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Problem 604

../

claims/: The 1 claim page of Problem 604, one per claimant's result; the problem's standing derives from them.


Statement. Given nn distinct points A⊂R2A\subset\mathbb{R}^2 must there be a point x∈Ax\in A such that

#{d(x,y):y∈A}≫n1−o(1)?\#\{ d(x,y) : y \in A\} \gg n^{1-o(1)}?

Or even ≫n/log⁡n\gg n/\sqrt{\log n}?

Status. Open.

Source. erdosproblems.com/604, accessed 2026-09-04. Cite as: T. F. Bloom, Erdős Problem #604, https://www.erdosproblems.com/604.

References.

  • [Er75f] Erdős, Paul, On some problems of elementary and combinatorial geometry. Ann. Mat. Pura Appl. (4) (1975), 99-108.
  • [Er97e] Erdős, Paul, Some of my favourite unsolved problems. Math. Japon. (1997), 527-537.
  • [KaTa04] Katz, Nets Hawk and Tardos, Gábor, A new entropy inequality for the Erdős distance problem. Towards a theory of geometric graphs (2004), 119-126.

Formalization. No statement of the problem's question is recorded. The Lean proof of the first question in its ε\varepsilon form is recorded on its claim page.

Current assessment

The standing is derived from the claim pages in claims/. The one claim is [[problems/distance_problems/E0604/claims/2026_09_23_openai|OpenAI's weak pinned planar distance theorem]], an accepted partial claim: for every fixed ε>0\varepsilon>0 and every sufficiently large nn, every nn-point planar set has a point from which at least n1−εn^{1-\varepsilon} distinct distances are seen, uniformly over sets, which is the first question's bound n1−o(1)n^{1-o(1)} answered yes; it is accepted on the Lean declarations built and audited here. The second question, whether some point sees ≫n/log⁡n\gg n/\sqrt{\log n} distinct distances, is not settled by the claim, so the problem is open; the site's remarks note that the integer grid shows that this bound would be best possible. The same claim's statement for all points, that for each fixed ε\varepsilon the proportion of points seeing fewer than n1−εn^{1-\varepsilon} distances tends to zero, also speaks to the site's remark that there may be ≫n\gg n such points, for each fixed ε\varepsilon; a comment on the site notes that ≫n\gg n such points follow from the existence of one. The release's companion manuscript in the same family, A power saving for planar unit distances, bounds the number of unit distances in the plane and concerns Problem 1085, where it is recorded on its claim page; it settles nothing asked here and has no claim page in this folder. The search scope is the site's page export of 2026-09-04 (last edited on the site on 23 March 2026, labeled OPEN), its proof-claims tab, which listed no claim on 2026-10-06, and the release of 23 September 2026, whose manuscript is carded at openai_2026_weak_pinned_planar_distance_theorem.

Progress

[[problems/distance_problems/E0604/claims/2026_09_23_openai|OpenAI's Theorem 1.1 and Corollary 1.2]] give, for every fixed ε>0\varepsilon>0, that all but o(n)o(n) points of an nn-point planar set see at least n1−εn^{1-\varepsilon} distinct distances, with no hypothesis on the set and no rate of decay; the proof moves each configuration into a number field, factors squared distances through the coordinates u±ivu\pm iv, and turns the product formula into an overlap identity for nested grid partitions. The claim page records the Lean statements, their audit and the built declarations. Before the release the best bound was ≫nc−o(1)\gg n^{c-o(1)} with c=(48−14e)/(55−16e)=0.864137…c=(48-14e)/(55-16e)=0.864137\ldots, due to Katz and Tardos [KaTa04], as the site records.

Known Results

The site's remarks (export of 2026-09-04) place the problem as the pinned form of Problem 89, the distinct distances problem, and record the following. The integer grid shows that n/log⁡nn/\sqrt{\log n} would be best possible. Erdős conjectured in [Er75f] the average form ∑x∈Ad(x)≫n2/log⁡n\sum_{x\in A}d(x)\gg n^2/\sqrt{\log n}, where d(x)d(x) is the number of distinct distances from xx. In [Er97e] he offered a prize for a solution, without making clear whether the prize is for one such point or for ≫n\gg n of them, and wrote that he had at first expected the pinned count to behave like the total count of distinct distances, which Harborth showed to be false; the two could still agree up to a factor no(1)n^{o(1)}.

Linked library material

These entries are derived from explicit links on library pages. They are navigation only and do not by themselves record mathematical progress.