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Doorn 2025 improved bounds mayer erdos phenomenon similarly

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lemma_2: Van Doorn's 2025 lemma behind his lower bound for Problem 1005: two Farey fractions of order n that enclose a Farey fraction a/b are similarly ordered whenever their index distance is at most (n + b + 1)/(2b).

theorem_1: Van Doorn's 2025 upper bound for the largest guaranteed run of similarly ordered Farey fractions of order n: f(n) is at most floor(n/4) + d with d = 1, 2, 2, 4 according to n modulo 4, by explicit badly ordered pairs around 1/2; conjectured to be exact for all n >= 92 and checked up to 5000.

theorem_2: Van Doorn's 2025 lower bound for Problem 1005: two Farey fractions of order n at index distance at most (n/12)(1 - 4 n^{-1/3}) are similarly ordered, so f(n) is at least (1/12 - o(1)) n; an optimization of Erdős's 1943 argument, improving the constants 1/400 (Erdős) and 1/480 (Zaharescu).

theorem_3: Van Doorn's 2025 local-density form of his lower bound for Problem 1005: two Farey fractions of order n that differ by x/n either enclose a Farey fraction of denominator below 6/x or are more than nx(1/12 - o(1)) places apart in the sequence.


Wouter van Doorn, Improved bounds for the Mayer-Erdős phenomenon on similarly ordered Farey fractions, arXiv:2509.00121 (2025). The site's key vD25b.

The copy read for this card is arXiv:2509.00121v1 (28 August 2025), 9 pages with a text layer whose plus signs drop out of the extracted text; the statements below were read on the rendered page images of pp. 1--9. The abstract page lists one version and no journal reference, and no journal record was found (Crossref bibliographic query, 2026-09-18): a preprint. Source: https://arxiv.org/abs/2509.00121. The arXiv record names arXiv's non-exclusive distribution license (arXiv:2509.00121), every other right reserved.

Read status: claims checked for the definition of f(n)f(n), the history paragraph, Theorem 1 with the Conjecture and the list of exceptional nn, Lemmas 1--6 as statements, Theorem 2 and Theorem 3, read clause by clause on the page images (pp. 1--8); the proofs of Theorems 1 and 2 were read for structure and not checked.

For the Farey sequence a1/b1,a2/b2,…a_1/b_1,a_2/b_2,\ldots of order n≥4n\ge4, van Doorn studies f(n)f(n), the largest integer such that (al−ak)(bl−bk)≥0(a_l-a_k)(b_l-b_k)\ge0 (the fractions are "similarly ordered") whenever ∣l−k∣≤f(n)|l-k|\le f(n); the condition n≥4n\ge4 ensures a non-similarly-ordered pair exists (1/41/4 and 2/32/3). Theorem 1 gives the upper bound f(n)≤⌊n/4⌋+df(n)\le\lfloor n/4\rfloor+d with d=1,2,2,4d=1,2,2,4 according to n mod 4n\bmod4, via explicit Farey neighborhoods of fractions like (2m−1)/(4m)(2m-1)/(4m) together with the standard criterion bc−ad=1bc-ad=1 and max⁡(b,d)≤n<b+d\max(b,d)\le n<b+d for consecutive Farey fractions; a conjecture (checked for all n≤5000n\le5000, with the fifteen exceptions below 9292 listed) asserts this is exactly f(n)f(n) for n≥92n\ge92. On the lower side, Lemma 2 shows that fractions bracketing a fraction a/ba/b of small denominator are similarly ordered whenever l−k≤(n+b+1)/(2b)l-k\le(n+b+1)/(2b), using the fact that numerators and denominators of Farey fractions adjacent to a/ba/b form arithmetic progressions; optimizing Erdős's argument, Theorem 2 yields f(n)≥⌊(n/12)(1−4/n1/3)⌋=(1/12−o(1))nf(n)\ge\lfloor(n/12)(1-4/n^{1/3})\rfloor=(1/12-o(1))n, improving Erdős's constant 1/4001/400 and Zaharescu's 1/4801/480 (the paper's account: Zaharescu generalized to arbitrary linear forms with c=1/480c=1/480, and Meng and Zaharescu to several variables). The paper reports no earlier improvement on Erdős's constant that its author was aware of; the site's account of Problem 1005 now rests on a 2026 preprint that claims the matching lower bound (1/4−o(1))n(1/4-o(1))n.

Contents

  • Introduction (p. 1): the definition of f(n)f(n); Mayer proved f(n)≥3f(n)\ge3 for n≥5n\ge5 (his first 1942 paper) and f(n)→∞f(n)\to\infty (his second); Erdős [3] proved f(n)>cnf(n)>cn, "his proof showed that one can take c=1/400c=1/400"; Zaharescu [4] (c=1/480c=1/480, linear forms) and Meng--Zaharescu [5]; "no improvements have occurred in the literature" since.
  • Theorem 1 (p. 2): f(n)≤⌊n/4⌋+df(n)\le\lfloor n/4\rfloor+d, d=1,2,2,4d=1,2,2,4 for $n\equiv0,1,2,3 \pmod4$, for all n≥4n\ge4; Lemma 1 (consecutive Farey fractions); the proof by the explicit segments around (2m−1)/(4m)(2m-1)/(4m) and 2m/(4m+1)2m/(4m+1); the Conjecture (f(n)>n/4f(n)>n/4 for all n≥4n\ge4; f(n)=⌊n/4⌋+df(n)=\lfloor n/4\rfloor+d for all n≥92n\ge92), checked for n≤5000n\le5000, with the exceptions $n=7,9,11,15, 19,23,25,27,31,35,39,49,51,63,91$; a stronger classification conjecture.
  • Section 3 (pp. 3--8): Lemma 2 (p. 3; bracketing a fraction a/ba/b: similarly ordered if l−k≤(n+b+1)/(2b)l-k\le(n+b+1)/(2b)); Lemma 3 (N>n2/4N>n^2/4 Farey fractions of order nn); Lemma 4 (Dress's discrepancy bound N(α−1/n)≤An(α)≤N(α+1/n)N(\alpha-1/n)\le A_n(\alpha)\le N(\alpha+1/n)); Theorem 2 (p. 5): if k<lk<l and l−k≤n12(1−4n1/3)l-k\le\frac n{12}(1-\frac4{n^{1/3}}) then ak/bka_k/b_k and al/bla_l/b_l are similarly ordered; Lemmas 5--6 and the proof (pp. 5--8) by splitting ∑1/(bibi+1)\sum1/(b_ib_{i+1}) as in Erdős.
  • Section 4 (p. 8): Theorem 3, a local-density form (either a Farey fraction with denominator below 6/x6/x lies between the two fractions or l−k>nx(1/12−o(1))l-k>nx(1/12-o(1)) when they are x/nx/n apart); the remark that for a badly ordered pair with ak/bk≥1/2−o(1)a_k/b_k\ge1/2-o(1) the argument gives l−k>n(1/8−o(1))l-k>n(1/8-o(1)), "at most a factor 2 off from optimal".

Compiled scope

The whole preprint was read. Theorems 1, 2 and 3 and Lemma 2 are compiled as statements with proof pointers; the computation behind the Conjecture was not rerun; no step of the proofs was checked and nothing here is independently reviewed.

Bears on. #1005: the same function f(n)f(n) as the problem's; Theorem 1 is the upper bound f(n)≤⌊n/4⌋+df(n)\le\lfloor n/4\rfloor+d the site prints as f(n)≤n/4+O(1)f(n)\le n/4+O(1), and Theorem 2 is the lower bound (1/12−o(1))n(1/12-o(1))n the site prints; the Conjecture that the upper bound is exact for n≥92n\ge92 is the statement the 2026 preprints address (asymptotically, and then exactly). Lemma 2 and Theorem 3 are not bounds on f(n)f(n): Lemma 2 gives similar ordering for pairs enclosing a Farey fraction a/ba/b when l−k≤(n+b+1)/(2b)l-k\le(n+b+1)/(2b) and is a step in the proof of Theorem 2, and Theorem 3 is the general form, in terms of the gap x/nx/n, of what that proof gives; neither improves the bound of Theorem 2. Theorems 1 and 2 are bounds on the problem's f(n)f(n) that the paper proves; the Conjecture is stated there, not proved.

Results to transcribe.

  • Theorem 1: for all n≥4n\ge4, f(n)≤⌊n/4⌋+df(n)\le\lfloor n/4\rfloor+d with d=1,2,2,4d=1,2,2,4 depending on n mod 4n\bmod4; in particular some k<l<k+n/4+5k<l<k+n/4+5 give (al−ak)(bl−bk)<0(a_l-a_k)(b_l-b_k)<0.
  • Theorem 2 (the lower bound): f(n)≥⌊n12(1−4n−1/3)⌋f(n)\ge\lfloor\frac n{12}(1-4n^{-1/3})\rfloor, hence f(n)≥(1/12−o(1))nf(n)\ge(1/12-o(1))n, improving Erdős's constant 1/4001/400 and Zaharescu's 1/4801/480.
  • Lemma 2 (p. 3): if ak/bk≤a/b≤al/bla_k/b_k\le a/b\le a_l/b_l are Farey fractions of order nn and l−k≤(n+b+1)/(2b)l-k\le(n+b+1)/(2b), then ak/bka_k/b_k and al/bla_l/b_l are similarly ordered.
  • Theorem 3 (p. 8): if al/bl−ak/bk=x/na_l/b_l-a_k/b_k=x/n with x>0x>0, then either a Farey fraction a/ba/b with b<6/xb<6/x satisfies ak/bk≤a/b≤al/bla_k/b_k\le a/b\le a_l/b_l, or l−k>nx(1/12−o(1))l-k>nx(1/12-o(1)).
  • Conjecture: for n≥92n\ge92, f(n)f(n) equals ⌊n/4⌋+d\lfloor n/4\rfloor+d exactly with dd as in Theorem 1; checked by computer for all n≤5000n\le5000.

No file of this source is held: no license on record permits its redistribution, and the card cites the edition it names above.