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Source. Theorem 1.1, Section 1, p. 2 of arXiv:2406.19491v1 (27 June 2024), the edition named on the source card; the definition of well-distribution on p. 1, the proof in Section 2 on pp. 2-4. Read on the PDF page images.

Statement

Notation (p. 1). (pn)(p_n) is the sequence of primes, 2=p1<p2<…2=p_1<p_2<\ldots, and {s}=s−⌊s⌋\{s\}=s-\lfloor s\rfloor. A real sequence (sn)(s_n) is well-distributed modulo 11 (a notion the paper credits to Petersen, 1956) when, for each pair a,ba,b with 0≤a<b≤10\le a<b\le1,

lim⁡N→∞ sup⁡m∈N∣card⁡{n∈[1,N]∩Z: a≤{sn+m}≤b}N−(b−a)∣=0.\lim_{N\to\infty}\ \sup_{m\in\mathbb N}\left| \frac{\operatorname{card}\{n\in[1,N]\cap\mathbb Z:\ a\le\{s_{n+m}\}\le b\}}{N} -(b-a)\right|=0 .

Theorem 1.1 (p. 2). "There exists an irrational number α\alpha having the property that the sequence (αpn)(\alpha p_n) is not well-distributed modulo 1."

The paper remarks (p. 2) that its proof constructs many such α\alpha, each transcendental; the α\alpha of the proof is ∑k≥02−nk\sum_{k\ge0}2^{-n_k}, shown transcendental in Lemma 2.1. By Vinogradov's theorem, which the paper recalls on p. 1, (αpn)(\alpha p_n) is equidistributed modulo 11 for every irrational α\alpha, so the theorem separates equidistribution from well-distribution along the primes.

Read depth. Claims checked: the definition and the theorem were read clause by clause on the page images, and the proof (pp. 2-4) was read in full. Nothing here is independently reviewed.

Proof pointer

Section 2, pp. 2-4. As a consequence of Shiu's theorem, for each nn there is m=m(n)m=m(n) with pm+1≡⋯≡pm+n≡1(mod2n)p_{m+1}\equiv\cdots\equiv p_{m+n}\equiv1\pmod{2^n} (2.2), and by Theorem 1(i) of Shiu (J. London Math. Soc. (2) 61, 2000), for large nn one may take m(n)<exp⁡4(n)m(n)<\exp_4(n). Put n0=1n_0=1, mk=m(nk)m_k=m(n_k), πk=pmk+nk\pi_k=p_{m_k+n_k}, nk+1=4πkn_{k+1}=4\pi_k and α=∑k≥02−nk\alpha=\sum_{k\ge0}2^{-n_k} (2.1). From Petersen's Theorems 2 and 3, (αpn)(\alpha p_n) is well-distributed modulo 11 if and only if, for each h∈Nh\in\mathbb N, the supremum over m∈Nm\in\mathbb N of ∣N−1∑n=1Ne(hαpn+m)∣\bigl|N^{-1}\sum_{n=1}^N e(h\alpha p_{n+m})\bigr| tends to 00 as N→∞N\to\infty (2.3). Lemma 2.2 (p. 3): for each positive integer hh and every large kk, ∥hα(pi+mk−1)∥<πk−2\|h\alpha(p_{i+m_k}-1)\|<\pi_k^{-2} for 1≤i≤nk1\le i\le n_k. Hence on the block of shift mkm_k the terms e(hαpn+mk)e(h\alpha p_{n+m_k}) all lie within πk−1\pi_k^{-1} of e(hα)e(h\alpha), the supremum in (2.3) is at least 1−1/N1-1/N for every NN, and its limit is 11 (2.4), so (2.3) fails.

The paper adds (p. 4) that the case h=1h=1 of (2.4) already suffices, and that α\alpha may be replaced by β=∑k≥0bkq−nk\beta=\sum_{k\ge0}b_kq^{-n_k} for an integer q≥2q\ge2 and positive integers bkb_k "not growing too rapidly", with (βpn)(\beta p_n) still not well-distributed; that remark is stated without a separate proof.

Dependencies

Lemma 2.1 for the irrationality of α\alpha; Shiu's theorem on strings of congruent primes; Petersen's criterion (Quart. J. Math. Oxford (2) 7, 1956, Theorems 2 and 3).

Bears on

  • Problem 997: the problem asks whether, for every α\alpha, the sequence {αpn}\{\alpha p_n\} is not well-distributed. The theorem gives this conclusion for one irrational, indeed transcendental, α\alpha (and the many variants the paper describes), not for every α\alpha. The paper's definition fixes a closed interval [a,b][a,b] and asks for the limit uniformly in the shift; the problem's statement asks for a bound uniform in both the shift and the interval I⊆[0,1]I\subseteq[0,1], so a failure in the paper's sense is a failure in the problem's. The paper does not cite Erdős or the problem.