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Let with . Must there exist some with such that ?
Source: erdosproblems.com/806
An accepted solution exists. The statement is true.
Proved; the site labels the problem PROVED. Theorem 1.4 of Alon, Bukh and Sudakov [ABS09] (Israel J. Math. 174 (2009) 285--301, refereed; result page) shows that a group of order containing a non-doubling set of size between and satisfies the "EN-condition": every with has a basis with . Cyclic groups qualify (Corollary 1.5(a), solvable groups; or since an interval is non-doubling), and the paper's reduction (p. 3) lifts a basis to at the cost of a factor , so every with lies in for some with , for all sufficiently large . The order is sharp up to constants: Erdős and Newman [ErNe77] (J. Number Theory 9 (1977), refereed) state on p. 423 that most sets of type have , the site's lower bound, a remark they assert without proof and which [ABS09] (pp. 2--3) restates and carries to every finite group. The claim page is Alon, Bukh and Sudakov (accepted on the refereed publication and the site's credit).