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Problem 1062

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claims/: The 5 claim pages of Problem 1062, one per claimant's result; the problem's standing derives from them.


Statement. Let f(n)f(n) be the size of the largest subset $A\subseteq {1,\ldots,n}$ such that there are no three distinct elements a,b,c∈Aa,b,c\in A such that a∣ba\mid b and a∣ca\mid c. How large can f(n)f(n) be? Is lim⁡f(n)/n\lim f(n)/n irrational?

Status. Open on the site: the problem is labeled OPEN, with the site's note that it cannot be settled by a finite computation, and its commentary (last edited 6 January 2026) records only the trivial bound and Lebensold's bracket. The site's one proof-claim entry, registered on 27 September 2026 by the curator, Thomas Bloom, attributes to conjectures.io a proof, by an AI system the entry gives as unknown, that the limit exists and is irrational; the entry says that he has not verified it and that the program does not disclose who runs the AI or which system, so it is not an acceptance. The derived standing rests on the claim pages. A Lean proof submitted to the bounty site Conjectures.io under the username JenW1N, verified by the site's Lean kernel, approved in review on 22 September 2026 and certified on 23 September 2026 with its bounty paid (claim page, accepted), proves that lim⁡f(n)/n\lim f(n)/n exists and is irrational, which answers the second question yes and the first in asymptotic form, f(n)=(l+o(1)) nf(n)=(l+o(1))\,n with ll irrational. Davis's paper of April 2026 gives f(n)=c2n+o(n)f(n)=c_2n+o(n) with c2c_2 effectively computable and leaves irrationality open (claim page, partial); a note generated with GPT-5.4 Pro and posted by Przemek Chojecki on 20 April 2026 proves the same with an explicit error term (claim page, partial). Lebensold's refereed bracket 0.6725n≤f(n)≤0.6736n0.6725n\le f(n)\le0.6736n for large nn (1977) is an accepted partial claim (claim page). A manuscript announced in the thread on 23 September 2026 asserts an extremal formula for f(n)f(n) and that the limit is transcendental (claim page, full, unreviewed).

Source. erdosproblems.com/1062, accessed 2026-09-22 and 2026-10-07 (OPEN; source keys [Gu04] and [Le76]; last edited 6 January 2026; a formalized statement; fourteen comments and one proof-claim entry on 2026-10-07; OEIS A038372), and the Conjectures.io record conjectures.io/results/8d59a0af-6762-4606-93c9-72dd356a57bc, read 2026-10-07 (Lean verified 21 September 2026; approved in review 22 September 2026; certified 23 September 2026; bounty paid). Cite as: T. F. Bloom, Erdős Problem #1062, https://www.erdosproblems.com/1062, accessed 2026-10-07.

References.

  • [Gu04] Guy, Richard K., Unsolved problems in number theory, 3rd ed. Problem Books in Mathematics, Springer (2004), xviii+437 pp. B24 "The largest set with no member dividing two others", printed p. 124: "Let f(n)f(n) be the size of the largest subset of [1,n][1,n] no member of which divides two others. Erdős asks how large can f(n)f(n) be?", the ⌈2n/3⌉\lceil2n/3\rceil example, Kleitman's f(29)=21f(29)=21, Lebensold's 0.6725n≤f(n)≤0.6736n0.6725n\le f(n)\le0.6736n for large nn (the bracket stated under The accepted proof), and "Erdős also asks if lim⁡f(n)/n\lim f(n)/n is irrational"; no proofs. Library home: guy_2004_unsolved_problems_number_theory.
  • [Le76] Lebensold, Kenneth, A divisibility problem. Studies in Appl. Math. 56 (1976–77), 291–294.
  • [Da26] Davis, Damek, Forbidden subgraphs in divisor graphs and an Erdős divisibility problem. arXiv:2604.17613 (2026), Corollary 4.

Formalization. Statement in formal-conjectures.

Current assessment

The standing is solved on the qualifications the Status field states. The status-defining source is the Lean proof accepted by the bounty site Conjectures.io (claim page), kernel-verified on 21 September 2026, approved in review and certified on 23 September 2026 with its bounty paid; the site's certification is the outside review, and the problem's standing rests on nothing else. The reviewed target answers the first question in asymptotic form only; the exact closed formula for f(n)f(n) and the value of the limit, 0.6729656511994…0.6729656511994\ldots, are intermediate theorems of the accepted file, outside the site's statement check, and the section below states them. On 2026-10-07 the erdosproblems.com page showed OPEN, last edited 6 January 2026, with fourteen comments and the curator's proof-claim entry of 27 September 2026 pointing at that Conjectures.io solution without endorsing it; its thread carries a post of 23 September 2026 reporting the Conjectures.io result and announcing an independent, unreviewed manuscript that asserts an extremal formula for f(n)f(n) and the transcendence of the limit (claim page, a pending full claim). The searches found no refereed publication and no erdosproblems.com acceptance, and the catalog's statement file, at that commit, tags the irrationality clause research open. Davis's 2026 paper (claim page, partial) establishes the existence of the limit, which answers the first question in asymptotic form, and leaves irrationality open; Chojecki's note of 20 April 2026 (claim page, partial) reaches the same answer independently, with an explicit error term. The accepted Lean file was not built here, and no independent review of it is filed here.

The accepted proof

The formula: writing every m≤nm\le n as q⋅2a3bq\cdot2^a3^b with qq coprime to 66,

f(n)=∑q≤n(q,6)=1s(⌊n/q⌋)−#{q≤n:(q,6)=1, ⌊n/q⌋∈W},f(n)=\sum_{\substack{q\le n\\(q,6)=1}} s(\lfloor n/q\rfloor) -\#\{q\le n:(q,6)=1,\ \lfloor n/q\rfloor\in W\},

where for m≥1m\ge1, s(m)=⌊log⁡3m⌋+1+⌊⌊log⁡2m⌋/2⌋+[⌊log⁡2m⌋ odd and 2⋅3⌊log⁡3m⌋≤m]s(m)=\lfloor\log_3 m\rfloor+1+\lfloor\lfloor\log_2 m\rfloor/2\rfloor+[\lfloor\log_2 m\rfloor\text{ odd and }2\cdot3^{\lfloor\log_3 m\rfloor}\le m] is the largest size of a fork-free set of {2,3}\{2,3\}-smooth numbers up to mm, and WW is the set of mm with 4j≤m<54⋅4j4^j\le m<\tfrac54\cdot4^j and 10⋅3b≤m<12⋅3b10\cdot3^b\le m<12\cdot3^b for some j,bj,b (the first is m=270m=270), the scales at which the components of qq and 5q5q cannot both be full. The limit is (32+∑k≥0c4(k)/4k+∑k≥0c3(k)/3k)/180\bigl(32+\sum_{k\ge0}c_4(k)/4^k+\sum_{k\ge0}c_3(k)/3^k\bigr)/180, where c4(k)∈{78,30,−30,30,0,−60,−12}c_4(k)\in\{78,30,-30,30,0,-60,-12\} and c3(k)∈{30,35,29,24,−60}c_3(k)\in\{30,35,29,24,-60\} are integer step functions of the position of 4k4^k among the powers of 33 and of 3k3^k among the powers of 44, that is, codings of the rotation by the irrational number log⁡4/log⁡3\log4/\log3. The value lies inside Lebensold's bracket 0.6725 n≤f(n)≤0.6736 n0.6725\,n\le f(n)\le0.6736\,n for large nn ([Le76], not held; recorded on its claim page) and above the trivial f(n)≥⌈2n/3⌉f(n)\ge\lceil2n/3\rceil from A=[m+1,3m+2]A=[m+1,3m+2].

The formal statement the site attacked is the formal-conjectures clause Erdos1062.erdos_1062.parts.ii (FormalConjectures/ErdosProblems/1062.lean) with its open answer fixed to true: there is an ll with f(n)/n→lf(n)/n\to l and ll irrational. There ForkFree A says that for each a∈Aa\in A at most one other element of AA is a multiple of aa, and f n is the largest size of a fork-free subset of {1,…,n}\{1,\ldots,n\}, which is the site wording's definition and its second question clause for clause, with the existence of the limit asserted as a conjunct rather than presupposed, so the formal target is at least as strong as the question. The accepted file proves that statement with no hypothesis, in four steps: the exact formula for every nn, its upper half a counting bound and its lower half a construction certified by kernel-checked finite tables below 1,647,0861{,}647{,}086 and a strong induction above; convergence of f(n)/nf(n)/n, by summing the jumps of ss and of the loss term against the density 1/31/3 of the integers coprime to 66; identification of the limit with the explicit series; and irrationality by contradiction, since a rational limit would give, through the rotation by log⁡4/log⁡3\log4/\log3 and a two-cutoff argument, infinitely many small nonzero integer combinations of at most 404404 numbers of the form 2a3b2^a3^b with bounded height, which a finiteness theorem for such combinations excludes. That finiteness theorem is the file's deepest component: a parametric Subspace Theorem over Q\mathbb{Q} for the places ∞\infty, 22 and 33 with rational linear forms in every dimension (its two-dimensional case is the Mahler--Ridout finiteness of the solutions of 0<3b−2a≤2a(1−ε)0<3^b-2^a\le2^{a(1-\varepsilon)}), proved inside the file in about 19,000 lines by Schmidt's method (Roth's lemma, geometry of numbers, compound matrices, Davenport's lemma), with Siegel's lemma from Mathlib as its one imported geometry-of-numbers input; no earlier machine-checked proof of a result of this depth is known to this compilation, and the site's note does not mention it.

The reviewed target answers the first question only in asymptotic form, f(n)=(l+o(1)) nf(n)=(l+o(1))\,n with ll irrational: the exact formula and the identification of the limit are intermediate theorems of the same file, compiled as part of the file the site's kernel accepted but not the subject of its statement check or its review, so their standing here is the site's build of the file together with the recomputations below. The site's review note says that a production run verified the submitted proof with Lean, comparator, statement-equality and permitted-axiom checks (the axioms propext, Quot.sound and Classical.choice; no imports, axiom declarations, sorry, native_decide or unsafe options; the statement unchanged), that the proof establishes both the convergence of f(n)/nf(n)/n and the irrationality of its limit, that one Codex assessment was completed without multiple independent assessments or a claim of independent consensus and a human operator accepted the advisory recommendation, that the review relied on the recorded verification, integrity checks, selected proof interfaces and bounded prior-work searches rather than a fresh kernel replay or a complete line-by-line audit, and that a second kernel was not run, so the verdict rests on a single kernel implementation. The accepting body is the bounty site alone, distinct from journal refereeing.

The 74,209-line proof file, from the record's solution page, was not built here: its target, header and key declarations agree with the site's statement; the file contains no sorry, axiom, native_decide, unsafe, implemented_by, opaque or set_option and no import, one theorem (the target; every other proposition is a def), and 3,609 decide +kernel lines on finite certificates, all inside the combinatorial part; no catalog or Mathlib name is redefined in the file; the chain from the target back to the constructions is complete at the level of every statement; the exact formula was confirmed by brute force for every n≤42n\le42, the explicit series was summed in exact arithmetic to 0.6729656511994890.672965651199489, the closed form's ratio f(n)/nf(n)/n was evaluated to nine digits at n=109n=10^9 and agrees with the series, and the final exponent bookkeeping and the irrationality of log⁡4/log⁡3\log4/\log3 were re-derived by hand; the Subspace-Theorem component and the summability estimates are checked at statement and comment level only and rest on the site's single kernel, and no numerical check can reach a Roth-type finiteness statement; no local kernel credit is claimed. The file's header names no author and declares no AI system; its assembly comments say that a complete ordinary-kernel check and target axiom audit are still required, and several component comments still call the covering theorem an explicit hypothesis, notes written before the final component, which proves that theorem and closes the target without hypotheses. Two further limits: the statement file was compared against the catalog's default branch, and the site's own source-type-hash check is the evidence that the pinned statement agrees (the record's solution page prints its proof target under a different task id and catalog revision than the record's); and the shared definitions of the target macro and the catalog's answer marker are known only through the proof's unfolding of them.

Progress

Davis's Corollary 4 gives f(n)=c2n+o(n)f(n)=c_2n+o(n) for an effectively computable constant c2c_2 (in fact with an explicit smaller error term). Thus the limit lim⁡f(n)/n\lim f(n)/n exists. The paper says explicitly that it does not settle whether c2c_2 is irrational. A note generated with GPT-5.4 Pro, dated 15 April 2026 and posted in the thread by Przemek Chojecki on 20 April 2026, proves the same existence through McNew's theorem, as Davis's paper does, with the error term Oε(nexp⁡(−(1−ε)log⁡nlog⁡log⁡n))O_\varepsilon(n\exp(-(1-\varepsilon)\sqrt{\log n\log\log n})), and evaluates the first four layers of the series for the limit (claim page). The later bounty-site Lean proof described above settles the irrationality question (claim page); a manuscript announced in the thread on 23 September 2026 asserts an extremal formula for f(n)f(n) and the stronger statement that the limit is transcendental (claim page, unreviewed).

Linked library material

These entries are derived from explicit links on library pages. They are navigation only and do not by themselves record mathematical progress.