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Statement

Setting (p. 125). For a positive integer rr, n(r)n(r) is the least size of a family of rr-sets, any two of which intersect, such that every set of size r−1r-1 is disjoint from at least one member; in hypergraph language,

n(r)=min⁡{∣H∣:H an r-uniform, intersecting hypergraph with τ(H)=r},n(r)=\min\{|\mathcal H|:\mathcal H\text{ an $r$-uniform, intersecting hypergraph with }\tau(\mathcal H)=r\},

where the cover number τ(H)\tau(\mathcal H) is the least size of a set meeting every member of H\mathcal H.

Theorem (p. 126, unnumbered; displays (5)--(7)). There is a fixed prime power KK with the following property. For every sufficiently large t∈Nt\in\mathbf N and every prime power q≡3(mod4)q\equiv3\pmod 4 with

q<t≤(1+K−2)q,q<t\le(1+K^{-2})q,

if r=Kq+tr=Kq+t, then

n(r)≤5(K2+K)t.n(r)\le5(K^2+K)t.

The paper then states "Since all sufficiently large rr's are of the form (6), (1) follows", where (6) is r=Kq+tr=Kq+t and (1) is n(r)=O(r)n(r)=O(r). It gives no further argument for that step; a prime q≡3(mod4)q\equiv3\pmod4 with r/(K+1+K−2)≤q<r/(K+1)r/(K+1+K^{-2})\le q<r/(K+1) exists for every large rr by the prime number theorem for arithmetic progressions, and t=r−Kqt=r-Kq then satisfies the range above (this remark is the corpus's, not the paper's). Since r/(K+1)<t≤(1+K−2)r/(K+1+K−2)r/(K+1)<t\le(1+K^{-2})r/(K+1+K^{-2}), the bound is about 5Kr5Kr, and the paper puts the constant at "about 5K5K". It makes no attempt to evaluate KK (p. 126); KK is fixed large enough for Lemma 2.1 and the inequalities of section 4 (p. 128), and t>t(K+1)t>t(K+1), the threshold of Theorem 2.2 (p. 129). The abstract (p. 143) states the result as a linear upper bound on n(r)n(r) settling the problem of Erdős and Lovász.

Source. J. Kahn, On a problem of Erdős and Lovász. II: n(r)=O(r)n(r)=O(r), J. Amer. Math. Soc. 7 (1994), no. 1, 125--143, read in the edition identified on the source card: the definition on p. 125, the theorem and the dual reformulation on p. 126, section 2 on pp. 127--132, the abstract on p. 143.

Read depth. Claims checked: the statement and the hypotheses on KK, qq and tt were read clause by clause on the page images; the construction was read for its outline and the proof was not checked. Nothing here is independently reviewed.

Proof pointer

Pp. 126--132 and sections 3--4. The examples are built in dual form (p. 126): section 2 (pp. 127--132) constructs an rr-regular hypergraph H\mathcal H on 5(K2+K)t5(K^2+K)t vertices in which every two vertices lie in a common edge (display (8)) and whose edge cover number is rr. Its dual is an rr-uniform intersecting hypergraph of size 5(K2+K)t5(K^2+K)t with cover number rr, which gives the bound. The construction combines 55-regular expander-like bipartite graphs, a projective plane of order KK with, for each line ll, a labelling σl:l→{1,2}\sigma_l:l\to\{1,2\} of its points satisfying conditions (I) and (II), which a random choice gives (Lemma 2.1), a transversal design TD(K,t)\mathrm{TD}(K,t) (Theorem 2.2) and a projective plane of order qq. That the edge cover number is rr is the content of Theorem 2.3.

Depends on. Theorem 2.3 (p. 131); Lemma 2.1 (p. 128), proved in section 3 except for its condition (I), which the paper calls a standard calculation and omits (p. 132); and Theorem 2.2 (p. 129), the transversal-design form of the theorem of Chowla, Erdős and Straus, for which the paper cites Wilson 1974.

Bears on

  • Problem 21: the problem's f(n)f(n) is the paper's n(r)n(r), and it asks whether f(n)≪nf(n)\ll n. The theorem, with the step above from the form r=Kq+tr=Kq+t to all large rr, gives n(r)=O(r)n(r)=O(r), the inequality the problem asks for.