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Problem 302

../

claims/: The 5 claim pages of Problem 302, one per claimant's result; the problem's standing derives from them.


Statement. Let f(N)f(N) be the size of the largest A⊆{1,…,N}A\subseteq \{1,\ldots,N\} such that there are no solutions to

1a=1b+1c\frac{1}{a}= \frac{1}{b}+\frac{1}{c}

with distinct a,b,c∈Aa,b,c\in A?

Estimate f(N)f(N). In particular, is f(N)=(12+o(1))Nf(N)=(\tfrac{1}{2}+o(1))N?

Formulation. The site's wording on 2026-09-17 (the page shows no last-edited date). The forbidden relation is the two-term one with a,b,ca,b,c distinct elements of AA; since 1a=1b+1c\frac1a=\frac1b+\frac1c forces a<ba<b and a<ca<c, distinctness only excludes b=cb=c, that is, the pairs {n,2n}\{n,2n\}. The all-length relation is Problem 301 (f301(N)≤f302(N)f_{301}(N)\le f_{302}(N)), and the coloring version is Problem 303. f(N)f(N) is OEIS A390395 (1,2,3,4,5,5,6,…1,2,3,4,5,5,6,\ldots, to N=731N=731). The statement asks for an estimate and whether f(N)=(1/2+o(1))Nf(N)=(1/2+o(1))N.

Status. Open: the site's label is OPEN (no last-edited date shown;), and the site marks the problem as not resolvable by a finite computation. The standing derived from the claim pages is open, claim none: five pending partial claims, Cambie's construction of density 5/8 and van Doorn's upper bound 9/10, both recorded from the site's commentary, Schuh's 373/420 and Khanukov's two-sided bounds from the proof-claim tab, and Kitamura's Lean upper bound of about 0.8462 from the discussion thread, none of which would settle the estimation question. The bounds supported by sources read here are (5/8+o(1))N≤f(N)≤(25/28+o(1))N(5/8+o(1))N\le f(N)\le(25/28+o(1))N: the upper bound comes from the site's 25/2825/28 argument for Problem 301 (elementary; its counting facts checked on that problem's page), which uses only two-term relations and sharpens van Doorn's Theorem 2, f(N)<9N/10+(log⁡N)3+1f(N)<9N/10+(\log N)^3+1 (an undated GitHub note of 2025, unrefereed; statement checked, proof read for structure); the lower bound is Cambie's construction in the site's commentary (elementary, checked here). Since 5/8>1/25/8>1/2, the site's particular guess f(N)=(1/2+o(1))Nf(N)=(1/2+o(1))N fails; that negative answer is Cambie's partial claim, pending because the site's commentary credits it while the site's label is OPEN, which it keeps for the estimation question. No proof, disproof or accepted determination of the asymptotic constant was found in the search whose scope the Current assessment records.

Source. erdosproblems.com/302, accessed 2026-09-17: the problem page (OPEN, with the site's note that no finite computation can resolve the problem; source keys [ErGr80] and [BrRo91]; no last-edited date shown), its discussion thread (two comments, of 5 July and 25 September 2026, as of 2026-10-07) and its proof-claim tab with two partial claims (20 July and 13 September 2026). The site thanks Stijn Cambie, Zachary Hunter, Mehtaab Sawhney and Wouter van Doorn. Cite as: T. F. Bloom, Erdős Problem #302, https://www.erdosproblems.com/302, accessed 2026-09-17.

References.

  • [ErGr80] Erdős, P. and Graham, R. L., Old and new problems and results in combinatorial number theory. Monographies de L'Enseignement Mathématique 28, Université de Genève (1980), p. 37 (the site gives no page). Library home: erdos_1980_old_new_problems_results_combinatorial_number_theory.
  • [BrRo91] Brown, Tom C. and Rödl, Vojtěch, Monochromatic solutions to equations with unit fractions. Bull. Austral. Math. Soc. 43 (1991), no. 3, 387--392, DOI 10.1017/S0004972700029221. Corollary 2.3 proves the coloring version (Problem 303) and gives no density bound here. Library home: brown_1991_monochromatic_solutions_equations_unit_fractions.
  • [vD25] van Doorn, W., Two-colouring and density lead to many solutions of 1/x+1/y=1/z1/x+1/y=1/z. Undated four-page note in the author's GitHub repository Woett/Mathematical-shorts (PDF created 31 July 2025; committed 11 August 2025 per the GitHub API); the note the site's commentary links and the formal-conjectures file cites as [va25]; unrefereed. Theorem 2, p. 3. Library home: doorn_2025_two_coloring_density_solutions_unit_fraction_equation.
  • [OEIS] Raza, H., Sequence A390395, The On-Line Encyclopedia of Integer Sequences (2025; entry last modified 30 November 2025, server time): f(n)f(n) for n≤731n\le731 (b-file by C. W. Wu and S. Kesarwani); read.
  • The site's commentary attributes the 5/85/8 construction and the non-distinct 2/32/3 remark to Stijn Cambie; neither has a written source beyond the site.

Formalization. The file ErdosProblems/302.lean of formal-conjectures at the linked commit (main) defines the extremal function through NoUnitFractionTriple and IsMaxNoTripleCard and declares erdos_302.parts.i (the limit of f(N)/Nf(N)/N, answer(sorry), category research open), erdos_302.parts.ii (that f(N)/Nf(N)/N does not tend to 1/21/2, category research solved, with the docstring "This is false: it is contradicted by Cambie's lower bound"), and the variants lower_half, lower_five_eighths and upper_nine_tenths (the last citing [va25]), all with proof sorry. The same file at the commit of 27 September 2026 adds the variant erdos_302.variants.upper_0_8461739827964010, also with proof sorry, with a formal_proof annotation pointing at Kitamura's repository, which is linked on his claim page. The community database (fetched 2026-09-17) lists the statement as formalized, as of its last update of 5 August 2026, and no formal proof. Nothing was built or checked here.

Current assessment

The question (site formulation of 2026-09-17). The statement above; OPEN; no last-edited date shown. The commentary records that the coloring version is Problem 303, solved by Brown and Rödl [BrRo91]; that the odd integers up to NN, or the integers in [N/2,N][N/2,N], give f(N)≥(1/2+o(1))Nf(N)\ge(1/2+o(1))N; that Wouter van Doorn has proved f(N)≤(9/10+o(1))Nf(N)\le(9/10+o(1))N in a linked note; that Stijn Cambie has observed f(N)≥(5/8+o(1))Nf(N)\ge(5/8+o(1))N by taking the odd integers up to N/4N/4 together with the integers in [N/2,N][N/2,N]; and that Cambie has also observed that, once b=cb=c is permitted, a set of size (2/3+o(1))N(2/3+o(1))N contains some pair n,2nn,2n and so a solution. The commentary refers to Problems 301 and 327. The thread has two comments (5 July and 25 September 2026, below) and the proof-claim tab two partial claims (below). The community database lists the problem as open with the statement formalized, as of its last update of 5 August 2026, OEIS A390395, and no formal proof.

Origin. Printed p. 37 of the 1980 monograph, after the Sn∗S_n^* question of Problem 301 and Szemerédi's variant: "In fact, is it true that if S⊆{1,2,…,n}S\subseteq\{1,2,\ldots,n\} with ∣S∣>cn|S|>cn then SS contains tt, xx and yy with 1t=1x+1y\frac1t=\frac1x+\frac1y", followed by "Of course, 1t=1x+1y\frac1t=\frac1x+\frac1y holds if and only if x+y∣xyx+y\mid xy" and the divisibility questions of Problem 327. The book asks for which cc this holds; the site asks whether 12\frac12 is the threshold.

Bounds supported by sources read here. Upper bound: van Doorn's Theorem 2 (p. 3, read clause by clause; claims checked): every S⊆{1,…,n}S\subseteq\{1,\ldots,n\} with ∣S∣≥9n/10+log⁡(n)3+1|S|\ge9n/10+\log(n)^3+1 contains distinct x,y,zx,y,z with 1/x+1/y=1/z1/x+1/y=1/z, so f(N)<9N/10+(log⁡N)3+1f(N)<9N/10+(\log N)^3+1. The proof (pp. 3--4, read for structure) counts disjoint dilates of the triples {2,3,6}\{2,3,6\} and {4,5,20}\{4,5,20\}, each of which a solution-free set must miss in one element. The note is an undated GitHub file of 2025 with no journal, no arXiv version and no independent review found; the site's commentary credits it to van Doorn and links it, and formal-conjectures cites it. Lower bound (site commentary, checked here): A0={a≤N/4:a odd}∪[N/2,N]A_0=\{a\le N/4:a\text{ odd}\}\cup[N/2,N] has 5N/8+O(1)5N/8+O(1) elements and no solution. A solution 1/a=1/b+1/c1/a=1/b+1/c with a<b,ca<b,c satisfies (b−a)(c−a)=a2(b-a)(c-a)=a^2; if a≥N/2a\ge N/2 then (b−a)(c−a)≤(N−a)2≤a2(b-a)(c-a)\le(N-a)^2\le a^2 with equality only for b=c=Nb=c=N, which distinctness excludes; if a≤N/4a\le N/4 is odd then a2a^2 is odd, so b−ab-a and c−ac-a are odd, bb and cc are even and hence lie in [N/2,N][N/2,N], whence b−a,c−a≥N/4≥ab-a,c-a\ge N/4\ge a and (b−a)(c−a)=a2(b-a)(c-a)=a^2 forces b=c=2ab=c=2a, excluded. The trivial bound 1/21/2 of the commentary (odd numbers, or [N/2,N][N/2,N]) follows from the same two observations. The site's 25/2825/28 argument for Problem 301, recorded on its claim page there, transfers: its relations inside D={2,3,4,6,12}D=\{2,3,4,6,12\} include the two-term relations 12=13+16\frac12=\frac13+\frac16, 13=14+112\frac13=\frac14+\frac1{12} and 14=16+112\frac14=\frac16+\frac1{12}, every four-element subset of DD contains one of these three, and {2,3,4,6}\{2,3,4,6\} contains the first, so the same disjoint dilates of density 3/73/7 give f(N)≤(25/28+o(1))Nf(N)\le(25/28+o(1))N here; Khanukov's manuscript (Section 1) calls it the transferable bound for this problem and Schuh's text the previously applicable bound. So 5/8≤lim inf⁡f(N)/N5/8\le\liminf f(N)/N and lim sup⁡f(N)/N≤25/28\limsup f(N)/N\le25/28; the particular guess f(N)=(1/2+o(1))Nf(N)=(1/2+o(1))N is false, as the formal-conjectures file also records, while the estimation question stays open. The non-distinct variant (site commentary, attributed to Cambie): allowing b=cb=c, the pair {n,2n}\{n,2n\} is a solution 1/n=1/2n+1/2n1/n=1/2n+1/2n, so any AA with ∣A∣≥(2/3+o(1))N|A|\ge(2/3+o(1))N, which contains such a pair, has a solution; the constant 2/32/3 is the largest density of a set without a pair {n,2n}\{n,2n\}. It is a variant, not the problem, and was not checked beyond reading.

Claims and forum items. Five claim pages, all pending partial claims: two recorded from the site's commentary, two from the proof-claim tab and one from the discussion thread. The problem lists no parts, so its partial claims derive no standing and the frontmatter is open, claim none.

  • Stijn Cambie's construction: the lower bound 5/85/8 above, recorded from the curator's credit in the commentary, which answers the particular question in the negative; pending, since the site labels the problem OPEN and lists no parts; the page is dated by the earliest archived copy of the site's page that carries the observation (25 March 2025), the site showing no last-edited date.
  • Wouter van Doorn's Theorem 2: the upper bound 9/109/10 above, credited in the commentary; pending for the same reason; dated by the note's GitHub commit.
  • Discussion, account SamKorsky, 21:11 on 5 July 2026: a claimed improvement of Cambie's construction to f(N)≥5N/8+N/(log⁡N)β+o(1)f(N)\ge5N/8+N/(\log N)^{\beta+o(1)} with β=1−(1+log⁡log⁡3)/log⁡3≈0.00415\beta=1-(1+\log\log3)/\log3\approx0.00415, by adjoining to A0A_0 the products mpmp with mm odd and all consecutive divisor ratios of mm at least 22 (a counting result the comment cites for such mm), m≤N1/2/10m\le N^{1/2}/10 and pp prime in (N/(4m),N/(2m))(N/(4m),N/(2m)); not checked and not accepted by the site. A thread comment without a manuscript, so it has no page.
  • Robert Schuh, 20 July 2026: the partial claim filed by the account 15Redstones, naming the systems GPT 5.6 and Kimi 2.6, with no summary and a single link to an unsigned text on a paste site that states f(N)≤(373/420+o(1))N≈0.888Nf(N)\le(373/420+o(1))N\approx0.888N by a tile of powers of 22 and 33; read at statement level, not checked.
  • Dmitry Khanukov, first released 16 August 2026: the partial claim filed on 13 September 2026, naming the systems GPT-6 Astra and GPT-5.6 Sol: a lower bound (5/8+δ)N(5/8+\delta)N for some δ>0\delta>0, obtained by padding the set of Della Pietra's pending Problem 301 claim with the odd integers up to N/4N/4, and an upper bound 140803024/163562355≈0.86085140803024/163562355\approx0.86085 from a finite exact certificate, with Lean 4 formalizations the claimant reports; the repository khanukov/erdos302 is linked at the release's commit. The lower bound depends on the unrefereed Problem 301 manuscript recorded on its claim page.
  • Kenta Kitamura, 25 September 2026: the second thread comment, announcing, with ChatGPT and OpenAI Codex using GPT-6 Astra and Claude Code using Claude Opus 5.5, a Lean 4 development that declares lim sup⁡f(N)/N≤0.8461739827964010\limsup f(N)/N\le0.8461739827964010, the smallest claimed constant; formal-conjectures added the variant with a formal_proof annotation pointing at it on 27 September 2026. Not built here.

None of the three pending claims from the tab and the thread has acceptance evidence or independent review, and none changes the standing.

Search scope. The site's problem, discussion and proof-claim pages; the community database record; the formal-conjectures file at the pinned commit; the GitHub API for the commit history of the note's file in Woett/Mathematical-shorts (one commit, 11 August 2025) and for the head of khanukov/erdos302; arXiv API searches for abstracts on unit-fraction-free sets or unit fractions with positive density (one unrelated record), on unit fractions and averages (Sawin's preprint on Problem 327 and one unrelated record) and for "Erdős problem" with unit fractions (none); OEIS A390395; the primary sources [vD25], [BrRo91] (its card and Corollary 2.3 page) and [ErGr80] read as stated. Not searched: MathSciNet, zbMATH, Google Scholar, X. Nothing found is refereed or determines the constant.

Remaining gaps. (1) The bounds rest on the site's commentary: the upper bound on its Problem 301 argument, with its counting facts checked, and the lower bound on Cambie's construction, both elementary and checked here to the depth stated; van Doorn's weaker upper bound is an unrefereed GitHub note, and no refereed source states either bound. (2) The proof of Theorem 2 was read for structure, its Lemma 4 inequalities not rechecked. (3) The forum comments and the three pending claims from the tab and the thread were consulted only for their statements. (4) The gap between 5/85/8 and 25/2825/28 is the open estimation question. There is no status-defining theorem to compile.

Progress and known results

Established here: (5/8+o(1))N≤f(N)≤(25/28+o(1))N(5/8+o(1))N\le f(N)\le(25/28+o(1))N, the upper bound the site's argument for Problem 301 (checked there), which sharpens van Doorn's Theorem 2, f(N)<9N/10+(log⁡N)3+1f(N)<9N/10+(\log N)^3+1 (claim page), and the lower bound Cambie's construction (site commentary, checked here; claim page); hence f(N)≠(1/2+o(1))Nf(N)\ne(1/2+o(1))N. Claimed, unrefereed: 373/420373/420 (Schuh), 5/8+δ5/8+\delta and about 0.860850.86085 (Khanukov), about 0.84620.8462, the smallest claimed constant (Kitamura), and the N/(log⁡N)β+o(1)N/(\log N)^{\beta+o(1)} gain (forum, 5 July 2026). The coloring version is Problem 303, proved by Brown and Rödl's Corollary 2.3 (with n=2n=2, a=1a=1), a partition-regularity statement that yields no density bound here; the all-length relation is Problem 301, and the divisibility form of the pair relation is Problem 327.

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