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Statement

Setting (p. 141). P{3,4}(x)P_{\{3,4\}}(x) counts the elements n≤xn\le x of Σ(Pow({3,4}),0)\Sigma(\mathrm{Pow}(\{3,4\}),0), the set of sums of distinct powers 3i3^i and distinct powers 4j4^j with i,j≥0i,j\ge0, the empty sum included (see Theorem 4 for the general notation). kk is the function on D=[1,4/3]D=[1,4/3] of the paper's Definition 1 (p. 142; see Lemma 3).

Proposition 5 (p. 147, quoted). "Let P{3,4}(x)P_{\{3,4\}}(x) be the counting function of Σ(Pow({3,4}),0)\Sigma(\mathrm{Pow}(\{3,4\}),0). We have"

lim inf⁡x→∞P{3,4}(x)x≤k(1)=10151458≃0.69616.(7)\liminf_{x\to\infty}\frac{P_{\{3,4\}}(x)}{x}\le k(1)=\frac{1015}{1458}\simeq0.69616.\qquad(7)

The value k(1)=1015/1458k(1)=1015/1458 is Lemma 3. The proposition bounds the lower density from above; it gives no positive lower bound for it.

Source. M. F. Hasler and G. Melfi, On sums of distinct powers of 3 and 4, Combinatorics and Number Theory 13 (2024), no. 2, 141--148, doi:10.2140/cnt.2024.13.141: the bound announced on p. 142, Proposition 5 on p. 147 and its proof on pp. 147--148. The edition read is identified on the source card.

Read depth. Claims checked: the statement was read clause by clause on the printed page. The proof was read but not checked step by step. Nothing here is independently reviewed.

Proof pointer

Pp. 147--148. For each ε>0\varepsilon>0 it suffices to find arbitrarily large xx with P{3,4}(x)/x<k(1)+εP_{\{3,4\}}(x)/x<k(1)+\varepsilon. Because log⁡4/log⁡3\log4/\log3 is irrational, for every δ>0\delta>0 there are infinitely many m,lm,l with 3m<4l<(1+δ)3m3^m<4^l<(1+\delta)3^m. Along such mm the paper takes x=3m+5−1x=3^{m+5}-1 and, from the structure developed for Theorem 4, bounds the limit of P{3,4}(x)/xP_{\{3,4\}}(x)/x by k(1+δ)k(1+\delta). Continuity of kk near 11 (Lemma 2) makes k(1+δ)<k(1)+εk(1+\delta)<k(1)+\varepsilon for small δ\delta, and Lemma 3 supplies the value of k(1)k(1).

Dependencies

Lemma 2 (p. 142, continuity of kk on D∖{39/47}D\setminus\{3^9/4^7\}) and Lemma 3 of the same paper.

Bears on

  • Problem 125: the problem asks whether A+BA+B has positive lower density, where AA and BB are the integers with only digits 0,10,1 in base 33 and in base 44; that sumset is Σ(Pow({3,4}),0)\Sigma(\mathrm{Pow}(\{3,4\}),0). Proposition 5 shows its lower density is at most 1015/14581015/1458. An upper bound below 11 does not decide whether the lower density is positive, and the paper does not settle it.