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Problem 133

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claims/: The 4 claim pages of Problem 133, one per claimant's result; the problem's standing derives from them.


Statement. Let f(n)f(n) be minimal such that every triangle-free graph GG with nn vertices and diameter 22 contains a vertex with degree ≥f(n)\geq f(n).

What is the order of growth of f(n)f(n)? Does f(n)/n→∞f(n)/\sqrt{n}\to \infty?

Statement (corrected). Let f(n)f(n) be maximal such that every triangle-free graph GG with nn vertices and diameter 22 contains a vertex with degree ≥f(n)\geq f(n).

What is the order of growth of f(n)f(n)? Does f(n)/n→∞f(n)/\sqrt{n}\to \infty?

Notes. The site's wording takes the least f(n)f(n) such that every triangle-free graph of diameter 22 on nn vertices has a vertex of degree at least f(n)f(n). Every value up to the least maximum degree of such a graph has that property, so the least one is 00 for every nn and both questions become trivial. The smallest failing instance is n=3n=3: the only triangle-free graph of diameter 22 on three vertices is the path, of maximum degree 22, while the minimal f(3)f(3) is 00. The change replaces "minimal" by "maximal"; the largest value with the property is the least possible maximum degree of a triangle-free graph of diameter 22 on nn vertices. The evidence is the poser's own statement of the question: [Er97b] item 7, p. 229, defines f(n)f(n) as the smallest integer for which some triangle-free graph on nn vertices of diameter two has maximum degree f(n)f(n), and states the Erdős--Pach conjecture f(n)/n1/2→∞f(n)/n^{1/2}\to\infty for that function. Füredi and Seress define their D2(n)D_2(n) in the same way (Section 6 of [FuSe94], p. 23), and the site's own commentary derives the lower bound f(n)≥(1−o(1))nf(n)\ge(1-o(1))\sqrt n, which holds only for the corrected f(n)f(n). The defect is the site's; [Er97b] has the right extremum. No result about the site's wording is recorded.

Status. Disproved. The site's label answers the second question: Erdős and Pach conjectured f(n)/n→∞f(n)/\sqrt n\to\infty, and f(n)f(n) has order exactly n\sqrt n. The trivial bound f(n)≥n−1f(n)\ge\sqrt{n-1} (a graph of diameter 22 with every degree at most dd has at most d2+1d^2+1 vertices) is matched by Cayley graphs on symmetric complete sum-free sets: Hanson and Seyffarth [HaSe84] gave f(n)=O(n)f(n)=O(\sqrt n), a bound that the site, Füredi and Seress and Alon state for all large nn and Haviv and Levy for the sequence n=m2+5m+2n=m^2+5m+2 ([[problems/extremal_graph_theory/E0133/claims/1984_01_01_hanson_seyffarth|claim page]], partial), and Haviv and Levy [HaLe18] constructed such sets in every large cyclic group, proving f(n)=O(n)f(n)=O(\sqrt n) for every large nn ([[problems/extremal_graph_theory/E0133/claims/2017_03_12_haviv_levy|claim page]]). Füredi and Seress's projective-plane construction [FuSe94] gives the best known constant, f(n)≤(2/3+o(1))nf(n)\le(2/\sqrt3+o(1))\sqrt n for all large nn ([[problems/extremal_graph_theory/E0133/claims/1994_01_01_furedi_seress|claim page]]); the last two are refereed and settle the problem. The constant, between 11 and 2/32/\sqrt3, is not asked and is open; Alon's 2024 note, also cited on Problem 134, conjectures f(n)∼nf(n)\sim\sqrt n, and one unreviewed proof claim of 2026-09-15 on the site's proof-claim tab asserts that the constant is 11 ([[problems/extremal_graph_theory/E0133/claims/2026_09_15_korsky|claim page]]). A Lean development attributed to Hanson and Seyffarth's result is linked from their claim page and is not built here. Search scope, 2026-10-07: the site's commentary, its comment thread (empty) and its proof-claim tab.

Source. erdosproblems.com/133, accessed 2026-09-04. Cite as: T. F. Bloom, Erdős Problem #133, https://www.erdosproblems.com/133.

References.

  • [Er97b] Erdős, Paul, Some old and new problems in various branches of combinatorics. Discrete Math. 165/166 (1997), 227--231, DOI 10.1016/S0012-365X(96)00173-2; item 7, p. 229: the definition of f(n)f(n), the Erdős--Pach conjecture f(n)/n1/2→∞f(n)/n^{1/2}\to\infty and Simonovits's Kneser graph with f(n)<n1−cf(n)<n^{1-c} for n=(3m−1m)n=\binom{3m-1}m, which leaves the question open. Library home: erdos_1997_some_old_new_problems_various_branches_combinatorics.
  • [FuSe94] Füredi, Zoltán and Seress, Ákos, Maximal triangle-free graphs with restrictions on the degrees. J. Graph Theory 18 (1994), no. 1, 11-24, DOI 10.1002/jgt.3190180103 (Crossref record accessed); Theorem 6.1, Section 6. Library home: furedi_1994_maximal_triangle_free_graphs_restrictions_degrees.
  • [HaLe18] Haviv, Ishay and Levy, Dan, Symmetric complete sum-free sets in cyclic groups. Israel J. Math. 227 (2018), no. 2, 931-956, DOI 10.1007/s11856-018-1754-5 (Crossref record accessed); arXiv:1703.04118; Theorem 1.5 and the Section 1 remark on regular triangle-free graphs of diameter 22. Library home: haviv_2018_symmetric_complete_sum_free_sets_cyclic.
  • [HaSe84] Hanson, D. and Seyffarth, K., kk-saturated graphs of prescribed maximum degree. Congr. Numer. (1984), 169-182; [FuSe94] cites volume 42, pp. 169-182, and [HaLe18] cites volume 44, pp. 127-138.

Formalization. The formal-conjectures statement file ErdosProblems/133.lean, added on 2026-09-20 and shown on the site's page as the formalized statement, defines f(n)f(n) as the least possible maximum degree and marks erdos_133 (the divergence question, answered false) and erdos_133.variants.isTheta (the order n\sqrt n) research solved, each with a formal_proof pointer to the declaration erdos_133 of Erdos133.lean in Boris Alexeev's repository plby/lean-proofs, a Lean development that declares itself a formalization of Hanson and Seyffarth's result and is linked from their claim page; the variant asking whether f(n)∼nf(n)\sim\sqrt n is research open. Nothing is built, kernel-checked or audited here, so the standing rests on the refereed papers.

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