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Problem 609

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claims/: The 4 claim pages of Problem 609, one per claimant's result; the problem's standing derives from them.


Statement. Let f(n)f(n) be the minimal mm such that if the edges of K2n+1K_{2^n+1} are coloured with nn colours then there must be a monochromatic odd cycle of length at most mm. Estimate f(n)f(n).

Status. Open (the site's label, which adds that the problem cannot be resolved by a finite computation). The sources below give separated lower and upper bounds at the exact host threshold K2n+1K_{2^n+1}, but they do not determine the growth order; the search recorded under Current assessment found nothing further, and that negative result is not proof of openness. Two refereed bounds are accepted partial claims: Day and Johnson's lower bound, which answers Chung's question whether f(n)→∞f(n)\to\infty, and Janzer and Yip's upper bound. Two partial claims are pending: Girão and Hunter's earlier upper bound, a preprint, and the value f(3)=5f(3)=5, recorded on its claim page.

Source. erdosproblems.com/609, accessed 2026-09-04. Cite as: T. F. Bloom, Erdős Problem #609, https://www.erdosproblems.com/609.

References.

  • [Ch97] Chung, F. R. K., Open problems of Paul Erdős in graph theory. J. Graph Theory (1997), 3-36. 1997 preprint.
  • [DaJo17] Day, A. Nicholas and Johnson, J. Robert, Multicolour Ramsey numbers of odd cycles. J. Combin. Theory Ser. B (2017), 56-63.
  • [GiHu24] A. Girão and Z. Hunter, Monochromatic odd cycles in edge-coloured complete graphs. arXiv:2412.07708 (2024).
  • [JaYi25] O. Janzer and F. Yip, Short monochromatic odd cycles. Math. Proc. Cambridge Philos. Soc. 181 (2026), no. 1, 781--788, doi:10.1017/S0305004125101801; arXiv:2506.14910 (2025).

Formalization. A statement only. The file ErdosProblems/609.lean of formal-conjectures, linked at the main commit of 18 September 2026, defines f(n)f(n) as the least mm such that every nn-coloring of the edges of K2n+1K_{2^n+1} has a monochromatic odd cycle of length at most mm, and declares erdos_609, the assertion that ff has the growth order of an unspecified function (answer(sorry)), under category research open with proof sorry. It carries no formal_proof attribute, so it records no formal proof. The file was added on 9 September 2026; the site's indicator reads "Formalised statement? Yes", and the community database lists the statement as formalized since 9 September 2026 with formal status unformalized.

Current assessment

The best compiled exact-threshold bounds are

f(n)≥22log⁡2n−O(1)f(n)\geq2^{\sqrt{2\log_2 n}-O(1)}

from Day--Johnson and

f(n)=O ⁣(n3/22n/2)f(n)=O\!\left(n^{3/2}2^{n/2}\right)

from Janzer--Yip. Both concern nn colors on exactly K2n+1K_{2^n+1}. Their orders remain far apart, so neither the upper-bound breakthrough nor the unbounded lower bound estimates f(n)f(n) to a determined asymptotic order.

Girão--Hunter's earlier exact-threshold upper bound

f(n)≤2n+1n1−εf(n)\leq\frac{2^n+1}{n^{1-\varepsilon}}

holds for every fixed ε>0\varepsilon>0 and all sufficiently large nn. It is historically important but is weaker than the later Janzer--Yip bound.

The bounded status search checked the current arXiv version records for Day--Johnson, Girão--Hunter, Janzer--Yip, Axenovich et al., Huang--Yang--Chen, and Miyazaki et al.; the Cambridge published record and repository entry for Janzer--Yip; an author publication page; exact-title and exact-parameter web/arXiv queries; and public X/web announcement queries. The Erdős Problems site's search listing classified the question as open. No additional result resolving the problem, closing the Day/Girão/Janzer gap, or matching the opposite bound's order was located in this bounded search. That absence does not certify openness or an exhaustive priority claim.

Proof claims on the site. The site's proof-claim tab carries one partial claim, submitted 25 September 2026: that f(3)=5f(3)=5, by the classical R(3,3,3)=17R(3,3,3)=17 for the lower bound and a structural argument with a finite enumeration and a SAT check for the upper bound. It concerns the case n=3n=3 only and leaves the asymptotic question untouched. It is recorded, with its provenance, on its claim page; the site's label is OPEN, and the claim is not accepted.

Progress

Day--Johnson construct nn-colorings of K2n+1K_{2^n+1} whose monochromatic odd girth is at least 22log⁡2n−O(1)2^{\sqrt{2\log_2 n}-O(1)}. Their Corollary 6 is on pp. 5--6 of arXiv:1602.07607v2. This proves in particular that f(n)→∞f(n)\to\infty.

Girão--Hunter Theorem 1.2 (arXiv:2412.07708v1, p. 1) gives the first o(2n)o(2^n) upper bound at the exact host. Its numerator is exactly 2n+12^n+1.

Janzer--Yip Theorem 1.4 improves this exponentially to O(n3/22n/2)O(n^{3/2}2^{n/2}). The same statement is Theorem 1.4, p. 2, of both arXiv:2506.14910v1 and the published 2026 Cambridge edition.

Their Theorem 1.5 is the separately quantified near-threshold result for N=(1+δ)2nN=(1+\delta)2^n. Specializing δ=2−n\delta=2^{-n} recovers Theorem 1.4 at N=2n+1N=2^n+1; it is not an additional sharper exact-threshold estimate.

Known Results

ResultStatement relevant to E609Interface and scope
Day--Johnson, Corollary 6f(n)≥22log⁡2n−O(1)f(n)\geq2^{\sqrt{2\log_2 n}-O(1)}arXiv v2 source, exact host
Girão--Hunter, Theorem 1.2f(n)≤(2n+1)/n1−εf(n)\leq(2^n+1)/n^{1-\varepsilon} for fixed ε>0\varepsilon>0 and large nnExact result page, exact host
Janzer--Yip, Theorem 1.4f(n)=O(n3/22n/2)f(n)=O(n^{3/2}2^{n/2})Exact result page, exact host

Several nearby results do not improve these exact-threshold bounds. Axenovich et al. Theorem 1.2 requires a host of order greater than bnb^n for b>2b>2 and explicitly gives no nontrivial conclusion at 2n+12^n+1. Huang--Yang--Chen Theorem 5 fixes the target cycle length before the number of colors grows. In contrast, Miyazaki--Mulrenin--Pohoata--Zheng Remark 2.2 gives the uniform bound

r(C2ℓ+1;q)≤(4ℓ−2)q(q!)1/ℓ+1.r(C_{2\ell+1};q)\leq(4\ell-2)^q(q!)^{1/\ell}+1.

This upper bound exceeds 2q+12^q+1 for every positive pair (q,ℓ)(q,\ell) other than (1,1)(1,1): at ℓ=1\ell=1 it is 2qq!+12^q q!+1, which is larger for q≥2q\geq2; at ℓ≥2\ell\geq2 it is at least 6q+1>2q+16^q+1>2^q+1. It therefore supplies no guaranteed cycle length at the exact host apart from the elementary one-color triangle case. Miyazaki et al.'s Theorem 1.3 has an exact 2n2^n threshold for an additive-coloring statement. Its conclusion concerns colorings of integers, not arbitrary edge-colorings, and does not itself supply the required cycle-length bound. This is the application boundary here; the paper's p. 3 comparison instead explains why the additive theorem is not a direct consequence of the graph-theoretic odd-cycle existence fact.

Linked library material

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