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Problem 616

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claims/: The 1 claim page of Problem 616, one per claimant's result; the problem's standing derives from them.


Statement. Let r≥3r\geq 3. For an rr-uniform hypergraph GG let τ(G)\tau(G) denote the covering number (or transversal number), the minimum size of a set of vertices which includes at least one from each edge in GG.

Determine the best possible tt such that, if GG is an rr-uniform hypergraph GG where every subgraph G′G' on at most 3r−33r-3 vertices has τ(G′)≤1\tau(G')\leq 1, we have τ(G)≤t\tau(G)\leq t.

Status. Open, the site's label. The accepted partial claim Erdős–Hajnal–Tuza 1991 determines the best tt for thirty-eight values of rr between 33 and 7070; for every other rr it is open.

Source. erdosproblems.com/616, accessed 2026-09-04. Cite as: T. F. Bloom, Erdős Problem #616, https://www.erdosproblems.com/616.

References.

  • [EHT91] Erdős, Paul and Hajnal, András and Tuza, Zsolt, Local constraints ensuring small representing sets. J. Combin. Theory Ser. A (1991), 78-84.

Formalization. Statement in formal-conjectures.

Current assessment

The site labels the problem OPEN and credits Erdős, Hajnal and Tuza [EHT91] with the bounds 316r+78≤t≤15r\frac3{16}r+\frac78\le t\le\frac15r. The paper states them with rounding, ⌊316r+78⌋≤t≤⌈r/5⌉\lfloor\frac3{16}r+\frac78\rfloor\le t\le\lceil r/5\rceil (Theorem 3 and the remark after it, p. 80, with the lower-bound construction on p. 84). The site's display drops the floor and the ceiling, and as printed it contradicts itself for every r<70r<70, where 316r+78\frac3{16}r+\frac78 exceeds r5\frac r5.

The rounded bounds meet for thirty-eight values of rr, from r=3r=3 to r=70r=70, and there they determine t=⌈r/5⌉t=\lceil r/5\rceil; that is the accepted partial claim 1991_09_01_erdos_hajnal_tuza, whose page lists the values. For every other rr, including every r>70r>70, the best tt is open.

A comment of 17 August 2026 on the site's discussion thread, disclosed as AI-assisted, reported the dropped rounding and the consequences t=1t=1 for r=3,4,5r=3,4,5 and t(6)=t(7)=2t(6)=t(7)=2. An earlier exchange on the thread (18 January 2026) posted an AI-generated argument, attributed to ChatGPT 5.2 Pro, that t=2t=2 for every r≥6r\ge6; replies on the thread refuted it as inconsistent with the lower bound of [EHT91]. It was a thread post, not a dated manuscript, so it has no claim page. The site's proof-claim tab carries no claims.