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Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

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Statement

"Pomerance and I considered the following problem. Put A(n,k)=∏1≤i≤k(n+i)A(n,k)=\prod_{1\le i\le k}(n+i) and denote by q(n,k)q(n,k) the least prime which does not divide A(n,k)A(n,k). Clearly,

q(n,k)<(1+o(1))klog⁡n.(10)q(n,k)<(1+o(1))k\log n. \qquad (10)

This is clearly very crude. For bounded kk and, more generally, for k=o(log⁡n)k=o(\log n), the factor klog⁡nk\log n in (10) can perhaps be replaced by log⁡n\log n. An interesting special case is k=[log⁡n]k=[\log n]. By choosing nn so that it is the product of the primes between log⁡n\log n and (2+o(1))log⁡n(2+o(1))\log n, we see that q(n,[log⁡n])q(n,[\log n]) can be as large as (2+o(1))log⁡n(2+o(1))\log n. Is it true that q(n,[log⁡n])<(2+ε)log⁡nq(n,[\log n])<(2+\varepsilon)\log n for n>n0(ε)n>n_0(\varepsilon)? We could not even prove that q(n,[log⁡n])<(1−ε)(log⁡n)2q(n,[\log n])<(1-\varepsilon)(\log n)^2."

The bound (10) is stated with "Clearly" and no argument; the example is the only construction. Nothing else in the paper returns to q(n,k)q(n,k).

Source. P. Erdős, Some unconventional problems in number theory, Acta Math. Acad. Sci. Hungar. 33 (1979), 71--80; printed p. 78 (PDF p. 8 of the 10-page scan), read on the page image.

Read depth. Claims checked: the passage was read clause by clause on the page image. The bound (10) and the example are asserted without proof; the example's indexing is checked under Proof pointer.

Proof pointer

None printed. Read as printed, the example fails: if nn is the product of the primes in (log⁡n,(2+o(1))log⁡n)(\log n,(2+o(1))\log n), each such prime divides nn and so divides n+in+i only if it divides ii, which it cannot for 1≤i≤[log⁡n]1\le i\le[\log n]; no prime of that range divides A(n,[log⁡n])A(n,[\log n]), and q(n,[log⁡n])q(n,[\log n]) is the least prime above log⁡n\log n. The example works when n+1n+1 rather than nn is that product, or when the product defining AA starts at i=0i=0, as the thread of Problem 457 notes: every prime up to [log⁡n][\log n] divides one of the [log⁡n][\log n] consecutive factors and every prime of the range divides n+1n+1 (or nn), so q(n,[log⁡n])≥(2+o(1))log⁡nq(n,[\log n])\ge(2+o(1))\log n. The statement is Erdős's and the details are not supplied.

Dependencies

None stated; the prime number theorem underlies the sizes.

Bears on

  • Problem 457: the origin passage for the question whether q(n,log⁡n)<(2+ε)log⁡nq(n,\log n)<(2+\varepsilon)\log n; the site's header locator is [Er79d, p. 78].
  • Problem 1181: the origin passage for the question whether q(n,log⁡n)<(1−ε)(log⁡n)2q(n,\log n)<(1-\varepsilon)(\log n)^2, with Erdős's bound (10).