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Translated geometric progressions and covering systems
lemma_5: Porubský's lemma that for every finite covering system there are a translated geometric progression and an admissible set of primes on it whose associated system of classes n(p) mod e(p) is that covering system.
theorem_1: Porubský's theorem that for every prime q dividing the least common multiple of the moduli of an irredundant covering system of k > 1 classes, at least q classes have moduli divisible by the full power of q, their residues meet every class mod q, and the sum of q^{-f(i,q)} is at least 1.
theorem_2: Porubský's theorem that in an irredundant covering system any two moduli are joined by a chain of moduli of the system in which consecutive moduli share a common factor, with its corollary that no modulus is coprime to all the others.
theorem_3: Porubský's theorem that in an irredundant covering system of k > 1 residue classes the least common multiple of the moduli, and so each modulus, is at most q 2^{k-q} for every prime q dividing a modulus, hence at most 2^{k-1}, a bound the paper says is attained for every k.
theorem_4: Porubský's theorem that when r^{m}-1 has enough primitive prime factors for each modulus m of a covering system of k classes, every choice of a (or b) extends to a translated geometric progression {ar^n+b} with an admissible set of k primes, with the corollary that some {ar^n+b} has only composite members.
theorem_5: Porubský's theorem that for every N >= 0 there is a translated geometric progression {ar^n+b} containing at most N primes, proved by realizing a covering system with few singly covered residues.
theorem_6: Porubský's theorem that for every M >= 1 there is a translated geometric progression each of whose elements has at least M distinct prime factors, from a finite covering system covering every integer at least M times.
theorem_7: Porubský's theorem that the elements of any maximal set of coprime elements of a translated geometric progression have together at least as many distinct prime divisors as the smallest admissible set, with the corollary that an infinite coprime subprogression exists exactly when no finite admissible set does.
theorem_8: Porubský's theorem answering a question of LeVan: a translated geometric progression contains an infinite subprogression each of whose elements is coprime to all preceding elements of the progression if and only if it has no finite admissible set.
Štefan Porubský, Translated geometric progressions and covering systems, Časopis pro pěstování matematiky 103 (1978), no. 2, 141–146, DML-CZ entry, DOI.
A translated geometric progression is a set with integers , and ; a set of primes is admissible on it if every element has a prime factor in the set (printed p. 141). Lemma 5 (printed p. 142) shows that every finite covering system arises as the covering system attached to an admissible set on some translated geometric progression. The paper omits the proofs of Theorems 1–3 as immediate consequences of its lemmas (printed p. 143), and no proof was reconstructed or independently reviewed for this card.
The copy read for this card is the DML-CZ digitization, which has seven PDF pages: a DML-CZ front page with terms of use followed by the article's printed pages 141–146. Its first page identifies the DML-CZ project, and the PDF metadata identifies the DML-CZ TeX production; citations in the digest distinguish PDF pages from printed article pages. Its DML-CZ cover sheet prints "Terms of use: © Institute of Mathematics AS CR, 1978" and "provides access to digitized documents strictly for personal use. Each copy of any part of this document must contain these Terms of use.", every other right reserved.
Theorem 3 (printed p. 144) states that in every irredundant covering system of residue classes , each modulus satisfies for any prime dividing a modulus. The paper adds that the bound is attained for every by exactly covering systems described by Stein. Here irredundant means that no proper subsystem is itself covering (printed p. 142), and the moduli need not be distinct.
For Problem 1189, whose irreducible covering sets have distinct moduli and minimize over choices of residues, the two minimality notions should be kept distinct. A covering choice of residues for an irreducible covering set is an irredundant system, so Theorem 3 gives there; but the exactly covering system the paper prints on p. 144, () with , uses its largest modulus twice, and the paper's sharpness remark says nothing about distinct moduli.
Results.
- Lemma 5 (p. 142): every finite covering system is the system of an admissible set on some translated geometric progression.
- Theorem 1 (p. 143): for each prime dividing the least common multiple of the moduli of an irredundant covering system, the -power structure of the moduli and residues.
- Theorem 2 (p. 143): any two moduli of an irredundant covering system are joined by a chain of moduli with consecutive ones not coprime; its corollary is on p. 144.
- Theorem 3 (p. 144): every modulus of an irredundant covering system of classes is at most .
- Theorem 4 (p. 144): admissible sets of primes on from primitive prime factors of , with Corollaries 1 to 3 (pp. 144–145), among them progressions with only composite members.
- Theorem 5 (p. 145): for every a translated geometric progression with at most primes.
- Theorem 6 (p. 145): for every a translated geometric progression whose elements all have at least distinct prime factors.
- Theorem 7 (p. 145) and its corollary (p. 146): maximal coprime subprogressions and the least admissible set.
- Theorem 8 (p. 146): an infinite subprogression coprime to all preceding elements exists exactly when there is no finite admissible set.
Bears on. #1189: Theorem 3 (p. 144) bounds every modulus of an irredundant covering system of classes, moduli not required distinct, by , which bounds the largest modulus of an irreducible covering set of size by ; the paper treats neither distinct moduli nor the problem's other questions.
No file of this source is held: no license on record permits its redistribution, and the card cites the edition it names above.