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Problem 209

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claims/: The 2 claim pages of Problem 209, one per claimant's result; the problem's standing derives from them.


Statement. Let AA be a finite collection of d≥4d\geq 4 non-parallel lines in R2\mathbb{R}^2 such that there are no points where at least four lines from AA meet. Must there exist a 'Gallai triangle' (or 'ordinary triangle'): three lines from AA which intersect in three points, and each of these intersection points only intersects two lines from AA?

Status. DISPROVED (LEAN). The question as stated is refuted already by an elementary arrangement of four lines (Current assessment); the site credits Füredi and Palásti and Escudero, whose arrangements together cover every d≥4d\ge4.

Source. erdosproblems.com/209, accessed 2026-09-04. Cite as: T. F. Bloom, Erdős Problem #209, https://www.erdosproblems.com/209.

References.

  • [Er84] Erdős, P., Research problems. Period. Math. Hungar. 15 (1984), 101-103; the site's first source key for the problem.
  • [ErPu95b] Erdős, P. and Purdy, G., Extremal problems in combinatorial geometry. Handbook of Combinatorics, Vol. 1, Elsevier (1995), 809-874, p. 818; the site's second source key, and the reference Escudero gives for the question.
  • [Es16] Escudero, Juan García, Gallai triangles in configurations of lines in the projective plane. C. R. Math. Acad. Sci. Paris 354 (2016), no. 6, 551-554.
  • [FuPa84] Füredi, Z. and Palásti, I., Arrangements of lines with a large number of triangles. Proc. Amer. Math. Soc. (1984), 561-566.

Formalization. Statement in formal-conjectures.

Current assessment

The question is whether every arrangement of d≥4d\ge 4 pairwise non-parallel real lines with no point on four or more of them must contain a Gallai triangle, three of the lines whose three corners each lie on exactly two lines of the arrangement. In the dual picture it asks whether nn points with no four on a line must contain three points whose three connecting lines are each ordinary, that is, contain exactly two of the points. The Sylvester-Gallai theorem gives one point where exactly two lines meet; the question asks for three such points forming a triangle.

The answer is no. A single arrangement with no Gallai triangle refutes the question, which asks whether such a triangle must exist in every admissible arrangement, and the formal-conjectures file states it that way. The question already fails for an elementary arrangement: three lines through one point PP together with a fourth line that is parallel to none of them and misses PP are d=4d=4 pairwise non-parallel lines with no point on four of them, and every triangle among them uses two of the concurrent lines, so it has PP, a point on three lines, as a corner and is not Gallai. Two accepted full claims record the answer, and the first is Füredi and Palásti (1984), whose arrangements have no Gallai triangle for every d≥4d\ge 4 not divisible by 99; Escudero (2016) gives arrangements for every d≥4d\ge 4, adding the multiples of 99. Both results are refereed, and the site's curator credits both.

The question the two papers answer is the one the sources pose for each number of lines: whether, for every d≥4d\ge 4, some arrangement of dd lines with no point on four of them has no Gallai triangle. Füredi and Palásti answer it for every d≥4d\ge 4 not divisible by 99, and Escudero for every d≥4d\ge 4, so for every admissible dd an arrangement without a Gallai triangle exists. This per-dd formulation is a stronger variant: its positive answer refutes the Statement's question at every d≥4d\ge 4. The site's Lean qualification refers to a third-party Lean development of Escudero's construction, which the formal_proof attribute of the formal-conjectures file cites; this corpus has not built it, and the formal-conjectures file itself states the problem without a proof.

Status search: the site's page and its formal-conjectures entry, the publishers' records of the two papers, and the Escudero source card. The corpus records no check of either proof. Problem 960 on the site is listed as related.

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