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Source. Published p. 267, Theorem 2.2 (PDF).

Statement. If 0<κ<1/20<\kappa<1/2 and all cross intersections of A,B⊆2X\mathcal A,\mathcal B\subseteq2^X have size less than (1/2−κ)n(1/2-\kappa)n, then, for 0≤λ<κ0\le\lambda<\kappa,

∣A∣∣B∣≤max⁡{2n+nH(1/2−λ)+1,22nH((1+κ−λ)/2)+2}.(1)|\mathcal A||\mathcal B| \le\max\left\{ 2^{n+nH(1/2-\lambda)+1}, 2^{2nH((1+\kappa-\lambda)/2)+2} \right\}. \tag{1}

In particular, for fixed κ>0\kappa>0 the normalized product is at most e−cne^{-cn} for some c>0c>0 and all sufficiently large nn.

Proof. Let A0\mathcal A_0 consist of the members of size at most (1/2−λ)n(1/2-\lambda)n. The binomial-tail estimate bounds its size by 2nH(1/2−λ)2^{nH(1/2-\lambda)}. If it contains half of A\mathcal A, multiply by the trivial bound ∣B∣≤2n|\mathcal B|\le2^n to obtain the first term of (1). The same argument applies to B\mathcal B.

Otherwise, retain the larger members A∗,B∗\mathcal A^*,\mathcal B^*, each comprising at least half its family. For A∈A∗A\in\mathcal A^* and C=X−BC=X-B with B∈B∗B\in\mathcal B^*,

∣A∩C∣=∣A∣−∣A∩B∣>(κ−λ)n.|A\cap C|=|A|-|A\cap B|>(\kappa-\lambda)n.

Apply theorem_2_1 to A∗\mathcal A^* and the complements of B∗\mathcal B^*. The factor four for the two deletions gives the second term of (1). Finally choose λ=κ/2\lambda=\kappa/2; both entropy exponents in (1) are strictly below 2n2n, and the fixed factors can be absorbed for sufficiently large nn. □\square

Dependencies. theorem_2_1, entropy_estimates.