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Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

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Claim. The answer to both questions of Problem 1193 is no, as the statement stands. Take A=NA=\mathbb N with 0∈N0\in\mathbb N and g(n)=n+1g(n)=n+1. Then 1A∗1A(n)1_A\ast1_A(n), the number of ordered pairs (a,b)∈A2(a,b)\in A^2 with a+b=na+b=n, equals n+1n+1 for every nn; gg is non-decreasing and positive; and the set {n:1A∗1A(n)=g(n)}\{n:1_A\ast1_A(n)=g(n)\} is all of N\mathbb N, so its lower density is 11, not 00, and its upper density is 11, not below any constant c<1c<1. Both conjectured bounds are refuted as stated. The counterexample needs no restriction on AA or gg beyond those the statement imposes. If 0∉N0\notin\mathbb N, the count is n−1n-1 for n≥2n\ge2 and 00 at n=1n=1, and g(n)=max⁡(n−1,1)g(n)=\max(n-1,1) gives the same conclusion, an observation made here. Erdős presumably intended further restrictions on gg or on AA; the site's commentary notes that [Er80] records none.

Submission note. Posted to the site's forum by Pietro Monticone on 13 April 2026:

Trivially autoformalised by Aristotle here.

(The site has been updated to address this comment.)

Depends on. Nothing in this wiki.

Postings. Pietro Monticone posted the counterexample on the site's discussion thread on 2026-04-13 as a Lean file produced with Aristotle (Harmonic's system), linked through the Lean web editor at the gist pinned above; the thread note says the site was updated in response. The same file, with its theorem renamed not_erdos_1193 and the original name kept as an alias, entered Boris Alexeev's lean-proofs repository on 2026-05-06 (src/latest/ErdosProblems/Erdos1193.lean, Lean v4.33.0 and Mathlib v4.33.0 at the pinned commit of 2026-09-15), with a record page added on 2026-07-27. The module defines conv_ind A n as the number of k∈{0,…,n}k\in\{0,\ldots,n\} with k∈Ak\in A and n−k∈An-k\in A and proves conv_ind Set.univ n = n + 1 for every n by simp; its comment records the axioms propext, Classical.choice and Quot.sound. That statement is the counterexample identity, not the two density questions themselves.

Acceptance. Reviewed: the site's curator, Thomas Bloom, adopted the counterexample. The problem's commentary states that both questions have the answer no with no work needed, gives A=NA=\mathbb N with 1A∗1A(n)=n+11_A\ast1_A(n)=n+1, and presumes unrecorded restrictions in [Er80]; the page is labeled SOLVED (LEAN), the thread carries no proof claim, and the community database (teorth/erdosproblems) records the problem solved with formal status Lean. Not refereed: there is no publication. Not listed as formalized: nothing was built, replayed or audited by this project, and the catalog's statement file (google-deepmind/formal-conjectures, ErdosProblems/1193.lean) states both parts with answer(False) and a variant sumRep_univ pointing to the lean-proofs copy as its formal proof, each with a sorry body in the catalog file itself.