Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
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Statement
Let (display (1), p. 1), the set of values of sums of distinct unit fractions with denominators at most , the empty sum included; so is the of Problem 320. Write for the -th iterate of the natural logarithm.
Theorem 1 (p. 2). Let and be positive integers. In each case below whose condition holds,
The abstract writes the third case as , the same bound. The proof (p. 9) gives the constant in place of .
Source. S. Bettin, L. Grenié, G. Molteni and C. Sanna, A lower bound for the number of Egyptian fractions, arXiv:2509.10030v1 (12 September 2025; the only arXiv version listed on 2026-09-18), 12 pages; Theorem 1 on p. 2 (page image), the definition (1) on p. 1, the proof in Section 2, pp. 3--9 (text layer). Published in Mathematics of Computation, DOI 10.1090/mcom/4190, online 22 January 2026 (Crossref record read; the record gives no volume or pages yet); the published text was not compared, and the locators here are v1 locators.
Read depth. Claims checked: Theorem 1, the definition of and Lemmas 1 and 2 were read clause by clause. The proof was read for structure (below) and is not verified here.
Proof pointer and sketch (Section 2)
Let be the set of such that for all , and . Lemma 1: if and only if (the union is disjoint exactly then). Lemma 2: . Lemma 4: if and is a prime compatible with (in particular ), then for every ; Lemma 5 lists explicitly. Lemma 7 turns this into the integral recursion for , , which Lemmas 8--10 iterate through the functions , , and ; the proof ends (p. 9) with for , obtained as a lower bound for and then Lemma 2. The first two cases come from Lemma 2 with Lemma 6's bounds () and the case of Lemma 8.
The paper compares its bound with Bleicher and Erdős's: their 1976 Theorems 2 and 3 give with for , and their 1975 Corollaries 1--3 raise to under (p. 1); relaxing the condition to admits larger and so improves the order of growth, not only the constant (p. 2). Section 3 computes exactly for (Table 2), extending OEIS A072207's values for .
Relation to Problem 321
The set has all its subset reciprocal sums distinct: if two
distinct subsets of had equal reciprocal sums, one
could drop their common elements and take the largest remaining element ,
say ; then would equal a -combination of the
with , contradicting . So, in the notation of
Problem 321, , and the proof's lower bound for
gives
for and . The paper does not state this consequence;
the site's Problem 321 page calls the lower bound "implicit" in the paper and
the proof claim accepted there attributes it to "the dissociated set
constructed in" the paper. The three-line argument above is written for that
page and is not taken from a source; the accepted claim's Lean file proves
the same finite statement (BGMSU_dissociated,
pow_card_BGMSU_le_harmonic_subsetSums), as the problem page records.
Dependencies
Rosser's explicit bound for (the paper's [8], p. 228, giving in the proof of Lemma 3); Rosser and Schoenfeld's explicit bounds for (the paper's [9]: Th. 1 in Lemma 3, and Th. 2, Cor. 1 in Lemmas 6 and 7); Lemma 5's explicit list, checked by the authors.
Bears on
- Problem 320: the best refereed lower bound for , matched in order by the site-accepted upper bound of July 2026.
- Problem 321: the lower bound for through the dissociated set , as above.