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Statement

Setting (pp. 2--3). The lemma concerns the random sequence of Section 2. For large nn, Pn\mathcal P_n is the set of primes in In=[en,en+1/(10n)]I_n=[e^{\sqrt n},e^{\sqrt n+1/(10\sqrt n)}]. The integer n0n_0 is so large that the intervals InI_n, n≥n0n\ge n_0, are disjoint, that ∣Pn∣≫en/n|\mathcal P_n|\gg e^{\sqrt n}/n for n≥n0n\ge n_0 (the paper's (1)), and that at least n0−1n_0-1 primes lie below en0e^{\sqrt{n_0}}. The terms u1<⋯<un0−1u_1<\cdots<u_{n_0-1} are fixed primes below en0e^{\sqrt{n_0}}, and for each n≥n0n\ge n_0 the term unu_n is drawn uniformly from Pn\mathcal P_n, independently of the others. With the constant BB of the paper's (4), put

Nt=exp⁡(23(t+1)3/2+Bt),N_t=\exp\Bigl(\frac23(t+1)^{3/2}+B\sqrt t\Bigr),

which bounds u1⋯ut+1u_1\cdots u_{t+1} for every outcome and all large tt.

Lemma 1 (Certificate exclusion, p. 3). Fix C≥1C\ge1 and η>0\eta>0, and for each tt write M=⌈(1+η)t⌉M=\lceil(1+\eta)t\rceil. There is an integer K0=K0(C,η)K_0=K_0(C,\eta) such that, with probability one, for every sufficiently large tt no integer nn with 0≤n<Nt0\le n<N_t admits distinct indices i1,…,iM>K0i_1,\dots,i_M>K_0 and positions j1,…,jMj_1,\dots,j_M with 1≤jr≤Ct1\le j_r\le Ct and

uir∣n+jr(1≤r≤M).u_{i_r}\mid n+j_r\qquad(1\le r\le M).

The integer K0K_0 comes before the almost-sure quantifier and does not depend on the outcome; the threshold beyond which tt counts as large may. The indices must be distinct and the positions need not be. The proof calls such a configuration a certificate at level tt (p. 5).

Source. Peter Li, A Subexponential Good Sequence, manuscript dated April 27, 2026, 7 pp.; the construction on pp. 2--3, Lemma 1 on p. 3 and its proof on pp. 3--5. The edition read is identified on the source card.

Read depth. Claims checked: the statement and the construction it concerns were read clause by clause on the page images of pp. 2--3. The proof was read through for structure only; no step of it was checked.

Proof sketch

The steps as the manuscript presents them (pp. 3--5); none was checked here. Fix β<1\beta<1 with β(1+η)3/2>1\beta(1+\eta)^{3/2}>1, the paper's (5). For N=n+jN=n+j with n<Ntn<N_t and 1≤j≤Ct1\le j\le Ct one has log⁡N≪t3/2\log N\ll t^{3/2}, and the primes of IiI_i are at least eie^{\sqrt i}, so at most log⁡N/i\log N/\sqrt i of them divide NN. With (1) this gives P(ui∣N)≪t3/2i e−i\mathbb P(u_i\mid N)\ll t^{3/2}\sqrt i\,e^{-\sqrt i} (7), and with K0≥n0K_0\ge n_0 large in terms of β\beta it gives P(ui∣N)≤min⁡{1,t2e−βi}\mathbb P(u_i\mid N)\le\min\{1,t^2e^{-\beta\sqrt i}\} whenever i>K0i>K_0 and tt is large ((8), (9)). Terms with distinct indices are independent, so a fixed certificate has probability at most the product of these bounds. The sum SM(t)S_M(t) of these products over increasing index tuples is at most the coefficient of wMw^M in ∏i≥1(1+wt2e−βi)\prod_{i\ge1}(1+wt^2e^{-\beta\sqrt i}), hence at most z−Mz^{-M} times that product for any z>0z>0. Taking z=eα/t2z=e^\alpha/t^2, an integral comparison makes the logarithm of the product α3/(3β2)+Oβ(α2)\alpha^3/(3\beta^2)+O_\beta(\alpha^2) (10), and α=βM\alpha=\beta\sqrt M gives SM(t)≤exp⁡(−2β3M3/2+o(t3/2))S_M(t)\le\exp(-\frac{2\beta}3M^{3/2}+o(t^{3/2})) (11). With at most Nt+1N_t+1 choices of nn and (Ct)M(Ct)^M of positions, the expected number XtX_t of certificates at level tt is at most exp⁡((23−2β3(1+η)3/2)t3/2+o(t3/2))\exp\bigl((\frac23-\frac{2\beta}3(1+\eta)^{3/2})t^{3/2}+o(t^{3/2})\bigr), which by (5) is at most e−ct3/2e^{-ct^{3/2}} for some c=c(C,η)>0c=c(C,\eta)>0 and all large tt. Hence ∑tP(Xt>0)<∞\sum_t\mathbb P(X_t>0)<\infty, and the Borel--Cantelli lemma gives Xt=0X_t=0 for all large tt almost surely.

Dependencies

The construction of Section 2 with its displays (1) and (4) (pp. 2--3), which rest on the prime number theorem with the de la Vallée Poussin error term; the Borel--Cantelli lemma (p. 5).

Bears on

  • Problem 1101: the lemma is the probabilistic input of Theorem 1. Section 4 turns a gap of length at least (1+ε)txD−1(1+\varepsilon)t_xD^{-1} into a certificate, so an outcome satisfying the lemma for every integer C≥1C\ge1 and rational η>0\eta>0 is good. On its own the lemma does not answer the problem.