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For every fixed sufficiently small δ>0\delta>0 and all sufficiently large nn, at least (1−2δ)n(1-2\delta)n integers in [n][n] are n1−δn^{1-\delta}-powersmooth.

In particular, for fixed sufficiently small ε>0\varepsilon>0 and Q=n1−ε/2Q=n^{1-\varepsilon}/2, at least (1−4ε)n(1-4\varepsilon)n integers in [n][n] are QQ-powersmooth for sufficiently large nn.

Source: published PDF, Lemma 5, p. 9. The first-minimal-power grouping makes the printed exception estimate explicit; this step is valid in the source. The second deduction uses δ=2ε\delta=2\varepsilon, rather than silently discarding the factor 1/21/2 in QQ.

Bears on. Problem 297.

Proof

Put t=n1−δt=n^{1-\delta}. The near-one Dickman estimate gives (1+log⁡(1−δ)+oδ(1))n(1+\log(1-\delta)+o_\delta(1))n tt-smooth integers. For 0<δ≤1/40<\delta\le1/4, −log⁡(1−δ)≤δ/(1−δ)≤4δ/3-\log(1-\delta)\le\delta/(1-\delta)\le4\delta/3. There are consequently at least (1−3δ/2)n(1-3\delta/2)n such integers for large nn.

If one is not tt-powersmooth, some prime p≤tp\le t has a power dividing it that exceeds tt. For each such pp, choose the least exponent a(p)a(p) with pa(p)>tp^{a(p)}>t. All exceptional integers associated with pp are divisible by this single minimal power, including those having higher powers. Their number is at most ⌊n/pa(p)⌋≤⌊n/t⌋\lfloor n/p^{a(p)}\rfloor\le\lfloor n/t\rfloor. The union bound over the primes gives at most

π(t)⌊n/t⌋≤n π(t)/t=o(n)\pi(t)\lfloor n/t\rfloor\le n\,\pi(t)/t=o(n)

exceptions, by the prime number theorem. For large nn this is at most δn/2\delta n/2. Subtracting proves the first assertion.

For the second, Q≥n1−2εQ\ge n^{1-2\varepsilon} once nε≥2n^\varepsilon\ge2. An integer that is n1−2εn^{1-2\varepsilon}-powersmooth is therefore QQ-powersmooth. Apply the first assertion with δ=2ε\delta=2\varepsilon.