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Chromatic support bridge


Proved bounds, not a contradiction. Use the least-budget minimal-ratio core, with

∣H∣=ar+1,α(H)=a,δ(H)≥r,S:=∑v(dH(v)−r)≤rh,h=r−a,|H|=ar+1,\quad \alpha(H)=a,\quad \delta(H)\ge r, \quad S:=\sum_v(d_H(v)-r)\le rh,\quad h=r-a,

where r≥12r\ge12 and a≤r−5a\le r-5. Every nonempty independent set obeys

∣NH[I]∣≥r∣I∣+1.(1)|N_H[I]|\ge r|I|+1. \tag{1}

Choose an inclusion-minimal vertex set UU such that J=H[U]J=H[U] is not rr-colorable, and put m=∣U∣m=|U|, b=α(J)b=\alpha(J). Such a set exists because ∣H∣>rα(H)|H|>r\alpha(H). Then

b≤min⁡{a,h+1},(r−2)m≤r2(h+1)−3r−2.(2)\boxed{b\le\min\{a,h+1\},\qquad (r-2)m\le r^2(h+1)-3r-2.} \tag{2}

If J=HJ=H, the stronger conclusion is

a≤⌊(r+1)/2⌋.(3)\boxed{a\le\lfloor(r+1)/2\rfloor.} \tag{3}

The distinction between vertex-critical JJ and an independence-critical core is essential throughout.

A bridge using the supplied density theorem

Let c=eH(U,V(H)∖U)c=e_H(U,V(H)\setminus U). Nonnegativity of degree surplus gives

S≥2e(J)+c−rm.(4)S\ge2e(J)+c-rm. \tag{4}

For a maximum independent bb-set II of JJ, inducedness makes II independent in HH. By (1),

c≥∣NH[I]∖U∣≥rb+1−m.(5)c\ge |N_H[I]\setminus U|\ge rb+1-m. \tag{5}

An edge-minimal non-rr-colorable subgraph of JJ must be spanning: otherwise its vertex support contradicts the choice of UU. It is therefore (r+1)(r+1)-critical in the usual subgraph sense. The supplied Kostochka--Yancey source, Theorem 3 and equation (9) gives

2e(J)−rm≥(1−2/r)m−r+1+2/r.(6)2e(J)-rm\ge(1-2/r)m-r+1+2/r. \tag{6}

The digest was read before checking that passage. Combining (4)--(6) with S≤rhS\le rh proves

rb≤r(h+1)−2−2/r+2m/r,(7)rb\le r(h+1)-2-2/r+2m/r, \tag{7}

and hence b≤h+2b\le h+2. This already supplies independence control on the chromatic support, rather than merely a scalar order estimate. Here bb is the independence number of the induced graph JJ, not of its edge-pruned critical subgraph.

The non-Ore strengthening

The previously proved Ore-cap exclusion says that every (r+1)(r+1)-Ore graph satisfying the (r+1)(r+1)-set cap has at least r2+1r^2+1 vertices. It applies to the spanning critical subgraph just extracted, since edge deletion preserves the upper caps. That subgraph has at most ar+1<r2+1ar+1<r^2+1 vertices, so is non-Ore.

An additional primary source gives a useful strict improvement: Kostochka and Yancey, A Brooks-type result for sparse critical graphs, Theorem 6, printed page 4. For a non-Ore kk-critical graph, k≥6k\ge6, it states

2e≥(k+1)(k−2)m−(k2−5k+2)k−1.2e\ge\frac{(k+1)(k-2)m-(k^2-5k+2)}{k-1}.

Its statement was checked in the primary text; its full proof was not independently rederived. Substituting k=r+1k=r+1 strengthens (6) to

2e(J)−rm≥(1−2/r)m−r+3+2/r.(8)2e(J)-rm\ge(1-2/r)m-r+3+2/r. \tag{8}

Using c≥0c\ge0 in (4) gives the order bound in (2). Using (5) instead gives

rb≤r(h+1)−4−2/r+2m/r.(9)\boxed{rb\le r(h+1)-4-2/r+2m/r.} \tag{9}

To obtain b≤h+1b\le h+1, first suppose h+1<r/2h+1<r/2. The order bound in (2) implies

m<r2/2+2r+1,m<r^2/2+2r+1,

because substituting this latter expression into its left side exceeds r3/2−3r−2r^3/2-3r-2 by r2r^2. Equation (9) and integrality then give the claim. If h+1≥r/2h+1\ge r/2, the claim already follows from b≤ab\le a unless rr is even and a=r/2+1=h+2a=r/2+1=h+2. In that sole case m≤ar+1=r2/2+r+1<r2/2+2r+1m\le ar+1=r^2/2+r+1<r^2/2+2r+1, so (9) again suffices. This proves (2).

If J=HJ=H, substitute b=ab=a, m=ar+1m=ar+1 into (9). It gives

2a(r−1)≤r2+r−4,a≤(r+2)/2−1/(r−1),2a(r-1)\le r^2+r-4, \qquad a\le(r+2)/2-1/(r-1),

and hence (3).

Actual color coupling strengthens the support cap

The core still carries an actual coloring in which every foreign color has independence at most rr. If a foreign color graph on UU could partition into rr cliques, those same parts would be independent in JJ, contradicting χ(J)>r\chi(J)>r. Thus the elementary nonpartite Turan gap applies to each foreign color. For m≥2r+1m\ge2r+1, it gives

e(J)≤Dr(m)−(r−1)(⌊m/r⌋−1).(10)\boxed{e(J)\le D_r(m)-(r-1)(\lfloor m/r\rfloor-1).} \tag{10}

Indeed every foreign color has at least pr(m)+⌊m/r⌋−1p_r(m)+\lfloor m/r\rfloor-1 edges, and their edge sets partition the complement of JJ on UU. This is an upper bound for this chromatic support, not an inherited bound on every induced subgraph.

What remains missing

Even with (2), JJ need not have m>rbm>rb. The hereditary span theorem therefore cannot be applied merely because b≤h+1b\le h+1 is smaller than aa. No theorem has been established saying that every capped graph of small independence number is rr-colorable below its capacity rbrb. Likewise (3) applies only if the entire core is vertex-critical; the core has not been proved to have that property.

The expansion/cut bridge, the substitution in the supplied density theorem, and the non-Ore strengthening against the later primary theorem were checked by the author; the argument is author-recorded. These estimates do not establish an unrestricted infinite family of positive cases.