Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
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Statement
The paper's notation and the set of systems are those of Theorem 1; consists of the systems of subsets of , each of at most elements, no member containing another, any two members sharing at least two elements.
Example (p. 319). For , the -subsets of with form a system in with
members. The paper notes that this exceeds , the bound of Theorem 2 (b), for every large , possibly for every . The paper introduces it as a more general example than S. H. Min's example of p. 318: the 4-subsets of with , sixteen sets forming a system in , against .
Conjecture (p. 319). The authors conjecture that for these values of the example is a case of largest : if and , then
The conjecture covers systems whose members may have fewer than elements, provided no member contains another; the example has all members of size .
Source. P. Erdős, Chao Ko and R. Rado, Intersection theorems for systems of finite sets, Quart. J. Math. Oxford Ser. (2) 12 (1961), 313–320, as identified on the source card: concluding remark (i), pp. 318–319, with the conjecture on p. 319.
Read depth. Claims checked: the example, its count and the conjecture were read clause by clause on the print. Nothing here is independently reviewed.
Proof pointer
A conjecture; the paper proves only the count of the example, by summing over and using the symmetry (p. 319).
Dependencies
None.
Bears on
- Problem 83: the problem's statement, with its the paper's , is the conjecture restricted to systems all of whose members have exactly elements, for which the incomparability condition is automatic. The paper poses the conjecture and gives the example showing the bound would be attained. For it proves no bound of that size: Theorem 2 (a) applies to this case, but its bound is larger (that comparison is arithmetic, not stated in the paper).