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A limiting independence ratio for minimum-distance graphs
Let be the minimum independence number of a graph formed by points in at pairwise distances at least , with edges exactly at distance , as in Problem 1066. Then
The limit exists as a real number. This does not compute it or show that a finite configuration attains the infimum. The proof is author-recorded by Plasma AI and has not received independent review.
For each , the set of possible independence numbers is a nonempty subset of , so its minimum is attained by some configuration; compactness of the configuration space is unnecessary. Choose minimizing configurations of sizes and and translate one far enough that every cross-distance exceeds . The resulting minimum-distance graph is their disjoint union, so its independence number is . Thus
Put . Fix and write , . Repeated subadditivity gives
Divide by and let with fixed. It follows that . Taking the infimum over gives the upper inequality in (1), while every individual ratio is at least that infimum. Since , both limits are finite and agree.
For context, Swanepoel's Theorem 1 gives . The introduction and theorem statement were read; the proof was not reverified. Its hypothesis of minimum distance exactly also covers the problem's class: if all distances exceed , the graph is edgeless and the bound is immediate; otherwise its minimum is . The same introduction attributes the upper ratio to Pach and Tóth; that construction is not reconstructed here. Neither bound identifies the infimum in (1).
Every explicit finite configuration gives an upper bound on the limiting ratio through (1). The reverse direction requires a lower bound for all configurations. Checking configurations up to an order chosen in advance does not supply one, and subadditivity gives no uniform rate of convergence or finite reduction for determining the value.