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Claim. Call a family of subsets of {1,…,n}\{1,\ldots,n\} admissible for rr when no member contains another and every size that occurs among its members occurs at least rr times, and let n0(r)n_0(r) be the least NN such that for every n>Nn>N some admissible family has exactly n−3n-3 distinct sizes. The manuscript states that

n0(r)=2r+4(4≤r≤10),n0(r)=2r+5(r≥11).n_0(r)=2r+4\quad(4\le r\le 10),\qquad n_0(r)=2r+5\quad(r\ge 11).

Together with the values n0(2)=3n_0(2)=3 and n0(3)=8n_0(3)=8 computed by He and Tang ([HeTa26b] on the problem page; the source card records them), this gives n0(r)n_0(r) for every r≥2r\ge2, which answers Problem 776 under either reading; the values sit inside He and Tang's bounds 2r+2≤n0(r)≤2r+2log⁡2r+O(log⁡log⁡r)2r+2\le n_0(r)\le 2r+2\log_2 r+O(\log\log r). As the forum entry describes the argument, the Kruskal–Katona theorem gives exact shadow constraints between consecutive size levels; for r≥11r\ge11, estimates on the low levels and an obstruction spanning four levels confine a carry ee to 1≤e≤61\le e\le6: the lower bound e≥1e\ge1 excludes an admissible family with n−3n-3 sizes at n=2r+5n=2r+5, and the upper bound e≤6e\le6 leaves a feasible core, which is punctured and then padded two points at a time to build families for every larger nn; for 4≤r≤104\le r\le10 the same constraints and constructions are verified by exact finite computation. The forum entry adds that the Lean development proves the set-family theorem for every r≥4r\ge4, with three bounded ranges closed by finite evaluation through soundness bridges proved in Lean.

Submission note. Posted to erdosproblems.com as a proof claim by AI's operated by M.Thiim (account mthiim) on 17 July 2026, giving "All ideas and lean formalization due to LLM's - exact contribution of each is specified in submission package. LLM's used: OpenAI ChatGPT 5.6 Pro, Anthropic Claude Fable 5, OpenAI Codex w gpt-5.6-Sol-Max" as the AI used:

Erdős #776 asks when subsets of [n][n] can occupy n−3n-3 sizes, with no set contained in another and at least rr sets at each occupied size. Let n0(r)n_0(r) be the least NN working for every n>Nn>N. We prove n0(r)=2r+4n_0(r)=2r+4 for $4\le r\le10$ and n0(r)=2r+5n_0(r)=2r+5 for r≥11r\ge11. Combining with n0(2)=3n_0(2)=3 and n0(3)=8n_0(3)=8, due to Yixin He and Quanyu Tang (as discussed in forum), this completes the table for r≥2r\ge2 with exact proven values. Kruskal--Katona gives exact shadow constraints between successive size levels. For r≥11r\ge11, lower-level estimates and a four-level obstruction give a carry 1≤e≤61\le e\le6. Here e≥1e\ge1 rules out n=2r+5n=2r+5, while e≤6e\le6 yields a feasible core; puncturing and repeated two-point padding then construct examples for every larger nn. The cases 4≤r≤104\le r\le10 use exact finite checks of the same constraints and constructions. Lean proves the full set-family theorem for r≥4r\ge4; only three bounded ranges use finite evaluation, through proved soundness bridges. Notes: Whole proof package can be found on Github. This includes a README.md that serves as a useful entropy pint for the problem statement, links to paper, notes that can be useful to validating the proof and the lean formalization: https://github.com/mthiim/erdos_776/. Tag: v0.4.1-proof-claim, commit hash: 1ca43203123642edaac45bf00b6fc333c848b4c9

Depends on. [[problems/set_systems/E0776/claims/2026_02_10_he_tang|He and Tang's thresholds at r equal to 2 and 3]]: the values n0(2)=3n_0(2)=3 and n0(3)=8n_0(3)=8, which the manuscript cites and its Lean development does not formalize, so the table for every r≥2r\ge2 is complete only with that pending claim.

Claimant. M. Thiim, posting under the username mthiim on 17 July 2026, who presents the result as the work of language models they operated (OpenAI ChatGPT 5.6 Pro, Anthropic Claude Fable 5, and OpenAI Codex with gpt-5.6-Sol-Max), with the contribution of each recorded in the repository's credits file; the page is named for the human submitter, who published the claim. The manuscript is the PDF in the repository at the claim's tag.

Formalization. The repository at the claim's tag (the pinned commit above) declares a Lean proof of the set-family theorem for every r≥4r\ge4, with n0(r)n_0(r) stated as genuine leastness. Its README reports that the ranges 4≤r≤104\le r\le10, 11≤r≤2811\le r\le28 and 29≤r≤37729\le r\le377 are closed by native_decide evaluations tied to the combinatorial statements by soundness bridges proved in Lean, that the range r≥378r\ge378 is proved symbolically, and that no source uses sorry or a project axiom; the complete endpoints additionally carry the three native_decide certificate axioms, trusting Lean's compiler, while only the symbolic r≥378r\ge378 endpoint rests on the standard axioms alone. The values for r=2,3r=2,3 are not part of that development and rest on He and Tang's computation.

Acceptance. None that counts as evidence. The manuscript is not refereed, and the site labels the problem OPEN (page last edited 10 April 2026) and does not credit this result. The forum thread carries three comments: on 21 July 2026 a forum user reported an independent check, building the Lean project from a cold cache with no errors and no sorry, reproducing the axiom audit, reading the statement file against the site's wording, re-implementing the Kruskal–Katona cascade to reproduce the boundary numbers and checking the stored r=11r=11 certificate, and said the check convinced them; the claimant replied the same day; a comment of 19 August 2026 asked whether anyone had read the human-readable PDF. A pseudonymous forum check is not a named outside reviewer, so no reviewed evidence is listed, and no Lean audited by the corpus checks the result, so no formalized evidence is listed. A further replication, posted in the problem's thread on 6 September 2026, rederives the cases r=5r=5, 66 and 1111 with Lean lemmas that import this development; it is recorded on the problem page and is not outside evidence either. The partial claim Ronen's value n_0(4)=12 agrees with this result at r=4r=4.