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Problem 452

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claims/: The 1 claim page of Problem 452, one per claimant's result; the problem's standing derives from them.


Statement. Let ω(n)\omega(n) count the number of distinct prime factors of nn. What is the size of the largest interval I⊆[x,2x]I\subseteq [x,2x] such that ω(n)>log⁡log⁡n\omega(n)>\log\log n for all n∈In\in I?

Status. Open, the site's label (page last edited 28 October 2025). One pending partial claim, White's weighted-sieve upper bound, bounds the longest run from above without determining its size, so the derived standing is open with no full claim.

Source. erdosproblems.com/452, accessed 2026-09-04. Cite as: T. F. Bloom, Erdős Problem #452, https://www.erdosproblems.com/452.

References.

  • [Er37] Erdős, Paul, Note on the number of prime divisors of integers. J. London Math. Soc. (1937), 308-314.

Formalization. Statement in formal-conjectures.

Current assessment

The question (site formulation). With ω(n)\omega(n) the number of distinct prime factors of nn, the size L(x)L(x) of the largest interval I⊆[x,2x]I\subseteq[x,2x] on which ω(n)>log⁡log⁡n\omega(n)>\log\log n throughout. The site labels the problem OPEN (page last edited 28 October 2025).

Standing. Open. One pending partial claim, White's report of 2026-07-26 (claim page), bounds L(x)L(x) by exp⁡((1+o(1))log⁡x/log⁡log⁡x)\exp((1+o(1))\log x/\log\log x); it is not refereed and names no reviewer, and it does not determine L(x)L(x), so the derived standing stays open.

What is known. Erdős [Er37] proved that the integers with ω(n)>log⁡log⁡n\omega(n)>\log\log n have density 1/21/2. The Chinese remainder theorem gives an interval with ∣I∣≥(1+o(1))log⁡x/(log⁡log⁡x)2|I|\ge(1+o(1))\log x/(\log\log x)^2, and the site's commentary suggests that intervals of length (log⁡x)k(\log x)^k might exist for every kk. From above, a thread post of 4 July 2026 gives L(x)≤xO(1/log⁡log⁡x)L(x)\le x^{O(1/\sqrt{\log\log x})} by comparing the mean, variance and skewness of the count of prime factors below a power of the interval's length, and reports that Erdős and Graham knew no upper bound; White's report of 26 July 2026 improves this to exp⁡((1+o(1))log⁡x/log⁡log⁡x)\exp((1+o(1))\log x/\log\log x) by a weighted sieve, crediting the argument to GPT-5.6 Sol; a thread post of 28 September 2026 proves L(x)≤x(1+ε)/log⁡log⁡xL(x)\le x^{(1+\varepsilon)/\log\log x} for every ε>0\varepsilon>0 by a Brun sieve, cites the report, tabulates L(x)L(x) for xx from 10610^6 to 5.3×1085.3\times10^8 and conjectures L(x)≍log⁡xL(x)\asymp\log x. Between log⁡x/(log⁡log⁡x)2\log x/(\log\log x)^2 and xo(1)x^{o(1)} the size is undetermined, and neither thread post is a dated manuscript, so neither has a claim page.

Search scope. The site's page, its two comments and its empty proof-claims tab, the report, the formal-conjectures statement file and the community database; no other literature search was made.

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