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Cambie 2025 proving it is impossible erdos problem
Stijn Cambie, Proving it is impossible; on Erdős problem #278. arXiv preprint (2025). arXiv:2508.18270. The arXiv record (https://arxiv.org/abs/2508.18270, read 2026-10-02) names the Creative Commons Attribution 4.0 license. The copy read for this card is arXiv v1 (August 25, 2025); arXiv also lists a v2 (August 17, 2026), which was not compared.
This short note argues that the open half of Erdos problem 278, asking for the minimum density of integers left uncovered by congruences a_i mod n_i for given moduli, admits no single closed-form answer. Cambie takes moduli of the form {3} union {3p : p in P} and shows by the Chinese remainder theorem that the uncovered density is (1/3)(prod_{P_1}(1 - 1/p) + prod_{P_2}(1 - 1/p)) over partitions P = P_1 union P_2, so minimizing it is exactly a knapsack problem with weights -log(1 - 1/p) and bound -(1/2) sum_P log(1 - 1/p). Cambie then shows the answer depends sensitively on the small modulus and that the formula for pairwise gcd equal to a prime q depends on q, so different non-equivalent formulas arise for different structures of the moduli; and for a set of n very large primes whose weights differ by at most a factor of 2 Cambie builds integer weights from them that satisfy Chvatal's four conditions, so that the resulting knapsack instances are hard for recursive algorithms (Chvatal's Theorem 1). The argument is informal but real mathematics rather than a forum-only claim; the note also asserts, without separate argument, that greedy approaches do not solve the problem. It records that the complementary worst-case question (all a_i equal) was settled by Simpson. There are no numbered theorems in the paper.
Source: https://arxiv.org/abs/2508.18270.
Bears on. #278
Results to transcribe.
- Section 1: For moduli 3, 3p, 3p_3, ..., 3p_r the minimal uncovered density depends sensitively on p, so no single formula in n_1,...,n_r can express it.
- Formula for common prime gcd: If all n_i = q b_i with pairwise gcd q and the b_i primes forming the set P, the minimum uncovered density is (1/q) min over q-partitions of P of sum_j prod_{b in P_j} (1 - 1/b) - an expression depending on q and on this special structure.
- Knapsack reduction: Minimization reduces to a knapsack instance with weights -log(1 - 1/p). When P consists of n very large primes whose weights differ by at most a factor of 2, integer weights a_i = c floor(w_i x), plus 1 for the smaller half, satisfy Chvatal's four conditions (a)-(d), so by Chvatal's Theorem 1 the instance is hard for recursive algorithms (Section 2).