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Claim. For each 1≤i≤41\le i\le4 there is a constant CiC_i such that for n≡i(mod4)n\equiv i\pmod4

fm(n)=(Ci+o(1)) 2n/4,f_m(n)=(C_i+o(1))\,2^{n/4},

where fm(n)f_m(n) counts the maximal sum-free subsets of {1,…,n}\{1,\ldots,n\} as in Problem 877. This is the exact order of fm(n)f_m(n), so it settles the estimate the problem asks for and, a fortiori, answers the displayed question fm(n)=o(2n/2)f_m(n)=o(2^{n/2}) yes. The source is Theorem 1.1 of J. Balogh, H. Liu, M. Sharifzadeh and A. Treglown, Sharp bound on the number of maximal sum-free subsets of integers, J. Eur. Math. Soc. 20 (2018), no. 8, 1885--1911, cited as [BLST18] on the problem page and cited from the arXiv version, with its result page on the library card. The paper says that each CiC_i can be computed to any additive error in constant time and gives no closed form; its structural statement is that almost all maximal sum-free subsets of {1,…,n}\{1,\ldots,n\} look like one of two extremal constructions. The proof is unread. The result sharpens the same authors' exponent 1/41/4 on its own page.

Depends on. No wiki page; the claim rests on the cited paper.

Acceptance. Refereed: the paper is a research article in the Journal of the European Mathematical Society (Crossref record read: volume 20, issue 8, published 4 June 2018); the text cited is arXiv:1502.07605v2 of 11 May 2018, whose comment says the paper is to appear there, and the journal text was not compared; the page is named by the first arXiv version, submitted 26 February 2015 (arXiv listing read). Reviewed: the site's curator, Thomas Bloom, marks the problem proved on erdosproblems.com and credits the four authors with this asymptotic, its constant determined by the residue of nn modulo 44. Read status: the statement checked, the proof unread; no further evidence is listed.