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Problem 206

../

claims/: The 1 claim page of Problem 206, one per claimant's result; the problem's standing derives from them.


Statement. Let x>0x>0 be a real number. For any n≥1n\geq 1 let

Rn(x)=∑i=1n1mi<xR_n(x) = \sum_{i=1}^n\frac{1}{m_i}<x

be the maximal sum of nn distinct unit fractions which is <x<x.

Is it true that, for almost all xx, for sufficiently large nn, we have

Rn+1(x)=Rn(x)+1m,R_{n+1}(x)=R_n(x)+\frac{1}{m},

where mm is minimal such that mm does not appear in Rn(x)R_n(x) and the right-hand side is <x<x? (That is, are the best underapproximations eventually always constructed in a 'greedy' fashion?)

Formulation. "Almost all" means Lebesgue almost every x>0x>0. The denominators are distinct positive integers; the maximum defining Rn(x)R_n(x) exists (by the argument of Nathanson's Theorem 3, on the card linked below, which the paper states for x∈(0,1]x\in(0,1] with repeated denominators ≥2\ge2), so Rn(x)R_n(x) is a rational number that may have several representations. Kovač's paper phrases the property as the existence of one strictly increasing sequence (mk)(m_k) and an n0n_0 with ∑k≤n1/mk=Rn(x)\sum_{k\le n}1/m_k=R_n(x) for every n≥n0n\ge n_0; this is the site's recursion, because nested best sums force the added denominator to be the least unused one that keeps the sum below xx and to exceed the denominators already used. The question is yes or no, and the answer is no. The companion questions for every rational xx and for every algebraic xx are variants, not the problem; they are recorded separately below.

Status. Disproved. Kovač's Theorem 1 (J. Number Theory 268 (2025), 39--48) shows that the set of x>0x>0 whose best Egyptian underapproximations are eventually greedy has Lebesgue measure zero, so the assertion fails for almost every xx instead of holding for almost every xx. The site's label is DISPROVED (LEAN); the suffix is a catalog label explained under Formalization. The claim page Kovač 2024 records the result, its postings and the acceptance evidence (refereed publication and the curator's credit) from which the standing above derives.

Source. erdosproblems.com/206, accessed 2026-09-17: the problem page (DISPROVED (LEAN); no last-edited date shown), its five-comment discussion thread and its empty proof-claim tab. The site cites [ErGr80, p. 31]. Cite as: T. F. Bloom, Erdős Problem #206, https://www.erdosproblems.com/206, accessed 2026-09-17.

References.

  • [ErGr80] Erdős, P. and Graham, R. L., Old and new problems and results in combinatorial number theory. Monographies de L'Enseignement Mathématique 28, Université de Genève (1980), p. 31.
  • [Cu22] Curtiss, D. R., On Kellogg's Diophantine problem. Amer. Math. Monthly 29 (1922), no. 10, 380--387.
  • [Er50b] Erdős, P., Az 1/x1+⋯+1/xn=a/b1/x_1+\cdots+1/x_n=a/b egyenlet egész számú megoldásairól (On a Diophantine equation). Mat. Lapok 1 (1950), 192--210.
  • [Na23] Nathanson, M. B., Underapproximation by Egyptian fractions. J. Number Theory 242 (2023), 208--234, doi:10.1016/j.jnt.2022.07.005; arXiv:2202.00191v2 (2022).
  • [Ch23b] Chu, H. V., A threshold for the best two-term underapproximation by Egyptian fractions. Indag. Math. (N.S.) 35 (2024), no. 2, 350--375, doi:10.1016/j.indag.2024.01.006; arXiv:2306.12564v2 (2024).
  • [Ko24b] Kovač, V., On eventually greedy best underapproximations by Egyptian fractions. J. Number Theory 268 (2025), 39--48, doi:10.1016/j.jnt.2024.09.004; arXiv:2406.07218v3 (2024).
  • [KoTa26] Kovač, V. and Tang, Q., Eventually greedy best Egyptian underapproximations of rational numbers via optimal control. arXiv:2607.28387v2 (4 August 2026), 30 pages; preprint.

Formalization. Statement only. The file ErdosProblems/206.lean of formal-conjectures at the linked revision (the main head of 2026-09-17) declares erdos_206 : answer(False) ↔ ∀ᵐ x ∂(volume.restrict (Set.Ioi (0 : ℝ))), EventuallyGreedy x under category research solved, with proof sorry, and carries a formal_proof attribute pointing to an external Lean 4 file. The community database records the formal status as Lean and no formal-proof URL. This corpus has built and audited neither file; see "Formalization and the Lean label" below.

Current assessment

The question (site formulation). The statement above; status DISPROVED (LEAN). The commentary attributes the disproof to Kovač [Ko24b] and adds: Erdős and Graham wrote that it is "not difficult" to construct irrational xx for which the property fails but gave no proof or reference, and no explicit such xx is known; the property holds for x=1x=1 (Curtiss [Cu22]), for x=1/mx=1/m, m≥1m\ge1 (Erdős [Er50b]), for x=a/bx=a/b with a∣b+1a\mid b+1 (Nathanson [Na23]) and for a larger class of rationals (Chu [Ch23b]); whether it holds for every rational x>0x>0 is listed as unknown; without "eventually" it fails for some rationals, for example R1(11/24)=1/3R_1(11/24)=1/3 but R2(11/24)=1/4+1/5R_2(11/24)=1/4+1/5; see also Problem 282. The origin is printed p. 31 of the 1980 monograph: the claim for every rational a/ba/b is stated without proof, then "An attractive conjecture is that this also holds for any algebraic number as well. It is not difficult to construct irrationals for which the result fails. Conceivably, however, it holds for almost all reals."

Status-defining source. Kovač, Theorem 1: the set of positive reals with eventually greedy best Egyptian underapproximations has Lebesgue measure zero. Version: arXiv:2406.07218v3 (26 September 2024; the arXiv comment says v3 incorporates the referee's suggestions), and the paper appeared in J. Number Theory 268 (March 2025), 39--48 (Crossref record checked 2026-09-17); the published text was not compared with that version. Refereed publication is the acceptance evidence. The statement is checked clause by clause, and the seven-page proof is summarized for its structure on the result page: a recursive reduction to two-term underapproximations, in which Lemma 3 (for every i≥1000i\ge1000 at least one per mille of the numbers in (1/i,1/(i−1)](1/i,1/(i-1)] have non-greedy best two-term underapproximations) drives the geometric decay ∣Xs,t+2∣≤19992000∣Xs,t∣|X_{s,t+2}|\le\frac{1999}{2000}|X_{s,t}| of Lemma 4 for the sets of numbers whose best nn-term sums are nested for s≤n≤ts\le n\le t. The proof is not rewritten in the corpus and has not been independently reviewed. Its Corollary 2 gives, non-constructively, a transcendental number without the property.

Where the property does hold (historical and current results).

  • x=1x=1: Curtiss, Theorem I (1922): the least positive value of 1−∑k≤n−11/xk1-\sum_{k\le n-1}1/x_k over positive integers is 1/un1/u_n, where u1=1u_1=1 and uk+1=uk(uk+1)u_{k+1}=u_k(u_k+1), attained only at xk=uk+1x_k=u_k+1. So Rn(1)=∑k≤n1/(uk+1)=1−1/un+1R_n(1)=\sum_{k\le n}1/(u_k+1)=1-1/u_{n+1} for every nn, with denominators 2,3,7,43,…2,3,7,43,\ldots, and the best underapproximations of 11 are greedy at every step, not only eventually. Takenouchi independently found, in a paper that had then just appeared (Proc. Phys.-Math. Soc. Japan (3) 3, 78--92), the largest unknown in solutions of ∑1/xi=b/a\sum1/x_i=b/a for a=(m+1)b−1a=(m+1)b-1, which for b=m=1b=m=1 is Kellogg's bound, but did not prove Theorem I itself (Curtiss's author's note, p. 387).
  • x=1/mx=1/m: attributed by the site and by Kovač (p. 2: Erdős "observed that this remains to hold whenever x=1/bx=1/b itself is a unit fraction") to Erdős [Er50b]. What the 1950 paper states and proves is the case x=1x=1, on its result page Theorems 3--5: the Sylvester sequence gives the largest proper fraction with N(a,b)≤nN(a,b)\le n, so the best nn-term underapproximation of 11 is the greedy one, the statement Curtiss proved. No statement for x=1/mx=1/m appears on printed pp. 194--197, 203--204 and 208, and a search of the text of all nineteen pages finds none, so the 1/m1/m case rests on the two attributions.
  • x=p/q∈(0,1]x=p/q\in(0,1] with p∣q+1p\mid q+1: Nathanson, Theorem 5 (2023): the greedy nn-term sequence, a1=(q+1)/pa_1=(q+1)/p and ak+1=qa1⋯ak+1a_{k+1}=qa_1\cdots a_k+1, is the unique best nn-term underapproximation for every nn, in the convention that allows repeated denominators; since it is strictly increasing, it is also the unique best among distinct denominators.
  • x=p/qx=p/q with p<qp<q, qq odd and 22 the least ℓ≥1\ell\ge1 with p∣q+ℓp\mid q+\ell: Chu, Theorem 1.12 (2024), the "larger class" of the site's commentary. Chu's Theorem 1.3 gives the threshold for two-term greed: for p<qp<q with Υ(p,q)≤3\Upsilon(p,q)\le3 (the least j≥1j\ge1 with p∣q+jp\mid q+j) the greedy pair is the unique best two-term underapproximation, except that 10/1710/17 has the two equal best pairs 1/2+1/12=1/3+1/41/2+1/12=1/3+1/4, and for each k≥4k\ge4 some p/qp/q with Υ(p,q)=k\Upsilon(p,q)=k has a non-greedy best pair.
  • every positive rational (a preprint claim): Kovač and Tang, Theorem 1 (arXiv:2607.28387, v1 30 July 2026, v2 4 August 2026): for every rational λ>0\lambda>0, in both the distinct and the repeated-denominator convention and with every denominator at least 22, there is n0n_0 such that Rn0+m(λ)=Rn0(λ)+Rm(λ−Rn0(λ))R_{n_0+m}(\lambda)=R_{n_0}(\lambda)+R_m(\lambda-R_{n_0}(\lambda)) for all m≥1m\ge1, the greedy mm-term tuple is the unique maximizer for the remainder, and a maximizing n0n_0-tuple can be extended by the greedy denominators. For λ≤1\lambda\le1 this would settle the rational companion question that the site lists as unknown (for λ>1\lambda>1 the problem also admits the denominator 11, which the paper's tuples exclude) and the one that Nathanson posed as Open problem (4). It is an author preprint, with no independent review found, and its Declaration of AI usage (p. 28) says that key steps of the proof were provided by OpenAI's GPT-5.6 Sol and rewritten by the authors. It is recorded as a claim with provenance, not as a status; the frontmatter status concerns the almost-all question only. The second author announced the result in the site discussion on 31 July 2026.
  • algebraic xx: open. Erdős and Graham's "attractive conjecture"; Kovač and Tang write that they cannot resolve it. A site comment of 9 August 2025 speculates that all algebraic numbers are eventually greedy; it carries no argument.
  • an explicit non-example: open. Kovač's Corollary 2 is non-constructive. In the other direction, Kovač and Tang's Example 2 gives an explicit irrational, the Liouville number ∑n≥12−n!\sum_{n\ge1}2^{-n!}, whose greedy nn-term underapproximation is the unique best one for every nn, in both conventions, answering Nathanson's Open problem (1).

Formalization and the Lean label. The site's Lean suffix is a catalog label. The formal-conjectures file at the pinned commit is a statement with a sorry body; its formal_proof attribute names the file src/latest/ErdosProblems/Erdos206.lean of the repository plby/lean-proofs at the linked revision. That file (89,993 bytes, imports Mathlib) contains no sorry, ends with theorem erdos_206 : volume {x : ℝ | EventuallyGreedy x} = 0 and a #print axioms comment listing only propext, Classical.choice and Quot.sound; its header names Aristotle and Matteo Del Vecchio as formal authors and links the gist that the site discussion (comment of 28 April 2026) describes as an autoformalization of Kovač's proof by Aristotle. Its EventuallyGreedy has the same shape as the formal-conjectures definition (a strictly increasing sequence of positive denominators whose prefixes are best nn-term underapproximations, quantified over all finite sets of positive naturals with sum below xx). The comparison covers the statement only: no build, no audit of the 1,980-line proof and no kernel credit is claimed. The community database (teorth/erdosproblems) lists formal_status Lean, as of its entry's last update on 28 April 2026, and no formal-proof URL.

Search scope. None of the routes below found a refereed source changing the answer above, a published version of the rational claim, or an explicit non-example.

  • The site: problem page, discussion thread and proof-claim tab (empty); formal-conjectures at the pinned commit; the community database file.
  • arXiv abstract pages for 2406.07218 (v1 11 June 2024, v2 13 June 2024, v3 26 September 2024; no journal reference), 2607.28387 (v1 30 July 2026, v2 4 August 2026), 2306.12564 (v1 19 June 2023, v2 20 January 2024) and 2202.00191 (v1 1 February 2022, v2 3 February 2022).
  • Crossref records for the three DOIs above and a bibliographic query for the Kovač--Tang title (no journal record).
  • Semantic Scholar citation lists: three papers cite Kovač 2024 (Kovač--Tang; Li and Tang, Acta Math. Hungar. 177 (2025), whose conditional Theorem 1.6 Kovač--Tang make unconditional as their Corollary 3; and a 2025 Fibonacci Quarterly paper on two-term underapproximations), and none cites Kovač--Tang.
  • arXiv API listings: "eventually greedy" (three records: the two Kovač papers and Li--Tang arXiv:2503.12277), "Egyptian underapproximation(s)" (four), "Problem 206" AND Egyptian (one).
  • The primary sources [Cu22] (page images), [Na23], [Ch23b], [Ko24b], [KoTa26] and printed p. 31 of [ErGr80] (page image), read as stated.

Not searched: MathSciNet, zbMATH, Google Scholar, X. Not read: Graham's 2013 survey and the Li--Tang papers (cited through Kovač--Tang), the published versions of [Na23], [Ch23b] and [Ko24b], and the Hungarian text of [Er50b] beyond printed pp. 194--197, 203--204 and 208.

Remaining gaps. (1) Kovač's proof is compiled as statement and structure only; a full rewriting and an independent review remain outstanding. (2) The x=1/mx=1/m case rests on attributions: the 1950 paper's x=1x=1 theorems are paged, and no 1/m1/m statement was located on the pages read. (3) The rational companion is a preprint claim with a disclosed AI-assisted proof; it becomes a recorded result when a refereed version or an independent review appears. (4) Published versions of three sources are not compared with their arXiv versions. (5) No explicit non-example and no result on algebraic xx exist in the sources read. (6) The Lean artifacts are pointers, not local evidence.

Linked library material

These entries are derived from explicit links on library pages. They are navigation only and do not by themselves record mathematical progress.