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Problem 920

../

claims/: The 2 claim pages of Problem 920, one per claimant's result; the problem's standing derives from them.


Statement. Let fk(n)f_k(n) be the maximum possible chromatic number of a graph with nn vertices which contains no KkK_k.

Is it true that, for k≥4k\geq 4,

fk(n)≫n1−1k−1(log⁡n)ckf_k(n) \gg \frac{n^{1-\frac{1}{k-1}}}{(\log n)^{c_k}}

for some constant ck>0c_k>0?

Status. SOLVED, the site's label (page last edited 25 July 2026); the site credits the case k=4k=4 to Mattheus and Verstraete's bound on r(4,t)r(4,t) and the cases k≥5k\ge5 to Bradač's off-diagonal Ramsey bound, and the claim pages Mattheus–Verstraete 2023 and Bradač 2026 record the two results, each accepted for its range. The two parts of the question, k=4k=4 and k≥5k\ge5, are each settled by an accepted partial claim. The derived standing is proved, where the site's label records only that the problem is answered, because the question asks whether the bound holds and both claims prove that it does: the answer is yes for every k≥4k\ge4.

Source. erdosproblems.com/920, accessed 2026-09-04. Cite as: T. F. Bloom, Erdős Problem #920, https://www.erdosproblems.com/920.

References.

  • [Br26] Bradač, D., Off-diagonal Ramsey numbers. arXiv:2605.28793 (2026); the first version, of 27 May 2026, carried the title "Nearly tight exponents for off-diagonal Ramsey numbers", which the site's reference uses; the third version, of 16 June 2026, is the version cited.
  • [GrYa68] Graver, Jack E. and Yackel, James, Some graph theoretic results associated with Ramsey's theorem. J. Combinatorial Theory 4 (1968), 125--175; the Corollary to Proposition 9, printed p. 156: R(x,y)≤Byx−1log⁡log⁡y/log⁡yR(x,y)\le By^{x-1}\log\log y/\log y for x≥3x\ge3, where the paper's R(x,y)R(x,y) is the largest order of a graph with no KxK_x and no yy independent vertices, one less than the usual Ramsey number. The paper prints no chromatic-number statement; the site's display is the form Erdős's 1969 survey gives it, and the library card records the translation to fk(n)f_k(n) with a filing observation on the exponent of the logarithmic factor for k≥4k\ge4. Library home: Corollary.
  • [MaVe23] Mattheus, S. and Verstraete, J., The asymptotics of r(4,t)r(4,t). Ann. of Math. (2) 199 (2024), no. 2, 919--941, DOI 10.4007/annals.2024.199.2.8; arXiv:2306.04007 (2023).

Formalization. Statement in formal-conjectures; solution at https://github.com/plby/lean-proofs/blob/8822f7ddef30fadbd92e1c6ab4ed897af356af5e/src/latest/ErdosProblems/Erdos920.lean.

Current assessment

Question and answer. The site formulation asks whether, for every fixed k≥4k\ge4, there is ck>0c_k>0 with fk(n)≫n1−1/(k−1)/(log⁡n)ckf_k(n)\gg n^{1-1/(k-1)}/(\log n)^{c_k}. The answer is yes for every k≥4k\ge4, with ck=(2k−4)/(k−1)c_k=(2k-4)/(k-1), by one elementary transfer applied to two Ramsey lower bounds: a graph on nn vertices with no KkK_k and no independent set of tt vertices has chromatic number at least n/(t−1)n/(t-1), since its color classes are independent, and such a graph exists whenever r(k,t)>nr(k,t)>n. Mattheus and Verstraete's r(4,t)≫t3/(log⁡t)4r(4,t)\gg t^3/(\log t)^4 gives the case k=4k=4; Bradač's r(k,t)≫ktk−1/(log⁡t)2k−4r(k,t)\gg_k t^{k-1}/(\log t)^{2k-4}, stated for every k≥3k\ge3, gives every k≥5k\ge5 and reproduces the case k=4k=4.

Standing. Two accepted claim pages cover the question between them: Mattheus–Verstraete 2023 (refereed in the Annals of Mathematics; the site credits it for k=4k=4) and Bradač 2026 (an arXiv preprint; the site credits it for k≥5k\ge5). Each is partial, as the site's own split credits it. The problem lists its two parts, k=4k=4 and k≥5k\ge5, and each accepted claim names the part it settles, so the problem's standing derives as proved from the two together. Two notes posted on the site's proof-claims page in July 2026, by Miroslav Lžičař and by Moses Lua, derive the inequality for every k≥4k\ge4 from Bradač's theorem with the explicit exponent; both present the inequality as a corollary of Bradač's theorem and claim nothing about the Ramsey construction itself, so they are recorded on Bradač's claim page as later claims of the same result rather than as claims of their own. Lua's Lean file formalizes the transfer with the Ramsey bound as a hypothesis, which this corpus has not built. Boris Alexeev's lean-proofs repository holds an unconditional Lean proof of the answer, with Codex and GPT-5.6 Sol as formal authors and Bradač, Mattheus and Verstraëte as informal authors; the formal-conjectures catalog (920.lean) cites it as the formal proof of its statement, but this corpus has not built it, so it gives no formalized evidence.

Evidence and search scope. Read on 2026-10-07: the site's problem page, discussion thread and proof-claims page; the arXiv records of both papers and the Annals record of Mattheus and Verstraete's; the two GitHub repositories behind the forum notes; the formal-conjectures statement file (920.lean as of 18 September 2026) and the Lean file in Boris Alexeev's repository that it cites. Neither proof of the two Ramsey theorems is reviewed in this corpus. No wider literature search is recorded.

Progress

The lower bounds come from the transfer stated above. With r(k,t)≥c tk−1/(log⁡t)2k−4r(k,t)\ge c\,t^{k-1}/(\log t)^{2k-4}, the least tt at which the bound exceeds nn is of order n1/(k−1)(log⁡n)(2k−4)/(k−1)n^{1/(k-1)}(\log n)^{(2k-4)/(k-1)}, and fk(n)≥n/(t−1)f_k(n)\ge n/(t-1) gives

fk(n)≫kn1−1k−1(log⁡n)2k−4k−1,f_k(n)\gg_k\frac{n^{1-\frac{1}{k-1}}}{(\log n)^{\frac{2k-4}{k-1}}},

which at k=4k=4 is n2/3/(log⁡n)4/3n^{2/3}/(\log n)^{4/3}, the consequence of Mattheus and Verstraete's bound that the site displays. The polynomial exponent 1−1/(k−1)1-1/(k-1) matches Graver and Yackel's upper bound [GrYa68], so what remains is the power of the logarithm.

Known Results

  • Upper bound: Graver and Yackel's Corollary to Proposition 9 [GrYa68], translated on its library card by removing largest independent sets in turn, gives fk(n)≪n1−1/(k−1)(log⁡log⁡n/log⁡n)1/(k−1)f_k(n)\ll n^{1-1/(k-1)}(\log\log n/\log n)^{1/(k-1)}. The site's display, Erdős's 1969 form (4) read with the slash its print omits, puts the exponent 1−1/(k−1)1-1/(k-1) on the logarithmic factor. The two agree at k=3k=3; for k≥4k\ge4 the display is stronger than the corollary yields.
  • k=4k=4: Mattheus–Verstraete 2023, f4(n)≫n2/3/(log⁡n)4/3f_4(n)\gg n^{2/3}/(\log n)^{4/3}.
  • k≥5k\ge5: Bradač 2026, fk(n)≫kn1−1/(k−1)/(log⁡n)(2k−4)/(k−1)f_k(n)\gg_k n^{1-1/(k-1)}/(\log n)^{(2k-4)/(k-1)}.
  • k=3k=3 is not part of the question; the site reports f3(n)≍(n/log⁡n)1/2f_3(n)\asymp(n/\log n)^{1/2} and refers to Problem 1104 and Problem 1013.

Linked library material

These entries are derived from explicit links on library pages. They are navigation only and do not by themselves record mathematical progress.