Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
Updated
Statement
For let be the least possible value of over all expansions
and let . Theorem 1 (p. 158): "If is a prime then , where is the least integer not less than ."
The inequality is not strict as printed. The site's commentary for Problem 305 quotes it as .
Source. M. N. Bleicher and P. Erdős, Denominators of Egyptian fractions, J. Number Theory 8 (1976), 157--168; Theorem 1 on printed p. 158 (PDF p. 2), proof on p. 158. The copy read is a scan whose text layer garbles formulas; the statement was read on the page image.
Read depth. Claims checked: the statement and the definition of and (p. 158; the Egyptian form, p. 157) were read clause by clause on the page images. The proof was not checked.
Proof pointer
The proof on p. 158 tracks, in an expansion of with least possible largest denominator, the denominators that are divisible by ; it is not reconstructed here. The authors add on p. 158: "There is both theoretical and computational evidence to indicate that is maximum when is a prime." The closing pages tabulate for the primes up to (p. 165).
Dependencies
None outside the paper.
Bears on
- Problem 305: the lower bound shows that the exponent of in the question cannot be lowered.