t); and credits Burr, Erdős and Spencer [BES75] with the value, for nn large in terms of tt, f(t)=R(t,t−1)+x(t,n)f(t)=R(t,t-1)+x(t,n) with 0≤x(t,n)<t0\le x(t,n)<t and n+1≡R(t,t−1)+x(modt)n+1\equiv R(t,t-1)+x\pmod t (the site's display, one more than the paper's formula; see below). The discussion thread and the proof-claim tab are empty.

Origin. [Er71], item 9, printed p. 100: "Moon [32] proved that if n=3k+2≥8n=3k+2\ge8 and we colour the edges of a KnK_n with two colours, then there are always kk vertex disjoint triangles whose edges have the same colour (different triangles can have different colours)", followed by the definition of f(l)f(l) quoted under Formulation, the remark that Ramsey's theorem implies f(l)<4lf(l)<4^l, the expectation that "it seems certain that f(l)1/l→1f(l)^{1/l}\to1 and perhaps f(l)<clf(l)<cl, or f(l)f(l) is bounded", and the same-color variant: "How many vertex disjoint KlK_l's are there, all edges of which have the same colour? (Here different KlK_l's must have the same colour.) It is easy to see that for l=2l=2 the answers [sic] is 13n+O(1)\frac13n+O(1) [31]." Moon's paper is the paper's [32], [Mo66b], recorded next.

Moon's theorem. The Theorem of [Mo66b] (printed p. 259) writes μ(Gn)\mu(G_n) for the largest number of vertex-disjoint monochromatic triangles in a two-coloring GnG_n of the edges of KnK_n and states two things: for every nn, [13n]−1≤μ(Gn)≤[13n][\tfrac13n]-1\le\mu(G_n)\le[\tfrac13n], and for n≡2(mod3)n\equiv2\pmod3 with n≥8n\ge8, μ(Gn)=[13n]\mu(G_n)=[\tfrac13n]. The second part is Erdős's sentence above. The proof (pp. 259--261) shows that every two-coloring of K8K_8 has two disjoint monochromatic triangles, by a case analysis on the pentagon coloring of the five vertices outside one such triangle (Figures 1--4), and reduces n=3h+2n=3h+2 to n=8n=8 by exchanging one triangle of a maximal family for two; the first part is a count of uncovered vertices with the fact that every two-coloring of K6K_6 has a monochromatic triangle. The paper does not define ff, does not count uncovered vertices and poses no question for KkK_k; the site's value f(3)=4f(3)=4 for n≥8n\ge8 is the translation f(n,3)=max⁡(n−3μ(Gn))f(n,3)=\max(n-3\mu(G_n)), which the theorem bounds by n−3[13n]+3n-3[\tfrac13n]+3 for every nn, at most 44 unless n≡2(mod3)n\equiv2\pmod3, and pins to 22 for n≡2(mod3)n\equiv2\pmod3, n≥8n\ge8; the one value left above 44 is f(5,3)=5f(5,3)=5, from the pentagon coloring of K5K_5 (Figure 1), which has no monochromatic triangle. The value 44 (for n≡1(mod3)n\equiv1\pmod3) needs a coloring with μ(Gn)=[13n]−1\mu(G_n)=[\tfrac13n]-1; the paper says such examples are easy to construct for every n≥3n\ge3 where the second part does not apply and prints none (p. 261), and the k=3k=3 case of the Figure 6 coloring of [BES75] below supplies them. The attribution of the general problem to Moon is that of [BES75]'s Section 5 and of [Er71]'s item 9. Read depth: the statement and the closing remark are checked clause by clause; the proof is followed in full, with the claims about Figures 2--4 taken as printed and not re-derived. The theorem is an accepted partial claim, 1966_11_01_moon.

Status-defining source. Theorem 6 of [BES75], Section 5 ("Decomposition of KnK_n into monochromatic KkK_k"), printed pp. 94--95. The section opens by attributing the case k=3k=3 to Moon [5] and defines f(n,k)f(n,k), for k<nk<n, as the least integer such that in any two-coloring of KnK_n "it is possible to find vertex-disjoint monochromatic KkK_k with ≤f(n,k)\le f(n,k) points left over", the copies allowed to differ in color; the authors fix kk and let nn grow, and note the trivial bound f(n,k)≤r(k,k)−1f(n,k)\le r(k,k)-1, since monochromatic KkK_k can be deleted until fewer than r(k,k)r(k,k) vertices remain. Theorem 6: "If kk is given, then for sufficiently large nn, f(n,k)=r(k,k−1)−1+rem(n−r(k,k−1)+1,k)f(n,k)=r(k,k-1)-1+\mathrm{rem}(n-r(k,k-1)+1,k)" (p. 94). The lower bound is the coloring of Figure 6: a set BB of r(k,k−1)−1r(k,k-1)-1 vertices colored with no red KkK_k and no blue Kk−1K_{k-1}, all edges between BB and the rest blue, and all pairs inside the rest red (the paper prints "[B]2[B]^2" for this last set where the argument needs [A]2[A]^2), so no vertex of BB lies in a monochromatic KkK_k and ∣B∣+rem(n−∣B∣,k)|B|+\mathrm{rem}(n-|B|,k) vertices are left. The upper bound (pp. 94--95) finds a large monochromatic clique by Ramsey's theorem for n≥r(u,u)n\ge r(u,u), u=(k−1)(r(k,k)−r(k,k−1))+(k−1)(k−2)+1u=(k-1)(r(k,k)-r(k,k-1))+(k-1)(k-2)+1, and uses it to absorb leftover blue Kk−1K_{k-1}'s until fewer than r(k,k−1)r(k,k-1) vertices resist; the threshold on nn is explicit but enormous. Acceptance evidence: the site's curator, T. F. Bloom, credits Burr, Erdős and Spencer with the determination, and the paper is a refereed publication in the Transactions (the Crossref record). Read depth: claims checked for the section's opening, the trivial bound, Theorem 6 and the construction; the upper-bound argument is followed for structure and not checked.

The site's formula against the paper's (recorded, not repaired). The site prints f(t)=R(t,t−1)+x(t,n)f(t)=R(t,t-1)+x(t,n) with 0≤x<t0\le x<t and $n+1\equiv R(t,t-1)+x\pmod t$. The paper's remainder is the same xx ($x\equiv n+1-r(k,k-1)\pmod k$), but the paper's value is r(k,k−1)−1+xr(k,k-1)-1+x, one less than the site's. A check made here against the case the site itself quotes: for k=3k=3, r(3,2)=3r(3,2)=3 and the paper's formula gives f(n,3)=2+rem(n−2,3)∈{2,3,4}f(n,3)=2+\mathrm{rem}(n-2,3)\in\{2,3,4\}, which is 22 when n≡2(mod3)n\equiv2\pmod3, as in the second part of Moon's theorem ([Mo66b], p. 259: for n≡2(mod3)n\equiv2\pmod3 and n≥8n\ge8 there are [13n][\tfrac13n] disjoint monochromatic triangles, leaving two vertices), and has maximum 44, the site's value and the bound Moon's theorem gives for every n≠5n\ne5 (its first part gives 33 for n≡0n\equiv0 and 44 for n≡1(mod3)n\equiv1\pmod3, its second part 22 for n≡2(mod3)n\equiv2\pmod3, n≥8n\ge8); the site's formula would give 33, 44 and 55 instead.

The two closing questions (an authored deduction, named as such). For k≥3k\ge3, a two-coloring of KNK_N with no red Kk−1K_{k-1} and no blue Kk−1K_{k-1} has no red KkK_k either, so r(k,k−1)≥r(k−1,k−1)=R(k−1)r(k,k-1)\ge r(k-1,k-1)=R(k-1), and Erdős's 1947 bound in the form of Spencer's Corollary 1 gives R(k−1)≥(k−1)2(k−1)/2[1/(e2)+o(1)]>2(k−1)/2R(k-1)\ge(k-1)2^{(k-1)/2}[1/(e\sqrt2)+o(1)]>2^{(k-1)/2} for all large kk. Hence, by Theorem 6, for all large kk and all nn large in terms of kk,

f(n,k) ≥ r(k,k−1)−1 ≥ R(k−1)−1 > 2(k−1)/2−1,f(n,k)\ \ge\ r(k,k-1)-1\ \ge\ R(k-1)-1\ >\ 2^{(k-1)/2}-1,

so lim inf⁡k→∞f(n,k)1/k≥2\liminf_{k\to\infty}f(n,k)^{1/k}\ge\sqrt2 and f(n,k)1/k↛1f(n,k)^{1/k}\not\to1, and f(n,k)≪kf(n,k)\ll k fails. In Erdős's clique count the same holds up to the factor kk noted under Formulation. The upper direction is the trivial f(n,k)≤r(k,k)−1≤(2k−2k−1)<4kf(n,k)\le r(k,k)-1\le\binom{2k-2}{k-1}<4^k, the site's bound f(t)≪4tf(t)\ll4^t. Both answers are elementary consequences of the cited statements; the Ramsey bounds themselves rest on the cited papers, and the exact growth of f(n,k)f(n,k) is exactly that of r(k,k−1)r(k,k-1), unknown to within exponential factors.

Search scope. None of the routes below found a sharper determination of f(n,k)f(n,k), a source for the same-color variant of [Er71], or a dispute of Theorem 6.

  • The site: problem page, discussion thread and proof-claim tab; the formal-conjectures directory listing at the revision of 2026-09-18 (no file); the community database (read 2026-09-18).
  • Crossref: bibliographic queries for [BES75] (the AMS record and a JSTOR record) and for [Mo66b] (the Taylor & Francis record).
  • OpenAlex: the 88 works citing [BES75], titles read (multiple-copies Ramsey numbers, star-critical and size Ramsey numbers, tilings in dense graphs, monochromatic coverings); none on Moon's decomposition problem.
  • arXiv: the API query abs:"vertex-disjoint monochromatic" AND abs:complete AND (abs:"K_t" OR abs:cliques OR abs:"complete subgraphs") (no records).
  • The primary sources: [BES75] printed pp. 87, 94--96, 98 and 99; [Er71] printed p. 100; [Sp75] through its result page; [Mo66b] printed pp. 259--261 (its card records the provenance).

Not searched: MathSciNet, zbMATH, Google Scholar, X.

Remaining gaps. (1) Moon's printed equality is the case n≡2(mod3)n\equiv2\pmod3, n≥8n\ge8; the value f(n,3)=4f(n,3)=4 for n≡1(mod3)n\equiv1\pmod3, the site's value, rests on the first part of his theorem for the upper bound and, for the matching coloring, on examples [Mo66b] leaves to the reader (p. 261) and on the k=3k=3 case of [BES75]'s Figure 6 coloring. (2) Proof coverage is statements only: Theorem 6's upper-bound argument is followed for structure and not checked, and the "sufficiently large nn" threshold r(u,u)r(u,u) is explicit but not tightened. (3) The value of f(n,k)f(n,k) is determined only in terms of r(k,k−1)r(k,k-1), which is unknown to within exponential factors; the site's label SOLVED covers this determination, not a formula in closed form, and the two negative answers are this page's own deduction. (4) The site's formula is off by one from the paper's; recorded above, not resolved with the site. The list of linked library material below is derived from the library links and records no progress.

Linked library material

These entries are derived from explicit links on library pages. They are navigation only and do not by themselves record mathematical progress.