Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
Updated
Statement
Theorem 2 (p. 117). Let and let be such that is squarefree for all , . Then (display (2)).
The print's display (2) reads , without the cardinality bars; the proof (p. 122) bounds the number of elements. The threshold is not made explicit.
Proof pointer
Sections 3 and 4, pp. 120--122. Lemma 1 (p. 120) is the large sieve inequality, taken from Montgomery's Topics in Multiplicative Number Theory (Corollary 2.2, p. 12). Lemma 2 (p. 120) is a large sieve by squares of primes derived from it: for integers and and a set of integers in , with the number of its elements congruent to modulo , for every . For Theorem 2 (section 4), confines to at most residue classes modulo , so at least classes are empty and the left side of Lemma 2 is at least . Taking and the prime number theorem give for large .
Read depth
Claims checked: the statement and Lemmas 1 and 2 were read clause by clause on the page images of the print, and the derivation of Theorem 2 from Lemma 2 on pp. 121--122 was followed. The proof of Lemma 2 was read for structure; Lemma 1 is cited, not proved, in the paper. Nothing here is independently reviewed.
Dependencies
None in the corpus. External inputs: the large sieve inequality and the identities for that the paper takes from Montgomery's book (pp. 12, 23 and 24 there), and the prime number theorem.
Source. P. Erdős and A. Sárközy, On divisibility properties of integers of the form , Acta Math. Hungar. 50 (1987), no. 1--2, 117--122, doi:10.1007/BF01903370; the edition read is named on the source card.
Bears on
- Problem 1109: gives for . This is far from the bounds and the problem asks about, so it answers neither question.
- Problem 1103: the paper says nothing about infinite sequences. Applied to the terms up to of an infinite sequence of positive integers whose pairwise sums are all squarefree, Theorem 2 bounds their number by for , which forces growth ; this does not settle how fast such a sequence must grow.