Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
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Nešetřil and Rödl's Theorem 2 shows that for every integer there is a sequence , a set in which every has at most representations with , counted without regard to order and with allowed (the definition on p. 186 does not exclude , and the case count on p. 187 counts each unordered pair once), and some has exactly , such that in every partition of into finitely many parts some part is again a sequence; the number of parts may depend on as well as on . With $C = k$ no part has fewer than representations of every , so the answer to the question of Erdős and Newman is no for every integer under that unordered count. The corrected Statement of Problem 328 takes Erdős and Graham's count, which excludes ; their book (1980, p. 49) reports that Nešetřil and Rödl showed the answer to the question, as stated with that count, to be negative for all , and the site's curator credits them with the same answer for all . The page values the result against the corrected Statement on that report. The case is trivial, and for non-integer the hypothesis already gives fewer than representations of every , so the partition into one part works. Erdős had earlier proved the same for $C = 2$, , every and every , by Ramsey's theorem, in the paper whose source card is Erdős 1980 and recorded on its own claim page; the note added in proof there records Nešetřil and Rödl's proof of the conjecture for every . The source is J. Nešetřil and V. Rödl, Two proofs in combinatorial number theory, Proceedings of the American Mathematical Society 93 (1985), no. 1, 185–188, in the January 1985 issue; the page is dated to that month because no publication day is recorded. The statement above is Theorem 2 of the published paper, whose proof counts each unordered representation once, and its proof is not checked in this corpus.
Acceptance. Refereed: Proceedings of the American Mathematical Society 93 (1985), no. 1, 185–188, the DOI linked above. Reviewed: the site's curator, Thomas Bloom, labels the problem DISPROVED (LEAN) and credits Nešetřil and Rödl in the problem's commentary with showing that the answer is no for all , even if may depend on (page last edited 6 April 2026). The site's Lean mark refers to a separate public Lean refutation of the site's ordered-count wording, which settles no instance of the corrected Statement and is recorded on its own, rejected, claim page.