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Erdos 1967 problems prime factors consecutive integers
conjecture_p429: Erdős and Selfridge's unnumbered conjecture that for every k the limsup over n of the sum of nu(n+i) for 0 <= i <= k, multiplied by log log n / log n, equals 1, the value known for a single nu(n).
inequality_1: Erdős and Selfridge's deduction from Pólya's theorem that the liminf over n of the sum of nu(n+i) for 0 <= i <= k-1 is at least k + pi(k) - 1, with their conjecture (2) that it is at most k + pi(k).
remark_p430: Erdős and Selfridge's report of Schinzel's deduction from Pólya's theorem that, with possibly finitely many exceptions, every p_1...p_{k-1}p_{k+1} consecutive integers include one with more than k prime factors, and their question whether p_1...p_k suffices.
theorem_p428: Erdős and Selfridge's unnumbered result that some n + k has at least two prime factors exceeding k, that is v_0(n) > 1, for every positive integer n other than 1, 2, 3, 4, 7, 8 and 16.
P. Erdős, J. L. Selfridge, Some problems on the prime factors of consecutive integers. Illinois Journal of Mathematics 11 (1967), 428-430. The copy read for this card is an archive scan that prints no notice; the article's Project Euclid page could not be read on 2026-10-02, its Crossref record (DOI 10.1215/ijm/1256054564) names no license, and the publisher's journal page shows the footer "© 2024 Duke University Press. All Rights Reserved." and names no license (https://www.dukeupress.edu/illinois-journal-of-mathematics, read 2026-10-02), every other right reserved.
For a positive integer and , counts the primes dividing , which the paper restates as the prime factors of dividing no with , and (p. 428). The authors prove for every except , by reducing to and to exponential equations in powers of and , and say they are very far from proving . They introduce , say it seems certain that for every , and report that for 1-4, 6-8, 10, 12, 15, 16, 18, 22, 24, 26, 30, 36, 42, 46, 48, 60, 70, 78, 80, 96, 120, 190, 222, 330 and for no other , that is probably the largest solution, and that they cannot prove the solutions finite (p. 428).
On p. 429, counts the primes with and , and . The paper reports for 1-4, 6-8, 12, 15, 16, 24, 30, 48, 80 and no other , probably with the largest solution, though finiteness is unproved; from factor tables, for and for every other with . It puts , says seems probable but very difficult, notes that a result of Hardy and Ramanujan gives for almost all , and calls it not impossible that for every and . With the number of distinct prime factors of , it poses the limsup conjecture for , and states without proof two limsup results for and over consecutive integers (p. 429, with a footnote).
On p. 430 a theorem of Pólya on gaps between integers composed of primes up to gives inequality (1), , and the authors conjecture (2), the same liminf at most , perhaps with equality. The last paragraph reports Schinzel's deduction from Pólya's theorem that, with possibly finitely many exceptions, among any consecutive integers one has more than prime factors, suggests that may be the right value, and says that even for the authors cannot improve Schinzel's value.
Source: https://combinatorica.hu/~p_erdos/1967-21.pdf.
Results. Labels and pages are the print's.
- Theorem (p. 428, unnumbered; proof on p. 428): for every positive integer except .
- Conjecture (p. 429, unnumbered; posed, not proved): for every , .
- Inequality (1) (p. 430; derived from Pólya's theorem): $\liminf_n\sum_{i=0}^{k-1}\nu(n+i)\ge k+\pi(k)-1$, with the conjecture (2) that the liminf is at most .
- Remark (p. 430, unlabeled; reported without proof): Schinzel's interval length , and the question whether suffices.
Bears on.
- #889: the problem's question whether is stated as an expectation here (p. 428); the theorem gives only outside the seven listed values.
- #890: the problem's second question is the conjecture on p. 429, posed and not proved (the paper's sum runs over , the problem's over ); its first question, on prime factors exceeding , is not the paper's (2), which counts all distinct prime factors, and the derivation of inequality (1) gives only the lower bound for the problem's liminf.
- #891: the problem is the authors' question in the remark on p. 430, where Schinzel's reported result gives the longer length with possibly finitely many exceptions.
No file of this source is held: no license on record permits its redistribution, and the card cites the edition it names above.