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Source. Section 1° (formula (6), p. 513; the section runs pp. 512--513) of A. A. Gol'dberg, Sets on which the modulus of an entire function has a lower bound (Russian), Sibirsk. Mat. Zh. 20 (1979), no. 3, 512--518, 691, the edition named on the source card. The paper numbers its sections 1°, 2°, 3° and gives its results no theorem labels.
Statement
Setting (p. 512). For an entire function and , , is its planar (Lebesgue) measure, and . The problem the paper solves (Hayman's Problem 2.40) concerns entire functions that are not identically constant.
Result of 1° (formula (6), p. 513). Let be an entire function and let be such that . Then
where the paper takes the lower limit (p. 512). This is the convergence half of Hayman's conjecture; that it cannot be sharpened is section 2°.
Read depth. Claims checked: the statement, the setting and the steps (1)--(6) were read on the page images of pp. 512--513. The inequality (1) that the proof imports from Pfluger and Arima was not checked against their papers, and nothing here is independently reviewed.
Proof pointer
Pages 512--513, outlined here. Write for the circle , for the set of at which is not contained in , for , and for the length of the longest arc of when . The proof starts from the Carleman-type estimate (1), proved independently by Pfluger and by Arima: for , with a constant . Finite area of gives that has finite linear measure and that (2). By (1) it suffices to show that divided by is integrable at infinity. On each dyadic block , with and , the Cauchy--Bunyakovsky inequality and the lower bound for the block's measure bound the reciprocal of over the block by times over the block (steps (3)--(5)); summing over the blocks and using (2) gives (6).
Dependencies
Inequality (1), cited from A. Pfluger, Compt. Rend. Acad. Sci. 229 (1949), 542--543, and K. Arima, J. Math. Soc. Japan 4 (1952), 62--66; the paper notes (p. 512) that Pfluger does not write (1) explicitly and that it follows easily from the stronger inequality he proves.
Bears on
- Problem 1118: the problem's first question asks for the minimal growth of a non-constant entire for which has finite measure for some . This page gives the bound , which Hayman conjectured; section 2° shows it is best possible in the sense stated there. The paper states the question as Problem 2.40 of Hayman's list.