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Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

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Problem 1197

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claims/: The 1 claim page of Problem 1197, one per claimant's result; the problem's standing derives from them.


Statement. Let E⊂(0,∞)E\subset (0,\infty) be a set of positive measure. Is it true that, for almost all x>0x>0, for all sufficiently large (depending on xx) integers nn there exists an integer r≥1r\geq 1 such that nx∈r⋅Enx\in r\cdot E?

Status. DISPROVED (LEAN), the site's label. Enrique Barschkis, posting as ebarschkis, constructed a measurable set of positive measure and an interval of xx on which infinitely many nn put nxnx outside every r⋅Er\cdot E, by varying the Buczolich–Mauldin construction; the accepted claim is Barschkis's counterexample, credited by the site's curator and not refereed. The Lean proofs behind the site's qualification are linked on the claim page; none was built here.

Source. erdosproblems.com/1197, accessed 2026-09-04. Cite as: T. F. Bloom, Erdős Problem #1197, https://www.erdosproblems.com/1197.

References.

  • [BuMa99] Buczolich, Zoltán and Mauldin, R. Daniel, On the convergence of ∑n=1∞f(nx)\sum^\infty_{n=1}f(nx) for measurable functions. Mathematika (1999), 337-341.

Formalization. The site's label carries the suffix "(LEAN)", a catalog label; this corpus has built none of the Lean developments. Statement in formal-conjectures, pinned to its revision of 2026-10-07 (the file was added on 20 September 2026). Its theorem erdos_1197, tagged research solved with answer(False), states that for every measurable E⊂(0,∞)E\subset(0,\infty) of positive measure, for almost every x>0x>0, for all large nn some integer r≥1r\ge1 has nx∈r⋅Enx\in r\cdot E; its proof is left open, and a formal_proof attribute points to not_erdos_1197 in Boris Alexeev's lean-proofs repository. That file and three other developments, the author's own file, the Tomodovodoo repository and the Jayyhk erdos-lean file, are linked on the claim page at their commits; none was built or audited here, and the standing rests on the manuscript and the curator's credit.

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