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If is a graph which contains odd cycles of different lengths then , with equality if and only if contains .
Source: erdosproblems.com/58
An accepted solution exists. The statement is true.
The site labels the problem proved, crediting Gyárfás [Gy92]. The accepted claim is Gyárfás's bound with its equality case; the strengthening by Gao, Huo and Ma [GaHuMa21] is an accepted partial claim, consecutive odd cycle lengths, covering the inequality but not the equality case.