Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
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Chromatic support bridge
Proved bounds, not a contradiction. Use the least-budget minimal-ratio core, with
where and . Every nonempty independent set obeys
Choose an inclusion-minimal vertex set such that is not -colorable, and put , . Such a set exists because . Then
If , the stronger conclusion is
The distinction between vertex-critical and an independence-critical core is essential throughout.
A bridge using the supplied density theorem
Let . Nonnegativity of degree surplus gives
For a maximum independent -set of , inducedness makes independent in . By (1),
An edge-minimal non--colorable subgraph of must be spanning: otherwise its vertex support contradicts the choice of . It is therefore -critical in the usual subgraph sense. The supplied Kostochka--Yancey source, Theorem 3 and equation (9) gives
The digest was read before checking that passage. Combining (4)--(6) with proves
and hence . This already supplies independence control on the chromatic support, rather than merely a scalar order estimate. Here is the independence number of the induced graph , not of its edge-pruned critical subgraph.
The non-Ore strengthening
The previously proved Ore-cap exclusion says that every -Ore graph satisfying the -set cap has at least vertices. It applies to the spanning critical subgraph just extracted, since edge deletion preserves the upper caps. That subgraph has at most vertices, so is non-Ore.
An additional primary source gives a useful strict improvement: Kostochka and Yancey, A Brooks-type result for sparse critical graphs, Theorem 6, printed page 4. For a non-Ore -critical graph, , it states
Its statement was checked in the primary text; its full proof was not independently rederived. Substituting strengthens (6) to
Using in (4) gives the order bound in (2). Using (5) instead gives
To obtain , first suppose . The order bound in (2) implies
because substituting this latter expression into its left side exceeds by . Equation (9) and integrality then give the claim. If , the claim already follows from unless is even and . In that sole case , so (9) again suffices. This proves (2).
If , substitute , into (9). It gives
and hence (3).
Actual color coupling strengthens the support cap
The core still carries an actual coloring in which every foreign color has independence at most . If a foreign color graph on could partition into cliques, those same parts would be independent in , contradicting . Thus the elementary nonpartite Turan gap applies to each foreign color. For , it gives
Indeed every foreign color has at least edges, and their edge sets partition the complement of on . This is an upper bound for this chromatic support, not an inherited bound on every induced subgraph.
What remains missing
Even with (2), need not have . The hereditary span theorem therefore cannot be applied merely because is smaller than . No theorem has been established saying that every capped graph of small independence number is -colorable below its capacity . Likewise (3) applies only if the entire core is vertex-critical; the core has not been proved to have that property.
The expansion/cut bridge, the substitution in the supplied density theorem, and the non-Ore strengthening against the later primary theorem were checked by the author; the argument is author-recorded. These estimates do not establish an unrestricted infinite family of positive cases.