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Erdos 1960 extremum problems elementary geometry

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conjecture_p54: Erdős's conjecture, recorded in the paper, that any 2^n + 1 points in n-space determine an angle greater than pi/2, known then for n <= 3, with a note added in proof that Danzer and Grünbaum proved it; the paper proves nothing on it.

construction_section_2: Erdős and Szekeres's explicit construction of 2^{n-2} points in the plane containing no convex n-gon, which with their 1935 upper bound brackets f_0(n), together with the conjecture f_0(n) = 2^{n-2} for every n >= 3 that the paper records.

theorem_1: Erdős and Szekeres's theorem that every plane configuration of 2^n points, n >= 3, contains an angle greater than (1 - 1/n)pi, which with Szekeres's 1941 configurations gives alpha(2^n) = (1 - 1/n)pi with the strict inequality.

theorem_2: Erdős and Szekeres's lower bound alpha(2^n - k) >= (1 - 1/n)pi - k pi/2(2^n - k) for 0 < k < 2^{n-1}, a bound on the largest forced angle between consecutive powers of two.

theorem_3: Erdős and Szekeres's sharpening of Theorem 2 at k = 1, printed for n >= 2 but true only from n = 3, which gives alpha(2^n - 1) = (1 - 1/n)pi and leaves open whether the inequality is strict there.

values_p54: The values of the largest forced angle alpha(m) for 3 <= m <= 8 that the paper says one can easily verify, with regular polygons extremal for 3 <= m <= 6 and the strict inequality holding for m = 7 and 8.


P. Erdős, G. Szekeres: On some extremum problems in elementary geometry, Ann. Univ. Sci. Budapest. Eötvös Sect. Math. 3--4 (1960/1961), 53--62 (MR 24 #A3560; Zentralblatt 103,155).

The paper attacks two extremal problems for finite planar point sets. First, writing f_0(n) for the least integer such that every planar set of more than f_0(n) points contains a convex n-gon, Section 2 constructs a set of 2^{n-2} points containing no convex n-gon, which combined with the authors' earlier upper bound gives 2^{n-2} <= f_0(n) <= binomial(2n-4, n-2); they conjecture f_0(n) = 2^{n-2} but can neither prove nor disprove it, noting it is known for n <= 5. Second, for α(m) the largest angle guaranteed in every configuration of m planar points, they record α(3) = π/3, α(4) = π/2, α(5) = 3π/5, α(6) = α(7) = α(8) = 2π/3 and prove Theorem 1 in Section 4: among any 2^n points of the plane (n >= 3) some three span an angle greater than (1 - 1/n)π, which together with Szekeres's construction gives α(2^n) = (1 - 1/n)π exactly and settles the strict-inequality question for m = 2^n. Theorem 2 gives the weaker bound α(2^n - k) >= (1 - 1/n)π - kπ/2(2^n - k) for 0 < k < 2^{n-1}, and Theorem 3, in a note added in proof, sharpens the case k = 1 to α(2^n - 1) = (1 - 1/n)π, leaving open whether the inequality is strict there; the print states it for n >= 2, but it holds only for n >= 3. The construction for the polygon bound uses convex and concave sequences of points in Cartesian coordinates; a footnote added in proof records that Erdős's conjecture on an angle exceeding π/2 among 2^n + 1 points in n-space was proved by Danzer and Grünbaum; that conjecture is problem 224. The paper supplies the 2^{n-2} lower bound for problem 107 (the Erdős-Szekeres convex polygon problem) and the angle results bearing on problem 504.

Source: https://users.renyi.hu/~p_erdos/1960-09.pdf. No notice is printed; the hosting archive's site footer speaks for the site, not the paper (https://users.renyi.hu/~p_erdos/, prints "(C) 2005-2007 All rights reserved. All material on this site is for scientifics purposes only."); the journal has no publisher page or DOI for this edition, so none was consulted, and no Crossref license is recorded; the term is unstated.

Read status: claims checked for the construction and conjecture of Sections 1--2, Theorems 1, 2 and 3, the small values of α(m)\alpha(m) and the conjecture on 2n+12^n+1 points in nn-space, read clause by clause on the page images of the print; the proofs of Theorems 1, 2 and 3 and the construction followed. Szekeres's 1941 results (i) and (ii) are cited, not read. Nothing here is independently reviewed. Result pages: construction_section_2, theorem_1, theorem_2, theorem_3, values_p54 and conjecture_p54.

Bears on. #107: the Section 2 construction (pp. 54--57), with its shift constant corrected as the page records, gives f(n)≥2n−2+1f(n)\ge2^{n-2}+1 in the problem's notation, the lower half of the conjectured equality, which the paper conjectures (p. 53) and does not prove. #504: Theorem 1 (p. 54) with Szekeres's configurations determines α2n=(1−1/n)π\alpha_{2^n}=(1-1/n)\pi for n≥3n\ge3, Theorem 3 (p. 61) determines α2n−1=(1−1/n)π\alpha_{2^n-1}=(1-1/n)\pi for n≥3n\ge3 (printed for n≥2n\ge2, false at n=2n=2), Theorem 2 (p. 60) is a lower bound for other mm between consecutive powers of two, and p. 54 asserts the values for 3≤m≤83\le m\le8; the paper determines no other value. #224: the conjecture on p. 54 is the problem's statement, which the paper records as Erdős's and, in a footnote added in proof, reports proved by Danzer and Grünbaum; the paper proves nothing on it.

Results.

  • Section 2 construction (pp. 54--57): for each nn a set of 2n−22^{n-2} points in the plane (Section 2 assumes no three points collinear) containing no convex nn-gon, so 2n−2≤f0(n)≤(2n−4n−2)2^{n-2}\le f_0(n)\le\binom{2n-4}{n-2}; the authors conjecture f0(n)=2n−2f_0(n)=2^{n-2} for every n≥3n\ge3 (p. 53). The section also constructs a set of (k+l−2k−1)\binom{k+l-2}{k-1} points with no concave sequence of length kk and no convex sequence of length ll (p. 55); as printed, its shift constant is too small in the smallest cases, which the page records.
  • Theorem 1 (p. 54; Theorem 1*, p. 59): every plane configuration of 2n2^n points (n≥3n\ge3) contains an angle greater than (1−1/n)π(1-1/n)\pi; with Szekeres's configurations this gives α(2n)=(1−1/n)π\alpha(2^n)=(1-1/n)\pi and the strict inequality (3) for m=2nm=2^n.
  • Theorem 2 (p. 60): every plane configuration of N=2n−kN=2^n-k points (0<k<2n−10<k<2^{n-1}) contains an angle at least (1−1/n−k/2N)π(1-1/n-k/2N)\pi; no range for nn is printed.
  • Theorem 3 (p. 61, note added in proof): printed as every plane configuration of 2n−12^n-1 points (n≥2n\ge2) containing an angle not less than (1−1/n)π(1-1/n)\pi, so α(2n−1)=(1−1/n)π\alpha(2^n-1)=(1-1/n)\pi, whether strictly or not left undecided. The printed range fails at n=2n=2 (an equilateral triangle has no angle of at least π/2\pi/2, and the paper gives α(3)=π/3\alpha(3)=\pi/3), and the printed proof needs a point inside the convex hull, which exists for n≥3n\ge3.
  • Small values (p. 54), asserted as easy to verify: α(3)=π/3\alpha(3)=\pi/3, α(4)=π/2\alpha(4)=\pi/2, α(5)=3π/5\alpha(5)=3\pi/5 and α(6)=α(7)=α(8)=2π/3\alpha(6)=\alpha(7)=\alpha(8)=2\pi/3, with the regular mm-gon extremal for 3≤m≤63\le m\le6 and the strict inequality holding for m=7,8m=7,8.
  • Conjecture (p. 54): Erdős's conjecture that 2n+12^n+1 points in nn-space determine an angle greater than π/2\pi/2, with its proof by Danzer and Grünbaum reported in a footnote added in proof.

No file of this source is held: no license on record permits its redistribution, and the card cites the edition it names above.