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Statement

As printed on p. 6 of the preprint (arXiv:math/0410218v1; page image): "Theorem 2 Let r≥2r\ge2, n≥rn\ge r, m≥tr(n)m\ge t_r(n) and let G=G(n,m)G=G(n,m) be a graph which is not regular. Then there exists a P\mathfrak P-sequence v1,…,vrv_1,\dots,v_r such that

∑i=1rd(vi)>2rmn.\sum_{i=1}^rd(v_i)>\frac{2rm}n.

"

Here G(n,m)G(n,m) is a graph with nn vertices and mm edges, tr(n)t_r(n) the number of edges of the rr-chromatic Turán graph Tr(n)T_r(n), and a P\mathfrak P-sequence is a vertex sequence produced by Faudree's greedy algorithm P\mathfrak P (p. 3): v1v_1 a vertex of maximum degree, and each viv_i a common neighbor of v1,…,vi−1v_1,\dots,v_{i-1} of maximum degree, the algorithm stopping when no common neighbor is left; by construction the terms of a P\mathfrak P-sequence are pairwise adjacent, so v1,…,vrv_1,\dots,v_r is an rr-clique. The section's opening (p. 6) states the consequence the theorem is for: every G(n,m)G(n,m) with m≥tr(n)m\ge t_r(n) contains an rr-clique RR with ∑i∈Rd(i)≥2rm/n\sum_{i\in R}d(i)\ge2rm/n (display (13)), which "is trivial for regular graphs" (every vertex then has degree 2m/n2m/n, and Theorem 1(i) gives an rr-clique) and holds with strict inequality otherwise by this theorem. In the catalog's notation, with x1,…,xrx_1,\dots,x_r the clique, d(x1)+⋯+d(xr)≥2rm/nd(x_1)+\dots+d(x_r)\ge2rm/n whenever m≥tr(n)m\ge t_r(n): the statement of Problem 904, proved for every n≥rn\ge r.

Source. B. Bollobás and V. Nikiforov, The sum of degrees in cliques, Electron. J. Combin. 12 (2005), N21; p. 6 of arXiv v1, read on the rendered page image and in the text layer (the journal text was not compared). The edition read is identified in the source digest.

Read depth. Claims checked: the theorem, the opening paragraph of Section 3 and display (13) were read clause by clause on the page image; the proof (pp. 6--7) was read and followed but not checked step by step.

Proof pointer

Pp. 6--7. Theorem 1(iii) (p. 3) gives a P\mathfrak P-sequence 1,…,r1,\dots,r with ∑i=1rd(i)>(r−1)n\sum_{i=1}^rd(i)>(r-1)n, hence ∑i=1sd(i)>(s−1)n\sum_{i=1}^sd(i)>(s-1)n for every s≤rs\le r (display (14)). Part (a) partitions VV by the sets of common neighbors of the initial segments (display (15)) and bounds ∣Vi∣≤n−d(i)|V_i|\le n-d(i) through the inclusion--exclusion inequality (3), giving 2m≤n∑d(i)−∑d2(i)+d(r)(∑d(i)−n(r−1))2m\le n\sum d(i)-\sum d^2(i)+d(r)(\sum d(i)-n(r-1)); part (b) uses d(r)≤Sr/rd(r)\le S_r/r and Cauchy's inequality to get 2m≤nSr/r2m\le nS_r/r, that is Sr≥2rm/nS_r\ge2rm/n (display (16)), with equality only when d(1)=⋯=d(r)d(1)=\dots=d(r), so that the maximum degree equals the average degree and GG is regular. Not reconstructed here.

Dependencies

Theorem 1 of the paper (p. 3): every P\mathfrak P-sequence in a G(n,m)G(n,m) with m≥tr(n)m\ge t_r(n) has at least rr terms, the first rr have degree sum at least (r−1)n(r-1)n, and equality forces m=tr(n)m=t_r(n); and the elementary inequalities (3) and (4) of Section 1.1.

Bears on

  • Problem 904: the status-defining theorem, with the trivial regular case, for every r≥2r\ge2, n≥rn\ge r and m≥tr(n)m\ge t_r(n); the site's "The full conjecture was proved by Bollobás and Nikiforov".