Wiki
Wiki

Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

Updated

Problem 1181

../


Statement. Let q(n,k)q(n,k) denote the least prime which does not divide ∏1≤i≤k(n+i)\prod_{1\leq i\leq k}(n+i). Is it true that there exists some c>0c>0 such that, for all large nn,

q(n,log⁡n)<(1−c)(log⁡n)2?q(n,\log n)<(1-c)(\log n)^2?

Formulation. The site's wording (page last edited 7 March 2026). $q(n,\log n)$ is q(n,⌊log⁡n⌋)q(n,\lfloor\log n\rfloor), as Erdős writes it (k=[log⁡n]k=[\log n], printed p. 78). The question asks whether the trivial upper bound $q(n,\log n)\le(1+o(1))(\log n)^2$, which holds for all nn, can be lowered by a constant factor for all large nn; it is Erdős's 1979 sentence "We could not even prove that q(n,[log⁡n])<(1−ε)(log⁡n)2q(n,[\log n])<(1-\varepsilon)(\log n)^2." The site created the page on 7 March 2026 by splitting the upper-bound question off Problem 457, which concerns lower bounds for q(n,log⁡n)q(n,\log n). The site's source key is [Er79d, p. 78].

Status. Open. The only bound in hand is the trivial one, $q(n,\log n)\le(1+o(1))(\log n)^2$ for all nn, Erdős's display (10) at k=[log⁡n]k=[\log n], which the site derives by comparing the primorial of q(n,k)q(n,k) with the product: every prime below q(n,k)q(n,k) divides ∏1≤i≤k(n+i)\prod_{1\le i\le k}(n+i), so their product is at most it. The construction accepted on Problem 457 gives $q(n,\log n)>A\log n$ for every fixed AA and infinitely many nn. A sketch by Tao in that thread gives q(n,log⁡n)>1−o(1)2log⁡log⁡nlog⁡log⁡log⁡nlog⁡nq(n,\log n)>\frac{1-o(1)}2\frac{\log\log n}{\log\log\log n}\log n for infinitely many nn; the site reports it as proved, but no accepted claim covers it, and the written version there, a claimed page, reaches only the ≫\gg form. Both are far below (log⁡n)2(\log n)^2, and a heuristic recorded by Tao in the thread of Problem 457 suggests q(n,log⁡n)≪log⁡nlog⁡log⁡n/log⁡log⁡log⁡nq(n,\log n)\ll\log n\log\log n/\log\log\log n for all nn, which he regards as beyond current methods. No source improving the trivial bound was found in the search whose scope the Current assessment records; this is a bounded negative finding, not a certificate of openness.

Source. erdosproblems.com/1181, accessed 2026-09-18 at 10:27 UTC: the problem page (labeled OPEN, with the site's note that no finite computation can settle it; last edited 7 March 2026; source key [Er79d, p. 78]; commentary citing Problem 457; a thanks line crediting Terence Tao), its empty discussion thread and its empty proof-claim tab. Cite as: T. F. Bloom, Erdős Problem #1181, https://www.erdosproblems.com/1181, accessed 2026-09-18.

References.

  • [Er79d] Erdős, P., Some unconventional problems in number theory. Acta Math. Acad. Sci. Hungar. 33 (1979), no. 1--2, 71--80, DOI 10.1007/BF01903382; Section 3, printed p. 78: the definition of q(n,k)q(n,k), display (10), the example and the two questions. Library home: erdos_1979_unconventional_problems_number_theory.
  • [OEIS] Bottomley, H., Sequences A053669--A053674, The On-Line Encyclopedia of Integer Sequences (2000): the least prime not dividing nn, and the least number coprime to n,n+1,…,n+jn,n+1,\ldots,n+j for j=1,…,5j=1,\ldots,5, that is q(n−1,j+1)q(n-1,j+1); the community database lists them as possible matches. Data leads only.

Formalization. None for this problem: on 2026-09-18 formal-conjectures had no file ErdosProblems/1181.lean, and the site showed no formalized statement. The question is, however, encoded in the collection's file for Problem 457 as the variant erdos_457.variants.one_sub : answer(sorry) ↔ ∃ ε > (0 : ℝ), ∀ᶠ n in Filter.atTop, q n (Real.log n) < (1 - ε) * Real.log n ^ 2 under category research open, with q n k the least prime not dividing ∏1≤i≤⌊k⌋(n+i)\prod_{1\le i\le\lfloor k\rfloor}(n+i). The community database (fetched 2026-09-18) records the problem open (last changed 7 March 2026), the statement not formalized, formal_status unformalized, OEIS A053669--A053674 and "possible", and no formal-proof URL. Nothing was built.

Current assessment

The question (site formulation of 2026-09-18). The statement above, labeled OPEN with the note that no finite computation can settle it, last edited 7 March 2026. The commentary, in summary: the trivial upper bound comes from comparing the primorial of q(n,k)q(n,k) with the product ∏1≤i≤k(n+i)\prod_{1\le i\le k}(n+i); Tao's heuristics in the discussion of Problem 457 point to $q(n,\log n)\ll\frac{\log\log n}{\log\log\log n}\log n$ at every nn; and Problem 457 is the companion question on lower bounds, with a parenthetical remark that its constructions show the upper bound to be best possible. The thread and the proof-claim tab are empty. The parenthetical remark is best taken to mean that the constructions of Problem 457 give lower bounds, not that the (log⁡n)2(\log n)^2 bound is attained: the constructions give q(n,log⁡n)q(n,\log n) of order $\log n\log\log n/\log\log\log n$ along a sequence, and nothing in the sources reaches $(\log n)^2$.

The origin. [Er79d], printed p. 78, Section 3, presents the problem as joint work with Pomerance: with A(n,k)=∏1≤i≤k(n+i)A(n,k)=\prod_{1\le i\le k}(n+i) and q(n,k)q(n,k) the least prime not dividing A(n,k)A(n,k), display (10) states q(n,k)<(1+o(1))klog⁡nq(n,k)<(1+o(1))k\log n, which Erdős calls very crude, expecting that when kk is bounded, or merely k=o(log⁡n)k=o(\log n), the bound might hold with log⁡n\log n in place of klog⁡nk\log n. He singles out the case k=[log⁡n]k=[\log n], observes that taking nn to be the product of the primes between log⁡n\log n and (2+o(1))log⁡n(2+o(1))\log n makes q(n,[log⁡n])q(n,[\log n]) as large as (2+o(1))log⁡n(2+o(1))\log n (as printed; with the product over 1≤i≤k1\le i\le k the example needs n+1n+1 to be that product), and asks, in his words: "Is it true that q(n,[log⁡n])<(2+ε)log⁡nq(n,[\log n])<(2+\varepsilon)\log n for n>n0(ε)n>n_0(\varepsilon)? We could not even prove that q(n,[log⁡n])<(1−ε)(log⁡n)2q(n,[\log n])<(1-\varepsilon)(\log n)^2." The first of the two questions is the negation of Problem 457's statement, answered there in the site's favor; the second is this problem.

The trivial bound (the site's argument). Every prime p<q(n,k)p<q(n,k) divides ∏1≤i≤k(n+i)≤(n+k)k\prod_{1\le i\le k}(n+i)\le(n+k)^k, so the primorial ∏p<q(n,k)p\prod_{p<q(n,k)}p is at most (n+k)k(n+k)^k; taking logarithms, ϑ(q(n,k))≤klog⁡(n+k)\vartheta(q(n,k))\le k\log(n+k) up to the last prime, and ϑ(x)∼x\vartheta(x)\sim x (the prime number theorem) gives q(n,k)≤(1+o(1))klog⁡nq(n,k)\le(1+o(1))k\log n when k≤nk\le n, which is Erdős's (10); at k=⌊log⁡n⌋k=\lfloor\log n\rfloor it reads q(n,log⁡n)≤(1+o(1))(log⁡n)2q(n,\log n)\le(1+o(1))(\log n)^2. Erdős calls this "very crude" and expects, for k=o(log⁡n)k=o(\log n), that klog⁡nk\log n can be replaced by log⁡n\log n; the question here is only whether the constant 11 can be lowered in the special case k=[log⁡n]k=[\log n].

Lower bounds and the heuristic (context from Problem 457). Erdős's example gives q(n,[log⁡n])≥(2+o(1))log⁡nq(n,[\log n])\ge(2+o(1))\log n when n+1n+1, not nn as printed, is the product of the primes between log⁡n\log n and (2+o(1))log⁡n(2+o(1))\log n. With nn itself the product, n+i≡i≢0(modp)n+i\equiv i\not\equiv0\pmod p for each such prime pp and $1\le i\le\log n$, so none of them divides the block. Tao's post of 7 March 2026 in the thread of Problem 457 records the slip, which a GPT attempt had pointed out; the 2026 construction accepted on Problem 457 gives, for every fixed AA, infinitely many nn with q(n,log⁡n)>Alog⁡nq(n,\log n)>A\log n, and its elaboration in that problem's thread gives infinitely many nn with $q(n,\log n)>\frac{1-o(1)}2\frac{\log\log n}{\log\log\log n}\log n$ (the site's account of an AI-generated argument and a sketch by Tao; see Problem 457 for the provenance and qualifications). These are lower bounds along a sequence and say nothing about the maximum of q(n,log⁡n)q(n,\log n) over all large nn. Tao's comment of 10 September 2025 on that thread records that standard probabilistic heuristics put the growth of q(n,log⁡n)q(n,\log n) at about log⁡n(log⁡log⁡n)/(log⁡log⁡log⁡n)\log n(\log\log n)/(\log\log\log n), while a rigorous justification is, in his view, beyond current methods; his comment of 2 March 2026 expects the matching upper bound to be extremely difficult, since the much weaker bound posed in the commentary, this problem, remains open. So the expected truth is a factor log⁡nlog⁡log⁡log⁡n/log⁡log⁡n\log n\log\log\log n/\log\log n below the trivial bound, and even a constant-factor saving is open.

The bounds map. For all large nn, q(n,log⁡n)≤(1+o(1))(log⁡n)2q(n,\log n)\le(1+o(1))(\log n)^2; for infinitely many nn, q(n,log⁡n)>Alog⁡nq(n,\log n)>A\log n for every fixed AA by the construction accepted on Problem 457, and $q(n,\log n)>\frac{1-o(1)}2\frac{\log\log n}{\log\log\log n}\log n$ by Tao's sketch there, which is not an accepted claim; both hold along a sequence and not at every scale; conjecturally q(n,log⁡n)≪log⁡nlog⁡log⁡n/log⁡log⁡log⁡nq(n,\log n)\ll\log n\log\log n/\log\log\log n for all nn. The OEIS entries A053669--A053674 list q(n−1,j+1)q(n-1,j+1) for j≤5j\le5, small fixed kk rather than k=log⁡nk=\log n; they are data leads and were not used.

Search scope. None of the routes below found a bound q(n,log⁡n)≤(1−c)(log⁡n)2q(n,\log n)\le(1-c)(\log n)^2, a disproof, or a proof claim.

  • The site: problem page, discussion thread and proof-claim tab as read on 2026-09-18; the problem page and thread of Problem 457 read the same day (the source of the lower bounds and the heuristic); the formal-conjectures directory listing and tree (no file for this problem; the variant in 457.lean read); the community database.
  • arXiv: the API queries abs:"least prime" AND abs:"does not divide" AND abs:consecutive and all:"Erdős Problem" AND (all:451 OR all:457 OR all:961 OR all:962 OR all:1181) (no records); the API searches titles and abstracts only, so these zeros are weak.
  • Crossref: the record of [Er79d].
  • OEIS: the JSON records of A053669--A053674.
  • The primary source: [Er79d], printed p. 78.

Not searched: MathSciNet, zbMATH, Google Scholar, X. Not held: [Er79d].

Remaining gaps. (1) No result beyond the trivial bound exists in any source found; the problem is open in the strong sense that no method is recorded for it (the thread of Problem 457 describes it as a problem of a different nature, about ruling out long consecutive runs of nearly smooth numbers). (2) The trivial bound's derivation above is the site's one-line argument, written out here with the prime number theorem as its only input; it is not a source result. (3) The lower bounds quoted from Problem 457 carry that page's qualifications (a site-accepted AI-generated construction and a forum sketch).

Linked library material

These entries are derived from explicit links on library pages. They are navigation only and do not by themselves record mathematical progress.