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Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

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Exact limits of order and primitive-kernel reductions


None of these configurations violates the target cardinality bound. They rule out the specific local reductions stated below.

Neither Euclidean replacement of a fixed pair need preserve dimension

Let P={1,4,5,6,7}P=\{1,4,5,6,7\}, which has dimension three. Its four-subsets are covered by

1+4=5,1+5=6,1+6=7,4+7=5+6,1+4=5,\quad1+5=6,\quad1+6=7,\quad4+7=5+6,

and {1,4,6}\{1,4,6\} is dissociated. Replacing either 44 or 11 by their difference 33 produces a set containing the dissociated four-set {3,5,6,7}\{3,5,6,7\}, whose subset sums are already listed in the convex obstruction note.

This refutes a dimension-preserving replacement guarantee for an arbitrarily prescribed pair. It does not refute the existence of some other usable pair or a more global compression.

No one-unit suffix-gap closure need preserve dimension

Let P={2,3,4,5,9}P=\{2,3,4,5,9\}. Every four-subset is dependent, using

2+3=5,4+5=9,2+3+4=9,2+3=5,\quad4+5=9,\quad2+3+4=9,

while {2,3,4}\{2,3,4\} is dissociated. Thus d(P)=3d(P)=3.

Consider decreasing an entire suffix by one while retaining positive distinct entries. The only possibilities are

{1,2,3,4,8},{2,3,4,5,8}.\{1,2,3,4,8\},\qquad \{2,3,4,5,8\}.

They contain the dissociated sets {1,2,4,8}\{1,2,4,8\} and {2,3,4,8}\{2,3,4,8\}, respectively. For the latter the subset sums are

0,2,3,4,5,6,7,8,9,10,11,12,13,14,15,17.0,2,3,4,5,6,7,8,9,10,11,12,13,14,15,17.

Hence even the existence of a dimension-preserving unit suffix compression is false.

Odd ordered splitting fails in the primitive rank-one regime

Put

O={1,7,11,13,15,17,19,21,25,31}.O=\{1,7,11,13,15,17,19,21,25,31\}.

Its lower five and upper five points are both dissociated, but d(O)=5d(O)=5. For either five-set, its pair sums are distinct and its three smallest points sum to more than its largest; parity rules out other relations.

Here is the exact finite certificate for the upper bound, run during the exploration. Among the 210 six-subsets, just one has every four-subset dissociated:

E={1,17,19,21,25,31}.E=\{1,17,19,21,25,31\}.

It has the relation 1+25+31=17+19+211+25+31=17+19+21. The following self-contained checker verifies the finite coverage assertion and both lower bounds.

python
from itertools import combinations

O = (1, 7, 11, 13, 15, 17, 19, 21, 25, 31)

def dissociated(D):
    S = {0}
    for a in D:
        T = {s + a for s in S}
        if S & T:
            return False
        S |= T
    return True

assert dissociated(O[:5]) and dissociated(O[5:])
exceptions = [
    C for C in combinations(O, 6)
    if all(dissociated(Q) for Q in combinations(C, 4))
]
assert exceptions == [(1, 17, 19, 21, 25, 31)]
assert 1 + 25 + 31 == 17 + 19 + 21

Every four-subset has gcd one: no prime divides more than two entries of OO. Moreover, its short ternary relations have a primitive, binary-connected rank-one presentation. Nine such relations are

1+17=7+11,1+7+11=19,1+19=7+13,1+7+13=21,1+21=7+15,1+7+17=25,1+31=7+25,1+11+13=25,7+21=11+17.\begin{gathered} 1+17=7+11,\quad1+7+11=19,\quad1+19=7+13,\\ 1+7+13=21,\quad1+21=7+15,\quad1+7+17=25,\\ 1+31=7+25,\quad1+11+13=25,\quad7+21=11+17. \end{gathered}

To verify primitivity without a determinant computation, denote the ten generators by a,b,c,d,e,f,g,h,i,ja,b,c,d,e,f,g,h,i,j in displayed order. The first seven relations give

f=b+c−a,g=a+b+c,d=2a+c,h=3a+b+c,e=4a+c,i=2b+c,j=3b+c−a.f=b+c-a,\quad g=a+b+c,\quad d=2a+c,\quad h=3a+b+c,\quad e=4a+c,\quad i=2b+c,\quad j=3b+c-a.

The last two then give c=2b−3ac=2b-3a and c=b+4ac=b+4a, hence b=7ab=7a, c=11ac=11a, and all ten generators are the specified integer multiples of aa. Each elimination has unit coefficient. The quotient lattice is therefore exactly Z\mathbb Z, with no torsion, and reduction modulo two has relation rank nine.

Thus oddness, a primitive short presentation, and primitive nearly maximum subsets do not repair ordered splitting. A successful argument in the remaining rank-one regime must also exploit the cardinality threshold; this ten-point example is far below it.

Full compression to an initial interval also fails

This is stronger than the local suffix-gap obstruction. Let

P={1,2,3,4,5,6,7,8,9,10,12,13,15}.P=\{1,2,3,4,5,6,7,8,9,10,12,13,15\}.

Then d(P)=4d(P)=4, whereas d({1,…,13})≥5d(\{1,\ldots,13\})\ge5. The four-set {1,2,4,8}⊂P\{1,2,4,8\}\subset P is dissociated. The absence of a dissociated five-subset is certified by the following exact finite check over all (135)=1287\binom{13}{5}=1287 five-subsets. The final assertion verifies a five-subset of the compressed interval.

python
from itertools import combinations

P = (1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 12, 13, 15)

def dissociated(D):
    sums = {0}
    for a in D:
        translated = {s + a for s in sums}
        if sums & translated:
            return False
        sums |= translated
    return True

assert dissociated((1, 2, 4, 8))
assert all(not dissociated(D) for D in combinations(P, 5))
assert dissociated((6, 9, 11, 12, 13))

The witness was suggested by an online research note on small values of Problem 963; the three assertions above were checked by the author from the definition and are author-recorded. No other claim in that note is needed here.

Thus initial intervals are not universal minimizers of dissociation dimension, even among positive integer sets. This rules out full one-dimensional compression as a general dimension-nonincreasing operation. It is not a counterexample to the requested bound: 13<2413<2^4.