Wiki
Wiki

Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

Updated


Statement

Setting. Cross-IU is defined on the Theorem 9 page: every member of one family meets every member of the other, and no such pair has union [n][n].

Theorem 10 (p. 3). If A1,A2,…,Ad⊂2[n]\mathcal A_1,\mathcal A_2,\dots,\mathcal A_d\subset2^{[n]} are pairwise cross-IU, then

∑i=1d∣Ai∣≤max⁡{2n, d⋅2n−2}.\sum_{i=1}^d|\mathcal A_i|\le\max\{2^n,\,d\cdot2^{n-2}\}.

The paper adds (p. 3, quoted) that "the equality holds only if d≤4d\le4 and A1=2[n]\mathcal A_1=2^{[n]} [sic] for some ii or d≥4d\ge4 and A1=…=Ad\mathcal A_1=\ldots=\mathcal A_d", the index 11 standing where ii is evidently meant. It compares the result with Hilton's theorem for pairwise intersecting families of kk-sets.

Theorem 12 (p. 7). If A,B⊂2[n]\mathcal A,\mathcal B\subset2^{[n]} are cross-IU and ∣A∣≥∣B∣|\mathcal A|\ge|\mathcal B|, then

∣A∣+3∣B∣≤2n.(14)|\mathcal A|+3|\mathcal B|\le2^n. \tag{14}

Corollary 1 (p. 6). If A1,…,Ad⊂2[n]\mathcal A_1,\dots,\mathcal A_d\subset2^{[n]} are pairwise cross-IU, d≥5d\ge5 and ∣A1∣≥∣A2∣≥⋯≥∣Ad∣|\mathcal A_1|\ge|\mathcal A_2|\ge\cdots\ge|\mathcal A_d|, then

∣A1∣+⋯+∣Ad∣≤d 2n−2,(13)|\mathcal A_1|+\cdots+|\mathcal A_d|\le d\,2^{n-2}, \tag{13}

with strict inequality unless A1=⋯=Ad\mathcal A_1=\cdots=\mathcal A_d.

Lemma 1 (p. 6). If d≥1d\ge1 and 1≤x≤d1\le x\le d, then x+d/x≤1+dx+d/x\le1+d (12).

The paper says Theorem 10 follows at once from Corollary 1 and Theorem 12. For d≥5d\ge5 this is Corollary 1, after ordering the families by size. For 2≤d≤42\le d\le4, ordering the families by size, Theorem 12 applied to the two largest gives ∑i∣Ai∣≤∣A1∣+3∣A2∣≤2n\sum_i|\mathcal A_i|\le|\mathcal A_1|+3|\mathcal A_2|\le2^n (the step spelled out on this page; d=1d=1 is trivial).

Proof pointer

Corollary 1, pp. 6--7: with ai=∣Ai∣/2n−2a_i=|\mathcal A_i|/2^{n-2}, (7) of Theorem 9 gives ai≤1/a1a_i\le1/a_1 for i≥2i\ge2, and Lemma 1 gives a1+(d−1)/a1≤da_1+(d-1)/a_1\le d when 1≤a1≤41\le a_1\le4; adding single sets to the families handles the equality case. Theorem 12, p. 7: with x=∣A∣/2nx=|\mathcal A|/2^n, y=∣B∣/2ny=|\mathcal B|/2^n, (7) gives xy≤1/16xy\le1/16, which settles x≤3/4x\le3/4; for x=1−zx=1-z with 0≤z≤1/40\le z\le1/4, Harris–Kleitman applied to the generated up-sets and down-sets gives y≤z2(1−z)<z/4y\le z^2(1-z)<z/4.

Read depth

Claims checked: Theorem 10 with its equality remark, Lemma 1, Corollary 1 and Theorem 12 were read clause by clause on the print, and their proofs on pp. 6--7 were followed for their structure and not checked line by line. Nothing here is independently reviewed.

Dependencies

Theorem 9; external input named by the paper: the Harris–Kleitman inequality (its Theorem 2, p. 2).

Source. P. Frankl and A. Kupavskii, Perfect matchings in down-sets, Discrete Math. 346 (2023), Paper No. 113323, DOI 10.1016/j.disc.2023.113323; read in arXiv:2201.03865v1, Theorem 10 on p. 3, Lemma 1 and Corollary 1 on p. 6, Theorem 12 on p. 7, with proofs on pp. 6--7. The edition is identified on the source card.

Bears on

No Erdős problem in the corpus is linked to these bounds.