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Claim. In the notation of Problem 609, f(3)=5f(3)=5: every 33-coloring of the edges of K9K_9 has a monochromatic odd cycle of length at most 55, and some 33-coloring has none of length 33. The lower bound is the classical R(3,3,3)=17>9R(3,3,3)=17>9, which gives a 33-coloring of K9K_9 with no monochromatic triangle. For the upper bound the write-up supposes a 33-coloring of K9K_9 with no monochromatic C3C_3 or C5C_5 and argues in three steps. First, no color class is bipartite: a bipartite class has a side with at least five vertices, inside which the other two colors would each have to be bipartite (an odd cycle on five vertices has length 33 or 55), and two bipartite graphs cannot cover K5K_5, since assigning each vertex its pair of sides gives five vectors in {0,1}2\{0,1\}^2, two of which coincide. Second, each class, having odd girth 77 or 99, has at most 1212 edges: a C7C_7 in it is induced, the two vertices off the cycle each send at most two edges to it, and the edge between them adds one, for 7+2+2+1=127+2+2+1=12; a class with no C7C_7 has a chordless Hamiltonian C9C_9 with nine edges. Third, the 3636 edges force each class to have exactly 1212 edges and the first shape; the admissible 1212-edge graphs form a single isomorphism class with 9!/8=45,3609!/8=45{,}360 labeled copies, and a direct enumeration finds no three pairwise edge-disjoint copies covering K9K_9. A SAT encoding with one variable per edge and color, forbidding each monochromatic C3C_3 and C5C_5, is reported unsatisfiable, and the same encoding with only triangles forbidden satisfiable.

Submission note. Posted to erdosproblems.com as a proof claim by Botnet AI agent grind-09 (proof); verified by Claude (Anthropic); submitted by Jeremy Cai (account jjeremycai) on 25 September 2026, giving "Grok 4.7 (found the argument, via Botnet agent grind-09); Claude (Anthropic): independent SAT/orbit verification and drafting of this summary and write-up" as the AI used:

Partial result: f(3)=5f(3)=5. Lower bound: R(3,3,3)=17R(3,3,3)=17, so K9K_9 has a 3-colouring with no monochromatic triangle. Upper bound: suppose a 3-colouring of K9K_9 has no monochromatic C3C_3 or C5C_5. No colour is bipartite (a side of size ≥5\geq 5 would force K5K_5 to be covered by two bipartite graphs, impossible). So each colour has odd girth 7 or 9, and then at most 12 edges: a C7C_7 is induced and each of the two remaining vertices has at most two neighbours on it, while a C9C_9 with no C7C_7 has no chords. So each colour has exactly 12 edges, and every such graph is one isomorphism class (45360 labelled copies); a finite check shows no three of them partition K9K_9. Also confirmed by an exhaustive SAT check. Settles only n=3n=3; no effect on the asymptotic bounds. Notes: AI disclosure: the argument was found by an AI agent on Botnet, and this summary and the linked write-up were drafted by Claude (Anthropic) at my request; I reviewed them before submitting. The linked write-up includes the SAT and orbit-count scripts. I found no statement of f(3) on this page, in Girão-Hunter or in Janzer-Yip, but I have not checked Day-Johnson.

Covers. The value f(3)=5f(3)=5, the case n=3n=3 of the problem. The estimation of f(n)f(n) as nn grows, the problem's question, is untouched, as the claim itself says; the asymptotic bounds on the problem page are unaffected.

Depends on. Nothing in this wiki; the argument rests on the classical value R(3,3,3)=17R(3,3,3)=17 and on the finite checks described in the write-up.

Standing. Claimed. The claim was submitted by Jeremy Cai, the claimant this page is named for. The site's tab credits the proof to the Botnet AI agent grind-09, through which Grok 4.7 found the argument, and credits Claude (Anthropic) with the independent SAT and orbit verification and with drafting the summary and the write-up at the submitter's request; the submitter's notes say the submitter reviewed them before submitting. That is provenance only. The write-up at the linked URL (133 lines of plain text including the two verification scripts) has not been checked outside the submission: the scripts have not been run and the enumeration has not been repeated, so no evidence kind is listed. The submitter adds that no statement of f(3)f(3) was found on the problem page or in the Girão--Hunter and Janzer--Yip papers, and that Day--Johnson was not checked; whether the value appears in the literature is not established. The claim had no comments on the site's tab and the site's label is OPEN.