Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
Updated
Subject and independence
Role. The reviewer is an independent reviewer in a fresh context, given only the assignment. The reviewer took no part in writing the connections page, its Tools section, the reconstruction pages or the problem page, had read none of them before this review, and holds no stake in the outcome. The charge is refutation of the section's author-recorded mathematics.
Subject. Page wiki/research/erdos_1171/connections.md as it stood on
2026-09-28T13:50:48Z, section
"Problem 601: the infinite-path target", lines 620-639: the H2 heading at
line 620 through the Outcome paragraph at line 639, the next H2 heading being
at line 641. The section names no lead page and files no lead.
Reading. In full, unless a depth is stated:
- the section;
- the page's Scope paragraph and Tools section (lines 18-123), as inputs whose proofs are another reviewer's subject; the interfaces of (T1) and (T3) were confirmed at each use, and the proof of (T4) was re-derived for graph targets, since (T3) is stated as its constant case;
- the Lemma 2.1 reconstruction and the Theorem 3.1 reconstruction, as premises at their reviewed standing; the section's inputs use only the Definitions and facts 1 and 2 of the lemma page;
- the statement block of Problem 601 (lines 17-37 of the page: the statement, status, prize and tags, source, references and formalization lines) and nothing else of that page;
- the library tree (folder names only) and a file-name search for Larson and [La90], to check the words "not held"; and lines 824-836 of the held conversion of Komjáth (2025), that survey's only mention of an infinite path, to check the words "not in the corpus";
- the named guidance:
docs/verification.md("Whole-claim report", "Audit checklist", "Grading and claim standing"),docs/approach_vetting.md,docs/evidence.md("Source fidelity") anddocs/math_authoring.md.
Exposures. No excluded content reached the reviewer: no folder index, no evidence folder, no review or grade, no assessment, known-results or standing text, no web search. Two reads fall outside the items the assignment names and are disclosed here. The page's Outcomes section (lines 678 to the end) was read to check that its Problem 601 row agrees with the section; it lists the author's summaries of the other sections and carries no review or standing text. The Komjáth lines above were read although the section invokes no theorem of that source.
Restatement
Conventions. Ordinals are von Neumann ordinals and is the set of two-element subsets of (lemma page, Definitions). A coloring of with the colors is a function . In the relation of (T1), a target that is a graph is met by a copy: a graph with vertex set inside and edge set inside , isomorphic to , all of whose edges have color . is the one-way infinite path: pairwise distinct vertices with the edges for . A graph contains a path when the path is a subgraph, not necessarily induced. The subscript is omitted for two colors.
- S1 (target formulation). Let be an ordinal. The relation says: every has a set with and on , or a copy of all of whose edges have color . The section asserts that this relation holds exactly when every graph with vertex set has an infinite path or an independent set whose vertex set has order type , the property the catalog asks about for limit ordinals , and that the catalog status is open.
- S2 (finite-union transfer). Let be an ordinal with and let be finite. For all graphs with vertex set such that no contains a one-way infinite path, the graph (vertex set , edge set the union of the edge sets) has an independent set with . The section's proof: color a pair by the least with the pair in , and by when there is none, and apply (T3) with .
- S3 (non-triviality). There are two graphs on an infinite ordinal, each containing no infinite path, whose union contains one; so S2 is not a restatement of the property.
- S4 (obstruction). S2 gives no information about which ordinals satisfy , which is the whole question.
- S5 (catalog and holding sentence). On the catalog page Problem 601 is open; its reference [La90] is Larson's 1990 paper on Martin's axiom and ordinal graphs, which carries the Martin's-axiom side of the problem; that paper is not held, and that side of the problem is not in the corpus.
- S6 (outcome). The mechanism transfers to Problem 601 as S2, without bearing on the question; no lead.
Checklist
- Quantifiers and scope. Pass. S2 quantifies over all ordinals with the property, all finite and all -tuples of graphs; no almost-all, eventual or exceptional-set clause appears. The catalog's restriction to limit ordinals is carried in S1 and is not needed for S2. The one loose quantifier is "for every finite ", which includes , an instance (T3) does not cover; it holds trivially (F1).
- Circularity. Pass. S2 takes the property as its hypothesis and says so; S4 refuses to draw any conclusion about which have it. Nothing equivalent to the target is assumed and then presented as progress.
- Model and convention changes. Pass. The passage from graphs on to two-colorings of and back is re-derived under Weakest step 1, including the reading of "infinite path" and the subgraph reading of a copy. The passage from the ordinal to a subset of type is (T1) transport, re-derived for graph targets under Weakest step 2.
- Finite and statistical overreach. Inapplicable: no finite case, average or sample is used.
- Uniformity. Inapplicable: no constant or error term appears; the only parameter is , and the number of colors, , depends on it explicitly.
- Extremal conclusions. Inapplicable: no infimum, supremum or sharpness claim is made.
- Consequences and composition. Pass. The consumed clause is (T3) at the constant chain with graph targets; its hypotheses, for each with a graph, are supplied by the property through S1. Each "so" was checked on its own: "a color- infinite path is a path of " (the copy's edges have color , so each lies in ); "independent in every " (no pair of the color- set lies in any ); "the union of two graphs without infinite paths can contain one" (witness under S3).
- Computation. Inapplicable: none is used.
- Reproduction. Inapplicable: the section states no rerun instruction and no coverage claim.
- Source and verdict fidelity. Pass within the read set. The paraphrase of the problem matches the statement block in substance (limit ordinals; a graph with vertex set ; an infinite path or an independent set on a set of vertices of order type ). The status line reads "Open". The reference [La90] is Larson, Jean A., Martin's axiom and ordinal graphs: large independent sets or infinite paths, Ann. Pure Appl. Logic (1990), so "the Martin's-axiom side" matches the title. The library has no folder for it, and the held Komjáth survey lists the form of the question (its Problem 66) with no Martin's-axiom result, so "not held" and "not in the corpus" stand. What [La90] proves is not assessed, since the paper is not held.
Weakest steps
1. The bridge between graphs and colorings (S1). For a graph put if and otherwise; every equals for exactly one , namely . A set of type with on is an independent set of whose vertex set has order type , and conversely. A copy of all of whose edges have color under is a subgraph of isomorphic to , that is, a one-way infinite path in , and conversely. It remains to match "has an infinite path" with "has a one-way infinite path": a one-way infinite path is an infinite path, and an infinite path, one-way or two-way, contains a one-way infinite path (from any vertex, follow one direction). So holds exactly when every graph on has an infinite path or an independent set of order type . This bridge is what lets the section apply tools stated for colorings to a problem stated for graphs.
2. (T3) with graph targets (S2). Let be the section's coloring and . Claim: has a set of type homogeneous in color or, for some , a copy of all of whose edges have color . Induction on . For this is read through the bridge. For let be with the color merged into , so exactly when . The case gives either a copy of whose edges have -color , hence -color , or a set of type with for all . In the second case let be the order isomorphism and color by if and otherwise. The hypothesis gives of type with on , whence has type and on ; or a copy of whose edges have -color , whose image under the bijection is a copy of inside whose edges have -color . This is the claim, and it is (T4) at the constant chain with the last color merged. Now a copy of whose edges have color has every edge in , so contains a one-way infinite path, which the hypothesis of S2 excludes; hence the color- set of type exists, and no pair of lies in any , so is independent in .
3. The obstruction (S4). For a fixed write for the conclusion of S2 at . S2 says that the property implies for every , and is the property itself: a single graph without an infinite path has an independent set of type . So the family of union statements is equivalent to the property, and what S2 says about a given never exceeds the property for that . The section's sentence that the transfer "says nothing about which have the property" is therefore exact, and the transfer could only be combined with independent knowledge of the property.
Strongest attack
- S1. Three readings were tried against the bridge. Reading "infinite path" as a two-way infinite path changes nothing, since a two-way infinite path contains a one-way one and a one-way one is an infinite path. Reading it as an induced path would be a different problem; the catalog statement says "have an infinite path", the standard subgraph containment, (T1) defines a copy as a subgraph, and the section's words "as a subgraph" fix the reading it uses. Reading the (T1) phrase "all of whose pairs have color " as all pairs of the copy's vertex set would turn the color- alternative into an infinite clique and break the equivalence; (T1) defines a copy of a graph as a subgraph, so the pairs are its edges, and the section's step "a color- infinite path is a path of " uses exactly that reading. The attack failed.
- S2. A counterexample was sought: an with the property and graphs without infinite paths whose union has no independent set of type . Weakest step 2 shows none exists. The concrete attempt , which has the property by Ramsey's theorem (an infinite clique contains an infinite path), with the two matchings of S3 fails: the union, the path , has the even numbers as an independent set of type . The step from a color- copy of to a path of was checked against the "least " rule: color means the pair lies in and in no with , so the copy is a subgraph of . The only gap found is the instance , outside (T3) and trivially true (F1). The attack failed.
- S3. Witness, on any infinite ordinal : with the edges and with the edges for , all other vertices isolated. Each has maximum degree , so each of its paths has at most one edge; their union contains the one-way infinite path . The attack, that no such pair exists, failed.
- S4. It was asked whether S2 could yield information about a new ordinal, for instance by transferring the property from to a larger ordinal or by producing a negative instance. Weakest step 3 shows the family of union statements is equivalent to the property, so any such derivation needs an input about the property itself. The obstruction claims only that this transfer says nothing about which have the property; it does not claim that no other use of the mechanism exists, and it was not read as such. The attack failed.
- S5. Checked against the statement block: status "Open"; reference [La90] as quoted under Source and verdict fidelity; no library folder for the paper; the held Komjáth survey records the form of the question without a Martin's-axiom result. The attack, that the words misdescribe the page or the library, failed within the read set.
- S6. Not a mathematical claim; it is consistent with S2 and S4 and with the Problem 601 row of the page's Outcomes section.
Premises
- (T1) Transport, Tools section of the page, held, read in full. Interface: the relation with order-type and graph targets, copies of graphs being subgraphs, transported to any set of type by an order isomorphism. Confirmed at its use inside (T3) for the graph target ; the transport of a copy of needs only a bijection.
- (T2) Restriction and weakening, Tools section: not used by the section.
- (T3) The induction with general targets and (T4) Descent lemma, Tools section, held, read in full; (T3) is the constant case of (T4), which assumes . Interface: from for to with color carrying . The proof of (T4) is another reviewer's subject; it was re-derived here for graph targets at the constant chain (Weakest step 2).
- (T5) Witness extraction, Tools section: not used by the section.
- Lemma 2.1 reconstruction, held, read in full, taken as established at its reviewed standing. Used through its Definitions (von Neumann ordinals, , colorings, homogeneous sets, order types) and facts 1 (transport) and 2 (relabeling), on which (T1) and (T4) rest.
- Theorem 3.1 reconstruction, held, read in full, taken as established at its reviewed standing; not used by the section.
- Problem 601, statement block (lines 17-37) read; the statement, the status line and the reference [La90] are the facts consumed.
- Larson (1990), [La90]: not held; not read; only its bibliographic entry on the problem page was seen. Its content is not assessed.
- Komjáth (2025), held; lines 824-836 of the conversion read, to test the words "not in the corpus".
- No local claim card is consumed. No axiom beyond ZFC enters: S2 is a ZFC deduction from the property of . No batch acceptance order applies.
Findings
- F1 (note). Location: line 628, "then for every finite ". Defect: (T3) is the constant case of (T4), which assumes , so the cited tool does not cover the instance . Witness: , where the union of no graphs is the edgeless graph on and itself is an independent set of type , so the instance holds trivially and nothing false is asserted. Proposed replacement: "then for every finite ".
- F2 (note). Location: lines 634-635, "but it says nothing about which have the property, which is the whole question". Defect: none; the sentence is exact but gives no reason. The reason is that the instance of the transfer is the property itself, so the family of union statements is equivalent to the property (Weakest step 3). Proposed addition after "property": "(the instance is the property itself, so the union statements are equivalent to it)".
Verdict
- S1 (target formulation): refutation-failed.
- S2 (finite-union transfer): refutation-failed, with the instance noted as trivially true and outside the cited tool (F1).
- S3 (non-triviality): refutation-failed; the witness is retained above.
- S4 (obstruction): refutation-failed; the transfer is equivalent to the property, so it decides no instance.
- S5 (catalog and holding sentence): refutation-failed within the read set.
- S6 (outcome): not a mathematical claim; consistent with S2 and S4.
Limitations. The paper [La90] is not held and was not read; the review takes no position on what it proves beyond what its title and the section's words say. The proofs of the Tools section are another reviewer's subject; this review confirmed the interfaces the section uses and re-derived (T4) at the constant chain for graph targets, not the general chain. The reconstruction pages were taken as established at their reviewed standing. No lead page exists for this section. Nothing in the section rests on a computation or on a source theorem, so no computation was rerun and no source PDF was consulted beyond the Komjáth lines named above.
This focused review assigns no tier and changes no status.