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Nguyen (2022): Sparse Fibonacci reciprocal series
theorem_1_2: Nguyen's transcendence theorem: if c > 2 and the positive integers n_1 < n_2 < ... satisfy n_{k+1}/n_k >= c for every k, then the sum of 1/f_k is transcendental for any choice of f_k among F_{n_k} and L_{n_k}.
theorem_1_3: Nguyen's main theorem: for a real quadratic unit alpha, rational terms u_n = a_n alpha^n - b_n beta^n with coefficients of subexponential height, and indices with n_{k+1}/n_k >= c > 2, the sum of c_{n_k}/u_{n_k} is transcendental.
Khoa Dang Nguyen, Transcendental series of reciprocals of Fibonacci and Lucas numbers, Algebra & Number Theory 16 (2022), no. 7, 1627--1654, doi:10.2140/ant.2022.16.1627. The result labels below were checked in arXiv:2009.02446v1, rather than the publisher's text.
Question 1.1 (p. 1) repeats the Erdős--Graham question in Problem 267, which asks whether is irrational whenever . The paper's results:
- Theorem 1.2 (p. 1): if and are positive integers with for every , then
is transcendental for any choice of , where is the Lucas sequence: and for . The print's definition reads , a misprint, as Example 1.4's shows.
- Theorem 1.3 (p. 3), the main theorem: the same conclusion for , where is a real quadratic unit with conjugate , ; are real with , and ; their logarithmic Weil heights are ; and , for every . Theorem 1.2 is its special case (Example 1.4, p. 3). The proof (Sections 3--5, pp. 5--26) uses the Subspace Theorem.
The paper points out (p. 2) that irrationality for already follows from the estimate ; the new conclusion is transcendence. The abstract states that the bound is best possible, because of the identity (the Millin series, p. 1), whose index ratios equal . Theorem 1.2 says nothing about sequences whose ratios are bounded below only by a constant .
Source: https://doi.org/10.2140/ant.2022.16.1627.
Edition read. The copy read for this card is the arXiv v1 PDF (arXiv:2009.02446v1). The arXiv record names arXiv's non-exclusive distribution license (arXiv:2009.02446), every other right reserved.
Bears on. #267: Theorem 1.2 with gives transcendence, hence irrationality, of when the ratios are at least a constant ; it does not reach constants .
Read status. Claims checked: Question 1.1, Theorems 1.2 and 1.3, Examples 1.4 and 1.5, and the comparison with the elementary irrationality bound were read in arXiv v1, pp. 1--3. The proof was read for its structure only and was not checked.
No file of this source is held: no license on record permits its redistribution, and the card cites the edition it names above.