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Problem 771

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claims/: The 1 claim page of Problem 771, one per claimant's result; the problem's standing derives from them.


Statement. Let f(n)f(n) be maximal such that, for every m≥1m\geq 1, there exists some S⊆{1,…,n}S\subseteq \{1,\ldots,n\} with ∣S∣=f(n)\lvert S\rvert=f(n) such that m≠∑a∈Aam\neq \sum_{a\in A}a for all A⊆SA\subseteq S.

Is it true that

f(n)=(12+o(1))nlog⁡n?f(n) = \left(\frac{1}{2}+o(1)\right)\frac{n}{\log n}?

Status. Proved: a conjecture of Erdős and Graham. They observed the lower bound f(n)≥(12+o(1))nlog⁡nf(n)\ge(\frac12+o(1))\frac n{\log n} (for every mm, which one may take below (n+12)\binom{n+1}2, the multiples of the least prime not dividing mm, a prime below (2+o(1))log⁡n(2+o(1))\log n, avoid mm as a subset sum), and Alon and Freiman [AlFr88] proved the matching upper bound by exhibiting an mm, the least common multiple of the integers below ss with ss largest such that m≤n2/(20log⁡2n)m\le n^2/(20\log^2n), whose avoiding sets have at most (12+o(1))nlog⁡n(\frac12+o(1))\frac n{\log n} elements. The site labels the problem PROVED and credits the paper. Claim page: Alon and Freiman 1988 (accepted, refereed in Combinatorica).

Source. erdosproblems.com/771, accessed 2026-09-04, and the cached snapshot of 2026-09-05 (refresh of 22:48 UTC): PROVED, header key [Er89], no last-edited line, an empty discussion thread and an empty proof-claim tab, no formalized statement, OEIS "Possible". Cite as: T. F. Bloom, Erdős Problem #771, https://www.erdosproblems.com/771.

References.

  • [AlFr88] Alon, N. and Freiman, G., On sums of subsets of a set of integers. Combinatorica (1988), 297-306.

Formalization. None recorded.

Progress

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Known Results

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Linked library material

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