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Problem 1205
claims/: The 1 claim page of Problem 1205, one per claimant's result; the problem's standing derives from them.
Statement. Let be maximal such that there exists, for all , a congruence class such that every satisfies at least of these congruences.
Estimate .
Formulation. The site's wording (page last edited 8 April 2026). One residue class is chosen for every modulus , and is the largest multiplicity that some choice guarantees for every ; the class modulo is satisfied by every , so . Erdős's 1980 survey (printed p. 108) defines the function right after the prime-modulus version that is Problem 689: "Denote by the largest integer for which there is a system of congruences (8) (where runs through the integers not exceeding ) so that every integer satisfies at least of the congruences (8). Now it is a simple exercise to prove that as . The only problem is to determine or estimate how fast tends to infinity." The site's statement is this question with for .
Status. SOLVED, the site's label, which the page glosses as a resolution by
some means other than a proof or disproof: the site's own commentary gives an
argument that , with the two-sided bound
. The status-defining
source is that commentary (last edited 8 April 2026), which this compilation
admits as a source for status. No paper, preprint or independent review of the
argument exists, and the label is the claimant's own (the site's curator, T. F.
Bloom, wrote the argument, so the curator's label is no independent review), so
the argument is a pending claim
(the site's argument, April 2026)
and the derived standing is claimed, not solved. The argument is presented
below as the site's account with its steps named and is not checked step by step
here.
Source. erdosproblems.com/1205, accessed 2026-09-18 at 10:27 UTC: the problem page (SOLVED, with the site's gloss that the resolution is by some means other than a proof or disproof; last edited 8 April 2026; source key [Er80, p. 108]; an OEIS indicator reading possible), its empty discussion thread and its empty proof-claim tab. Cite as: T. F. Bloom, Erdős Problem #1205, https://www.erdosproblems.com/1205, accessed 2026-09-18.
References.
- [Er80] Erdős, P., A survey of problems in combinatorial number theory. Ann. Discrete Math. 6 (1980), 89--115; item 6 of Section 6, printed p. 108. Library home: erdos_1980_survey_problems_combinatorial_number_theory.
Formalization. None found: there is no
ErdosProblems/1205.lean in google-deepmind/formal-conjectures and the problem
page shows no formalized statement. The community database
(teorth/erdosproblems,) records the problem solved (record last updated 4 April
2026), the statement not formalized, formal_status unformalized and no
formal-proof URL.
Current assessment
The question (site formulation). The statement above; SOLVED, last edited 8 April 2026. The commentary, which is the status-defining source, recalls that Erdős called a "simple exercise", points to Problem 689 as the prime-modulus analogue, and then gives an argument, which it says was suggested by the comments on that problem, for : a pigeonhole upper bound , a lower bound from uniformly random classes for the moduli with a Chernoff-type concentration step leaving exceptional integers, and a greedy choice of the classes for covering those exceptions times; its conclusion is the displayed two-sided bound. The thread and the proof-claim tab are empty. The claim page [[problems/integer_sequences/E1205/claims/2026_04_08_bloom|the site's argument, April 2026]] records it as a pending full claim.
The origin. Item 6 of Section 6, "Some problems on sieve methods", of the survey, printed p. 108, quoted under Formulation. It follows the prime-modulus function of Problem 689 ("Let be the largest integer for which there is a system of congruences ... so that every integer should satisfy at least of the congruences ... I can not even prove that for "), and Erdős asserts as an exercise without an argument or a rate.
The site's argument, as the site's. Three steps, named here and not re-proved. An averaging upper bound: each modulus puts about of the integers into its class, so the average number of congruences an integer satisfies is , and some is at or below the average. A random lower bound for the moduli : each lies in the class of with probability , the expected count is , and a Chernoff-type concentration bound leaves at most integers covered fewer than times. A greedy repair with the moduli : each of these classes can be aimed at one of the exceptional integers, and there are far more such moduli than exceptional integers, so the exceptional ones end up covered times. Together these give , hence . The compilation records this as the site's account: the concentration step and the greedy count are not written out on the site, no published version exists, and no step is checked here; an independent whole-argument review, an elementary one, is the evidence that would accept it. The site's remark that the argument was inspired by the comments on Problem 689 is recorded; that page carries the prime-modulus question, which remains open.
Context, not consumed. Sun's 1999 theorem on the covering multiplicity of a finite system of residue classes (card) concerns systems covering every integer at least times and relates to sums of the reciprocal moduli; the present question restricts the covered integers to and chooses the classes, so the theorem does not apply to it as stated and is not cited as a result here.
Search scope. None of the routes below found a published proof of , a sharper estimate of the second-order term, or a dispute of the site's argument.
- The site: problem page, discussion thread and proof-claim tab; the formal-conjectures directory listing and tree (no file); the community database.
- arXiv: the API query
abs:"congruence" AND abs:"covering" AND abs:"multiplicity"(twenty records, none on this function); the API searches titles and abstracts only, so this zero is weak. - The primary source: [Er80] p. 108.
Not searched: MathSciNet, zbMATH, Google Scholar, X.
Remaining gaps. (1) The label rests on the site's own argument, which has
no publication and no independent review, so its claim page is claimed and
the problem's standing is claimed; a written proof, a review or a refereed
source is the evidence that would accept it. (2) The second-order term is
open: the argument gives
and nothing narrower
was found. (3) No formalization exists.
Linked library material
These entries are derived from explicit links on library pages. They are navigation only and do not by themselves record mathematical progress.